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第29节专业英语1

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1[單項(xiàng)選擇題]A project life cycle is a collection of generally sequential project ( ) whose name and number are determined by the control needs of the organization or

Aganizations involved in the project.

Bphases

Cframework

Dprocesses

Esegments

【參考答案】B

【題目解析】一個(gè)項(xiàng)目的生命周期由若干個(gè)順序相連的階段（phases）組成，階段的名字和個(gè)數(shù)由組織的控制需要決定

2[單項(xiàng)選擇題]TCP/IP communication protocol contains four layers. From bottom to top, the four layers are （）.

Anetwork interface layer, internet layer, transport layer and application layer

Binternet layer, network interface layer, transport layer and application layer

Cnetwork interface layer, transport layer, network interface layer and application layer

Dapplication layer, transport layer, internet layer and network interface layer

【參考答案】A

【題目解析】TCP/IP通訊協(xié)議分為4層，從最上層到最下層分別是()。
A．網(wǎng)絡(luò)接口層，互聯(lián)網(wǎng)層，傳輸層和應(yīng)用層
B．互聯(lián)網(wǎng)層，網(wǎng)絡(luò)接口層，傳輸層和應(yīng)用層
C網(wǎng)絡(luò)接口層，傳輸層，互聯(lián)網(wǎng)層和應(yīng)用層
D應(yīng)用層，傳輸層，互聯(lián)網(wǎng)層和網(wǎng)絡(luò)接口層

3[單項(xiàng)選擇題]IPv6 is short for "Internet Protocol Version 6". IPv6 is the "next generation" protocol designed by the IETF to (71) the current version Internet Protocol.IP version 4("IPv4").Most of today's internet uses IPv4, which is now more than twenty years old. IPv4 has been ? (72) resilient in spite of its age, but it is beginning to have problems. Most importantly, there is a growing (73) of IPv4 addresses, which are needed by all new machines added to the Internet. lPv6 fixes a number of problems in IPv4, such as the (74) number of available IPv4 addresses. It also adds many improvements to IPv4 in areas such as routing and network autoconfiguration. IPv6 is expected to gradually replace IPv4, with the two coexisting for a number of years during a transition (75).

IPv6 is short for "Internet Protocol Version 6". IPv6 is the "next generation" protocol designed by the IETF to (71) the current version Internet Protocol.IP version 4("IPv4").Most of today's internet uses IPv4, which is now more than twenty years old. IPv4 has been ? (72) resilient in spite of its age, but it is beginning to have problems. Most importantly, there is a growing (73) of IPv4 addresses, which are needed by all new machines added to the Internet. lPv6 fixes a number of problems in IPv4, such as the (74) number of available IPv4 addresses. It also adds many improvements to IPv4 in areas such as routing and network autoconfiguration. IPv6 is expected to gradually replace IPv4, with the two coexisting for a number of years during a transition (75).

Aremainder

Bremarkably

Cordinary

Dabbreviation

參考答案：B
解析：?(71) D： (72) B； (73) A； (74) C； (75) B。
IPv6是“互聯(lián)網(wǎng)協(xié)議第6版”的簡(jiǎn)稱.它是由IETF設(shè)計(jì)的下一代互聯(lián)網(wǎng)協(xié)議，目的是取代（replace)現(xiàn)有的互聯(lián)網(wǎng)協(xié)議第4版（IPv4)。
目前，大多數(shù)互聯(lián)網(wǎng)使用的IPv4己經(jīng)有了20多年的歷史。雖然IPv4在過(guò)去的應(yīng)用中具有不同尋常的（remarkably)業(yè)績(jī)，但是現(xiàn)在看來(lái)已經(jīng)暴露出很多缺點(diǎn)。最為重要的是，現(xiàn)在的互聯(lián)網(wǎng)(IPv4)己經(jīng)面臨地址短缺（shortage)的問(wèn)題，而這正是所有新加入互聯(lián)網(wǎng)的計(jì)算機(jī)所迫切需要的。IPv6能夠解決IPv4存在的諸如有效網(wǎng)絡(luò)地址受限（limited)等問(wèn)題，同時(shí)還對(duì)IPv4做了大量的改進(jìn)，包括路由和網(wǎng)絡(luò)自動(dòng)配置等。IPv6和IPv4將在過(guò)渡期（period)內(nèi)共存幾年，以后IPv6將漸漸取代IPv4.

