I have a list, sometimes it is nested, sometimes it is not. Based whether it is nested, the continuation is different. How do I check if this list is nested? True or False should be output.

example:

[1,2,3] --> False

[[1],[2],[3]] --> True

解決方案

You can use isinstance and a generator expression combined with any. This will check for instances of a list object within your original, outer list.

In [11]: a = [1, 2, 3]

In [12]: b = [[1], [2], [3]]

In [13]: any(isinstance(i, list) for i in a)

Out[13]: False

In [14]: any(isinstance(i, list) for i in b)

Out[14]: True

Note that any will return True as soon as it reaches an element that is valid (in this case if the element is a list) so you don't end up iterating over the whole outer list unnecessarily.

《新程序員》：云原生和全面數字化實踐50位技術專家共同創作，文字、視頻、音頻交互閱讀

總結

以上是生活随笔為你收集整理的python列表的嵌套,Python检查列表是否嵌套的全部內容，希望文章能夠幫你解決所遇到的問題。

如果覺得生活随笔網站內容還不錯，歡迎將生活随笔推薦給好友。