java中rpn_java – RPNCalculator代码混淆
好.開始了.我已經修改了你的程序了一點點.以下是修改程序時出現的問題.
1.任何類中都沒有“writeOutput()方法.因此我不得不刪除那段代碼.
2.必須引入while循環才能使其成為迭代過程.
3.在讀取運算符字符串后向下移動operator.charAt(0)方法.
由于您使用的是switch語句,因此無法將運算符值與“nCr”字符串值進行比較.要使用此方法,您必須使用equals()方法使用字符串比較.
最后但并非最不重要的是,操作的結果應該是下一輪計算的輸入之一.意味著第一個操作的結果將被傳遞到下一個操作的第一個參數.
import java.util.Scanner;
public class RPNCalc
{
public static void main(String[]args)
{
Scanner keyboard = new Scanner(System.in);
double v1, v2;
// String operator = keyboard.nextLine();
// char symbol = operator.charAt(0);
char operator = ' ';//First time around, set this to an something other than 'q'
String operatorString = " ";
System.out.print("Enter a value v1: ");
v1 = keyboard.nextDouble();
System.out.println();
while(operator != 'q')
{
System.out.print("Enter a value v2: ");
v2 = keyboard.nextDouble();
System.out.println();
System.out.print("Enter one of the valid operators +, -, *, /, nCr,: ");
operatorString = keyboard.next();//nextLine() doesn't wait until the user hit enter
operator = operatorString.charAt(0);
switch (operator)
{
case'+':
v1 = sum(v1, v2);
System.out.println(v1);
break;
case'-':
v1 = minus(v1, v2);
System.out.println(v1);
break;
case'*':
v1 = times(v1, v2);
System.out.println(v1);
break;
case'/':
v1 = divide(v1, v2);
System.out.println(v1);
break;
case'q':
System.out.println("Your last result was " );
default:
System.out.println("You must choose an appropriate operator .");
}
}
}
double value1, value2;
int n;
public static double sum(double value1,double value2)
{
double newSum = value1 + value2;
return newSum;
}
public static double minus(double value1, double value2)
{
double newMinus = value1 - value2;
return newMinus;
}
public static double times(double value1, double value2)
{
double newTimes = value1 * value2;
return newTimes;
}
public static double divide(double value1, double value2)
{
if (value2 == 0)
{
System.out.println("Division by Zero. Try again");
return value1;
}
double newDivide = value1 / value2;
return newDivide;
}
}
總結
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