Adays

Bperiod

Cphase

Depoch

Arestrict

Bconfine

Climited

Dimprison

參考答案：C
解析：?(71) D： (72) B； (73) A； (74) C； (75) B。
IPv6是“互聯(lián)網(wǎng)協(xié)議第6版”的簡(jiǎn)稱.它是由IETF設(shè)計(jì)的下一代互聯(lián)網(wǎng)協(xié)議，目的是取代（replace)現(xiàn)有的互聯(lián)網(wǎng)協(xié)議第4版（IPv4)。
目前，大多數(shù)互聯(lián)網(wǎng)使用的IPv4己經(jīng)有了20多年的歷史。雖然IPv4在過(guò)去的應(yīng)用中具有不同尋常的（remarkably)業(yè)績(jī)，但是現(xiàn)在看來(lái)已經(jīng)暴露出很多缺點(diǎn)。最為重要的是，現(xiàn)在的互聯(lián)網(wǎng)(IPv4)己經(jīng)面臨地址短缺（shortage)的問(wèn)題，而這正是所有新加入互聯(lián)網(wǎng)的計(jì)算機(jī)所迫切需要的。IPv6能夠解決IPv4存在的諸如有效網(wǎng)絡(luò)地址受限（limited)等問(wèn)題，同時(shí)還對(duì)IPv4做了大量的改進(jìn)，包括路由和網(wǎng)絡(luò)自動(dòng)配置等。IPv6和IPv4將在過(guò)渡期（period)內(nèi)共存幾年，以后IPv6將漸漸取代IPv4.

Asubstitution

Bswap

Cswitchover

Dreplace

參考答案：D
解析：?(71) D： (72) B； (73) A； (74) C； (75) B。
IPv6是“互聯(lián)網(wǎng)協(xié)議第6版”的簡(jiǎn)稱.它是由IETF設(shè)計(jì)的下一代互聯(lián)網(wǎng)協(xié)議，目的是取代（replace)現(xiàn)有的互聯(lián)網(wǎng)協(xié)議第4版（IPv4)。
目前，大多數(shù)互聯(lián)網(wǎng)使用的IPv4己經(jīng)有了20多年的歷史。雖然IPv4在過(guò)去的應(yīng)用中具有不同尋常的（remarkably)業(yè)績(jī)，但是現(xiàn)在看來(lái)已經(jīng)暴露出很多缺點(diǎn)。最為重要的是，現(xiàn)在的互聯(lián)網(wǎng)(IPv4)己經(jīng)面臨地址短缺（shortage)的問(wèn)題，而這正是所有新加入互聯(lián)網(wǎng)的計(jì)算機(jī)所迫切需要的。IPv6能夠解決IPv4存在的諸如有效網(wǎng)絡(luò)地址受限（limited)等問(wèn)題，同時(shí)還對(duì)IPv4做了大量的改進(jìn)，包括路由和網(wǎng)絡(luò)自動(dòng)配置等。IPv6和IPv4將在過(guò)渡期（period)內(nèi)共存幾年，以后IPv6將漸漸取代IPv4.

Ashortage

Black

Cdeficiency

Dscarcity

參考答案：A
解析：?(71) D： (72) B； (73) A； (74) C； (75) B。
IPv6是“互聯(lián)網(wǎng)協(xié)議第6版”的簡(jiǎn)稱.它是由IETF設(shè)計(jì)的下一代互聯(lián)網(wǎng)協(xié)議，目的是取代（replace)現(xiàn)有的互聯(lián)網(wǎng)協(xié)議第4版（IPv4)。
目前，大多數(shù)互聯(lián)網(wǎng)使用的IPv4己經(jīng)有了20多年的歷史。雖然IPv4在過(guò)去的應(yīng)用中具有不同尋常的（remarkably)業(yè)績(jī)，但是現(xiàn)在看來(lái)已經(jīng)暴露出很多缺點(diǎn)。最為重要的是，現(xiàn)在的互聯(lián)網(wǎng)(IPv4)己經(jīng)面臨地址短缺（shortage)的問(wèn)題，而這正是所有新加入互聯(lián)網(wǎng)的計(jì)算機(jī)所迫切需要的。IPv6能夠解決IPv4存在的諸如有效網(wǎng)絡(luò)地址受限（limited)等問(wèn)題，同時(shí)還對(duì)IPv4做了大量的改進(jìn)，包括路由和網(wǎng)絡(luò)自動(dòng)配置等。IPv6和IPv4將在過(guò)渡期（period)內(nèi)共存幾年，以后IPv6將漸漸取代IPv4.

