要求如下：

可以生成具有特定圓心、半徑的圓對象

提供可以設置成員變量的方法

計算一個點（Point）對象是否在圓（Circle）對象內

源代碼如下：

import java.util.Scanner;class Point{//Point點類，用于確定一個點的坐標double x;//x坐標double y;//y坐標public Point(double x,double y) {this.x = x;this.y = y;}void showPoint() {//顯示點的坐標System.out.print("點的坐標為： ");System.out.println("(" + x + "," + y + ")");} }public class Circle {//Circle圓類，用于確定一個圓private double radius;//圓的半徑private Point point;//為類Point定義對象point作為圓的圓心坐標public Circle(Point point,double radius) {this.point = point;this.radius = radius;}void showCircle(){//顯示圓的圓心坐標和半徑System.out.print("圓心坐標為： ");System.out.println("(" + point.x + "," + point.y + ")");System.out.print("圓的半徑為： ");System.out.println(radius);}void judgement(Point a,Circle b){//判斷點與圓的關系（包括圓外、圓上、圓內）if((a.x-point.x)*(a.x-point.x)+(a.y-point.y)*(a.y-point.y)>(b.radius*b.radius))System.out.print("點在圓外！");else if((a.x-point.x)*(a.x-point.x)+(a.y-point.y)*(a.y-point.y)==(b.radius*b.radius))System.out.print("點在圓上！");else if((a.x-point.x)*(a.x-point.x)+(a.y-point.y)*(a.y-point.y)<(b.radius*b.radius))System.out.print("點在圓內！");} public static void main(String[] args) {// TODO Auto-generated method stubScanner in = new Scanner(System.in);//鍵盤輸入System.out.print("請輸入點的坐標（x坐標、y坐標） ： ");//輸入提示語Point point1 = new Point(in.nextDouble(),in.nextDouble());//點的坐標System.out.print("請輸入圓的坐標（x坐標、y坐標、半徑）： ");//輸入提示語Point point2 = new Point(in.nextDouble(),in.nextDouble());//圓心坐標Circle circle1 = new Circle(point2,in.nextDouble());point1.showPoint();circle1.showCircle();circle1.judgement(point1, circle1);in.close();}}

總結

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