稱號：
Given an array and a value, remove all instances of that value in place and return the new length.

The order of elements can be changed. It doesn’t matter what you leave beyond the new length.

這道題比較簡單直接看代碼，這里多寫幾個版本號的作參考！

C++版本號

class Solution { public:int removeElement(int A[], int n, int elem){int pt = 0;for (int i = 0; i < n; i++){if (A[i] != elem) A[pt++] = A[i];}return pt;} };

C#版本號：

public class Solution {public int RemoveElement(int[] A, int elem){int pt = 0;for (int i = 0; i < A.Length; i++){if (A[i] != elem) A[pt++] = A[i];}return pt;} }

Python版本號：

class Solution:# @param A a list of integers# @param elem an integer, value need to be removed# @return an integerdef removeElement(self, A, elem):pt = 0for i in range(len(A)):if A[i] != elem:A[pt] = A[i]pt += 1return pt

Java版本號：

public class Solution {public int removeElement(int[] A, int elem) {int pt = 0;for (int i = 0; i < A.length; i++){if (A[i] != elem) A[pt++] = A[i];}return pt;} }

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轉載于:https://www.cnblogs.com/gcczhongduan/p/4805679.html

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