【題目解析】(71) D： (72) B； (73) A； (74) C； (75) B。
IPv6是“互聯(lián)網(wǎng)協(xié)議第6版”的簡(jiǎn)稱.它是由IETF設(shè)計(jì)的下一代互聯(lián)網(wǎng)協(xié)議，目的是取代（replace)現(xiàn)有的互聯(lián)網(wǎng)協(xié)議第4版（IPv4)。
目前，大多數(shù)互聯(lián)網(wǎng)使用的IPv4己經(jīng)有了20多年的歷史。雖然IPv4在過(guò)去的應(yīng)用中具有不同尋常的（remarkably)業(yè)績(jī)，但是現(xiàn)在看來(lái)已經(jīng)暴露出很多缺點(diǎn)。最為重要的是，現(xiàn)在的互聯(lián)網(wǎng)(IPv4)己經(jīng)面臨地址短缺（shortage)的問(wèn)題，而這正是所有新加入互聯(lián)網(wǎng)的計(jì)算機(jī)所迫切需要的。IPv6能夠解決IPv4存在的諸如有效網(wǎng)絡(luò)地址受限（limited)等問(wèn)題，同時(shí)還對(duì)IPv4做了大量的改進(jìn)，包括路由和網(wǎng)絡(luò)自動(dòng)配置等。IPv6和IPv4將在過(guò)渡期（period)內(nèi)共存幾年，以后IPv6將漸漸取代IPv4.

4[單項(xiàng)選擇題]WLAN is increasingly popular because it enables cost-effective （） among people and applications that were not possible in the past.

Aline

Bcircuit

Cconnection

DInterface

【參考答案】C

【題目解析】WLAN快速流行是因?yàn)樗谌藗兣c應(yīng)用軟件之間提供了高效的（），這在過(guò)去不能實(shí)現(xiàn)。
A、線?
B、環(huán)路?
C、連接?
D、界面

5[單項(xiàng)選擇題]Project Quality Management must address the management of the project and the （） of the project. While Project Quality Management applies to all projects, regardless of the nature of their product, product quality measures and techniques are specific to the particular type of product produced by the project.

Aperformance

Bprocess

Cproduct

Dobject

【參考答案】C

【題目解析】項(xiàng)目質(zhì)量管理必須專注于對(duì)項(xiàng)目和項(xiàng)目產(chǎn)品的管理。當(dāng)所有的項(xiàng)目在運(yùn)用項(xiàng)目質(zhì)量管理時(shí)，無(wú)論項(xiàng)目產(chǎn)品的本質(zhì)如何，都要依據(jù)項(xiàng)目所產(chǎn)生產(chǎn)品的類型明確產(chǎn)品質(zhì)量的度量和技術(shù)。

6[單項(xiàng)選擇題]all of the following tools and techniques are helpful to acurately confirming customers needs except （）

Aquestionnaires

Bprototyping approaches

Cfishbone diagrams

Dinterviews

【參考答案】C

【題目解析】以下所有的工具和技術(shù)有助于準(zhǔn)確地確定客戶的需求，除了（）
A、問(wèn)卷
B、原型方法
C、魚骨圖
D、訪談

7[單項(xiàng)選擇題]The features and functions that characterize a product, service, or esult in a project are called ( ).

A. statement of work

BProduct Scope

CProduct quality

DProject scope

【參考答案】A

【題目解析】用來(lái)描述項(xiàng)目提供的產(chǎn)品、服務(wù)或成果的那些特性和功能被稱為（）。
A、工作說(shuō)明書
B、產(chǎn)品范圍
C、產(chǎn)品質(zhì)量
D、項(xiàng)目范圍

8[單項(xiàng)選擇題]A（） infected computer may lose its data.

Afile

Bdata base

Cvirus

Dprogram

【參考答案】C

【題目解析】感染病毒的計(jì)算機(jī)可能會(huì)丟失數(shù)據(jù)。

9[單項(xiàng)選擇題]Although a given waveform may contain frequencies over a very broad range, as a practical matter any transmission system will be able to accommodate only a limited band of ?（1） ?. This, in turn, limits the data rate that can be carried on the transmission ?（2） ?. A square wave has an infinite number of frequency components and hence an infinite ?（3） ?.However, the peak amplitude of the kth frequency component, kf, is only 1/k, so most of the ? ?（4） ?in this waveform is in the first few frequency components. In general, any digital waveform will have ?（5） ?bandwidth. If we attempt to transmit this waveform as a signal over any medium, the transmission system will limit the bandwidth that can be transmitted.

