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Clone Graph

發布時間:2025/5/22 编程问答 14 豆豆
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題目

Clone an undirected graph. Each node in the graph contains a?label?and a list of its?neighbors.

OJ's undirected graph serialization:

Nodes are labeled uniquely.

We use?#?as a separator for each node, and?,?as a separator for node label and each neighbor of the node.

As an example, consider the serialized graph?{0,1,2#1,2#2,2}.

The graph has a total of three nodes, and therefore contains three parts as separated by?#.

  • First node is labeled as?0. Connect node?0?to both nodes?1?and?2.
  • Second node is labeled as?1. Connect node?1?to node?2.
  • Third node is labeled as?2. Connect node?2?to node?2?(itself), thus forming a self-cycle.
  • Visually, the graph looks like the following:

    1/ \/ \0 --- 2/ \\_/

    方法

    主要分兩步:第一步創建全部的結點。第二步,創建結點的neighbors /*** Definition for undirected graph.* class UndirectedGraphNode {* int label;* List<UndirectedGraphNode> neighbors;* UndirectedGraphNode(int x) { label = x; neighbors = new ArrayList<UndirectedGraphNode>(); }* };*/ public class Solution {public UndirectedGraphNode cloneGraph(UndirectedGraphNode node) {if (node == null) {return null;}Map<Integer, UndirectedGraphNode> map = new HashMap<Integer, UndirectedGraphNode>();Map<Integer, UndirectedGraphNode> graph = new HashMap<Integer, UndirectedGraphNode>();Queue<UndirectedGraphNode> queue = new LinkedList<UndirectedGraphNode>();queue.offer(node);while(!queue.isEmpty()) {UndirectedGraphNode temp = queue.poll();if (!map.containsKey(temp.label)) {UndirectedGraphNode newTemp = new UndirectedGraphNode(temp.label);graph.put(temp.label, temp);map.put(temp.label, newTemp);}for (UndirectedGraphNode neighbor : temp.neighbors) {if (!map.containsKey(neighbor.label)) {queue.offer(neighbor);}}}for (int label : graph.keySet()) {UndirectedGraphNode temp = graph.get(label);UndirectedGraphNode cloneTemp = map.get(temp.label);for (UndirectedGraphNode neighbor : temp.neighbors) {cloneTemp.neighbors.add(map.get(neighbor.label));}}return map.get(node.label);} }


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