1.用一條SQL語句 查詢出每門課都大于80分的學生姓名 ?

name?? kecheng?? fenshu
張三???? 語文?????? 81
張三???? 數學?????? 75
李四???? 語文?????? 76
李四???? 數學?????? 90
王五???? 語文?????? 81
王五???? 數學?????? 100
王五???? 英語?????? 90

A: select distinct name from table? where? name not in (select distinct name from table where fenshu<=80)


2.一道SQL語句面試題，關于group by
表內容：
2005-05-09 勝
2005-05-09 勝
2005-05-09 負
2005-05-09 負
2005-05-10 勝
2005-05-10 負
2005-05-10 負

如果要生成下列結果, 該如何寫sql語句?

??????????? 勝 負
2005-05-09 2 2
2005-05-10 1 2
------------------------------------------
使用函數連接：
SELECT rq,SUM(CASE? WHEN shengfu='勝' THEN 1 ELSE 0 END) 勝,SUM(CASE WHEN shengfu='負' THEN 1 ELSE 0 END) 負 FROM tmp GROUP BY rq;
外連接：
SELECT n.rq,n.勝,m.負 FROM (SELECT rq,COUNT(*) 勝 FROM tmp WHERE shengfu='勝' GROUP BY rq) n INNER JOIN (SELECT rq,COUNT(*) 負 FROM tmp WHERE shengfu='負' GROUP BY rq) m ON n.rq=m.rq;
自連接：
SELECT a.rq, a.a1 勝,b.b1 負 FROM
(SELECT rq,COUNT(rq) a1 FROM tmp WHERE shengfu='勝' GROUP BY rq)a,
(SELECT rq,COUNT(rq) b1 FROM tmp WHERE shengfu='負' GROUP BY rq)b
?WHERE a.rq=b.rq;
?

一個表中的Id有多個記錄，把所有這個id的記錄查出來，并顯示共有多少條記錄數。
------------------------------------------
select id, Count（*) from tb group by id having count(*)>1
select * from(select count(ID) as count from table group by ID)T where T.count>1





SQL資料：和我們在課堂上所學的較大的不同在于：子查詢的位置非常靈活，可以出現在from子句后（需要為此查詢取別名），
也可以出現在select的目標列中，請仔細讀懂下列例子（有的地方取別名直接就空格后出現別名，有的地方是用as后面跟別名的方式）。
注：主要是學習基本語句或短語的用法

Student(S#,Sname,Sage,Ssex) 學生表
Course(C#,Cname,T#) 課程表
SC(S#,C#,score) 成績表
Teacher(T#,Tname) 教師表

問題：
1、查詢“001”課程比“002”課程成績高的所有學生的學號；
select a.S#
from (select s#,score from SC where C#=’001′) a,
(select s#,score from SC where C#=’002′) b
where a.score>b.score and a.s#=b.s#;

2、查詢平均成績大于60分的同學的學號和平均成績；
select S#,avg(score)
from sc
group by S# having avg(score) >60;

3、查詢所有同學的學號、姓名、選課數、總成績；
select Student.S#,Student.Sname,count(SC.C#),sum(score)
from Student left Outer join SC on Student.S#=SC.S#
group by Student.S#,Sname

4、查詢姓“李”的老師的個數；
select count(distinct(Tname))
from Teacher
where Tname like ‘李%’;

5、查詢沒學過“葉平”老師課的同學的學號、姓名；
select Student.S#,Student.Sname
from Student
where S# not in (select distinct( SC.S#) from SC,Course,Teacher where SC.C#=Course.C# and Teacher.T#=Course.T# and Teacher.Tname=’葉平’);