Although a given waveform may contain frequencies over a very broad range, as a practical matter any transmission system will be able to accommodate only a limited band of ?（1） ?. This, in turn, limits the data rate that can be carried on the transmission ?（2） ?. A square wave has an infinite number of frequency components and hence an infinite ?（3） ?.However, the peak amplitude of the kth frequency component, kf, is only 1/k, so most of the ???（4） ?in this waveform is in the first few frequency components. In general, any digital waveform will have ?（5） ?bandwidth. If we attempt to transmit this waveform as a signal over any medium, the transmission system will limit the bandwidth that can be transmitted.

Asmall

Blimited

Cinfinite

Dfinite

參考答案：C
解析：雖然一個(gè)給定的波形包含了很寬的頻率范圍，但是任何實(shí)際的傳輸系統(tǒng)只能夠通過(guò)有限的頻帶。這樣，就限制了傳輸介質(zhì)可以承載的數(shù)據(jù)速率。一個(gè)方波包含了無(wú)限多的頻率成分，因而也具有無(wú)限的帶寬。然而，第k個(gè)頻率成分的峰值幅度kf只是1/k，所以波形的大部分能量只是包含在前面的少數(shù)頻率成分中。一般來(lái)說(shuō)，任何數(shù)字波形都有無(wú)限帶寬。如果我們?cè)噲D在某種介質(zhì)上傳輸這種波形信號(hào)，則傳輸系統(tǒng)實(shí)際上會(huì)限制可以發(fā)送的帶寬。

2.雖然一個(gè)給定的波形包含了很寬的頻率范圍，但是任何實(shí)際的傳輸系統(tǒng)只能夠通過(guò)有限的頻帶。這樣，就限制了傳輸介質(zhì)可以承載的數(shù)據(jù)速率。一個(gè)方波包含了無(wú)限多的頻率成分，因而也具有無(wú)限的帶寬。然而，第k個(gè)頻率成分的峰值幅度kf只是1/k，所以波形的大部分能量只是包含在前面的少數(shù)頻率成分中。一般來(lái)說(shuō)，任何數(shù)字波形都有無(wú)限帶寬。如果我們?cè)噲D在某種介質(zhì)上傳輸這種波形信號(hào)，則傳輸系統(tǒng)實(shí)際上會(huì)限制可以發(fā)送的帶寬。

Afrequency

Benergy

Camplitude

Dphase

參考答案：B
解析：雖然一個(gè)給定的波形包含了很寬的頻率范圍，但是任何實(shí)際的傳輸系統(tǒng)只能夠通過(guò)有限的頻帶。這樣，就限制了傳輸介質(zhì)可以承載的數(shù)據(jù)速率。一個(gè)方波包含了無(wú)限多的頻率成分，因而也具有無(wú)限的帶寬。然而，第k個(gè)頻率成分的峰值幅度kf只是1/k，所以波形的大部分能量只是包含在前面的少數(shù)頻率成分中。一般來(lái)說(shuō)，任何數(shù)字波形都有無(wú)限帶寬。如果我們?cè)噲D在某種介質(zhì)上傳輸這種波形信號(hào)，則傳輸系統(tǒng)實(shí)際上會(huì)限制可以發(fā)送的帶寬。

Asource

Bbandwidth

Cenergy

Dcost

Aprocedures

Bfunction

Croute

Dmedium

參考答案：D
解析：雖然一個(gè)給定的波形包含了很寬的頻率范圍，但是任何實(shí)際的傳輸系統(tǒng)只能夠通過(guò)有限的頻帶。這樣，就限制了傳輸介質(zhì)可以承載的數(shù)據(jù)速率。一個(gè)方波包含了無(wú)限多的頻率成分，因而也具有無(wú)限的帶寬。然而，第k個(gè)頻率成分的峰值幅度kf只是1/k，所以波形的大部分能量只是包含在前面的少數(shù)頻率成分中。一般來(lái)說(shuō)，任何數(shù)字波形都有無(wú)限帶寬。如果我們?cè)噲D在某種介質(zhì)上傳輸這種波形信號(hào)，則傳輸系統(tǒng)實(shí)際上會(huì)限制可以發(fā)送的帶寬。

Afrequencies

Bconnections

Cdiagrams

Dresources

參考答案：A
解析：雖然一個(gè)給定的波形包含了很寬的頻率范圍，但是任何實(shí)際的傳輸系統(tǒng)只能夠通過(guò)有限的頻帶。這樣，就限制了傳輸介質(zhì)可以承載的數(shù)據(jù)速率。一個(gè)方波包含了無(wú)限多的頻率成分，因而也具有無(wú)限的帶寬。然而，第k個(gè)頻率成分的峰值幅度kf只是1/k，所以波形的大部分能量只是包含在前面的少數(shù)頻率成分中。一般來(lái)說(shuō)，任何數(shù)字波形都有無(wú)限帶寬。如果我們?cè)噲D在某種介質(zhì)上傳輸這種波形信號(hào)，則傳輸系統(tǒng)實(shí)際上會(huì)限制可以發(fā)送的帶寬。

