Base62 編碼用62個可見字符來編碼信息，也就是所謂的62進制，可用于縮短地址之類的。實現起來也很簡單。當然，這個實現跟別人家的有可能不一樣，反正自己能編能解就行。?

package mainimport ("math""strings" )const CODE62 = "0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ" const CODE_LENTH = 62 var EDOC = map[string]int{"0":0,"1":1,"2":2,"3":3,"4":4,"5":5,"6":6,"7":7,"8":8,"9":9,"a":10,"b":11,"c":12,"d":13,"e":14,"f":15,"g":16,"h":17,"i":18,"j":19,"k":20,"l":21,"m":22,"n":23,"o":24,"p":25,"q":26,"r":27,"s":28,"t":29,"u":30,"v":31,"w":32,"x":33,"y":34,"z":35,"A":36,"B":37,"C":38,"D":39,"E":40,"F":41,"G":42,"H":43,"I":44,"J":45,"K":46,"L":47,"M":48,"N":49,"O":50,"P":51,"Q":52,"R":53,"S":54,"T":55,"U":56,"V":57,"W":58,"X":59,"Y":60,"Z":61, }/*** 編碼 整數 為 base62 字符串*/ func Encode(number int) string {if number == 0 {return "0"}result := make([]byte , 0)for number > 0 {round := number / CODE_LENTHremain := number % CODE_LENTHresult = append(result,CODE62[remain])number = round}return string(result) }/*** 解碼字符串為整數*/ func Decode(str string) int {str = strings.TrimSpace(str)var result int = 0for index,char := range []byte(str){result += EDOC[string(char)] * int(math.Pow(CODE_LENTH,float64(index)))}return result }

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里面硬編碼了 CODE_LENGTH 是不想每次去算一下長度，省點時間。

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轉載于:https://www.cnblogs.com/qufo/p/5730229.html

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