6、查詢學過“001”并且也學過編號“002”課程的同學的學號、姓名；
select Student.S#,Student.Sname
from Student,SC
where Student.S#=SC.S# and SC.C#=’001′and exists( Select * from SC as SC_2 where SC_2.S#=SC.S# and SC_2.C#=’002′);
7、查詢學過“葉平”老師所教的所有課的同學的學號、姓名；
select S#,Sname
from Student
where S# in
(select S# from SC ,Course ,Teacher
where SC.C#=Course.C# and Teacher.T#=Course.T# and Teacher.Tname=’葉平’ group by S# having count(SC.C#)=(select count(C#)
from Course,Teacher where Teacher.T#=Course.T# and Tname=’葉平’));

8、查詢所有課程成績小于60分的同學的學號、姓名；
select S#,Sname
from Student
where S# not in (select Student.S# from Student,SC where S.S#=SC.S# and score>60);

9、查詢沒有學全所有課的同學的學號、姓名；
select Student.S#,Student.Sname
from Student,SC
where Student.S#=SC.S#
group by Student.S#,Student.Sname having count(C#) <(select count(C#) from Course);

10、查詢至少有一門課與學號為“1001”的同學所學相同的同學的學號和姓名；
select S#,Sname
from Student,SC
where Student.S#=SC.S# and C# in （select C# from SC where S#='1001'）;

11、刪除學習“葉平”老師課的SC表記錄；
Delect SC
from course ,Teacher
where Course.C#=SC.C# and Course.T#= Teacher.T# and Tname='葉平';

12、查詢各科成績最高和最低的分：以如下形式顯示：課程ID，最高分，最低分
SELECT L.C# 課程ID,L.score 最高分,R.score 最低分
FROM SC L ,SC R
WHERE L.C# = R.C#
and
L.score = (SELECT MAX(IL.score)
FROM SC IL,Student IM
WHERE IL.C# = L.C# and IM.S#=IL.S#
GROUP BY IL.C#)
and
R.Score = (SELECT MIN(IR.score)
FROM SC IR
WHERE IR.C# = R.C#
GROUP BY IR.C# );

13、查詢學生平均成績及其名次
SELECT 1+(SELECT COUNT( distinct 平均成績)
FROM (SELECT S#,AVG(score) 平均成績
FROM SC
GROUP BY S# ) T1
WHERE 平均成績 > T2.平均成績) 名次, S# 學生學號,平均成績
FROM (SELECT S#,AVG(score) 平均成績 FROM SC GROUP BY S# ) T2
ORDER BY 平均成績 desc;

14、查詢各科成績前三名的記錄:(考慮成績并列情況)
SELECT t1.S# as 學生ID,t1.C# as 課程ID,Score as 分數
FROM SC t1
WHERE score IN (SELECT TOP 3 score
FROM
(select distinct score from SC order) by score desc)
ORDER BY t1.C#;

(2)、查詢各科成績前三名的記錄:(bu考慮成績并列情況)
SELECT t1.S# as 學生ID,t1.C# as 課程ID,Score as 分數
FROM SC t1
WHERE score IN (SELECT TOP 3 score
FROM SC
WHERE t1.C#= C#
ORDER BY score DESC)
ORDER BY t1.C#;

15、查詢每門功成績最好的前兩名
SELECT t1.S# as 學生ID,t1.C# as 課程ID,Score as 分數
FROM SC t1
WHERE score IN (SELECT TOP 2 score
FROM SC
WHERE t1.C#= C#
ORDER BY score DESC )
ORDER BY t1.C#;

補充：
已經知道原表
year salary
——————
2000 1000
2001 2000
2002 3000
2003 4000

解：
select b.year,sum(a.salary)
from salary a,salary b
where a.year<=b.year
group by b.year
order by b.year;

在面試過程中多次碰到一道SQL查詢的題目，查詢A(ID,Name)表中第31至40條記錄，ID作為主鍵可能是不是連續增長的列，完整的查詢語句如下：
方法一：
select top 10 *
from A
where ID >(select max(ID) from (select top 30 ID from A order by ID ) T) order by ID
方法二：
select top 10 *
from A
where ID not In (select top 30 ID from A order by ID)
order by ID

轉載于:https://www.cnblogs.com/wcyBlog/p/3820652.html

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