【題目解析】雖然一個(gè)給定的波形包含了很寬的頻率范圍，但是任何實(shí)際的傳輸系統(tǒng)只能夠通過(guò)有限的頻帶。這樣，就限制了傳輸介質(zhì)可以承載的數(shù)據(jù)速率。一個(gè)方波包含了無(wú)限多的頻率成分，因而也具有無(wú)限的帶寬。然而，第k個(gè)頻率成分的峰值幅度kf只是1/k，所以波形的大部分能量只是包含在前面的少數(shù)頻率成分中。一般來(lái)說(shuō)，任何數(shù)字波形都有無(wú)限帶寬。如果我們?cè)噲D在某種介質(zhì)上傳輸這種波形信號(hào)，則傳輸系統(tǒng)實(shí)際上會(huì)限制可以發(fā)送的帶寬。

10[單項(xiàng)選擇題]The （） process analyzes the effect of risk events and assigns a numerical rating to those risks.

ARisk Identification

BQuantitative Risk Analysis

CQualitative Risk Analysis

DRisk Monitoring and Control

【參考答案】B

【題目解析】定量分析分析過(guò)程分析風(fēng)險(xiǎn)事件的影響并對(duì)這些風(fēng)險(xiǎn)賦予一個(gè)數(shù)值化的評(píng)價(jià)。

11[單項(xiàng)選擇題]OSPF routing protocol typically runs over()。

AIP

BTCP

CUDP

DARP

【參考答案】A

【題目解析】本題題意為：OSPF協(xié)議基于什么協(xié)議。
OSPF開放最短路徑優(yōu)先(Open Shortest Path First)；開放式最短路徑優(yōu)先；開放最短路徑優(yōu)先協(xié)議，其工作是基于IP的。
本題正確答案是A。

12[單項(xiàng)選擇題]Schedule compression shortens the project schedule without changing the project scope, to meet schedule constraints, imposed dates, or other schedule objectives. Schedule compression techniques include crashing and （）

Afast tracking

Bwhat-if scenario analysis

Cresource leveling

Dcritical chain method

【參考答案】A

【題目解析】進(jìn)度壓縮技術(shù)包括快速跟進(jìn)

13[單項(xiàng)選擇題]Tool for defining activities is（）．

ADependency Determination

BPrecedence Diagramming method

CRolling Wave Planning

DSchedule network Templates

【參考答案】C

【題目解析】于定義活動(dòng)的工具/方法是？
選項(xiàng)A是依賴關(guān)系確定法，選項(xiàng)B是前緊關(guān)系繪圖法，選項(xiàng)C是滾動(dòng)式規(guī)劃，選項(xiàng)D是進(jìn)度網(wǎng)絡(luò)模板。其中A、B、D是活動(dòng)排序的方法和工具。
因此，正確答案是C。

14[單項(xiàng)選擇題]Requirements management is the process of （1），analyzing，tracing，prioritizing and agreeing on requirements and then controlling changes and communicating to relevant stakeholders. It is a（2）process throughout a project. A requirement is a capability to which a project outcome（product or service）should conform.

1.Requirements management is the process of （1），analyzing，tracing，prioritizing and agreeing on requirements and then controlling changes and communicating to relevant stakeholders. It is a（2）process throughout a project. A requirement is a capability to which a project outcome（product or service）should conform.

Apersistent

Bcontinuing

Cpermanent

Dcontinuous

參考答案：D
解析：需求管理包括需求獲取(收集)，需求分析，需求定義和需求驗(yàn)證。需求管理是持續(xù)的過(guò)程

2.Requirements management is the process of （1），analyzing，tracing，prioritizing and agreeing on requirements and then controlling changes and communicating to relevant stakeholders. It is a（2）process throughout a project. A requirement is a capability to which a project outcome（product or service）should conform.

Acommunicating

Bcollecting

Cfiling

Ddocumenting

參考答案：B
解析：需求管理包括需求獲取(收集)，需求分析，需求定義和需求驗(yàn)證。需求管理是持續(xù)的過(guò)程

【題目解析】需求管理包括需求獲取(收集)，需求分析，需求定義和需求驗(yàn)證。需求管理是持續(xù)的過(guò)程

15[單項(xiàng)選擇題]WebSQL is a SQL-like （1） language for extracting information from the web. Its capabilities for performing navigation of web （2） make it a useful tool for automating several web-related tasks that require the systematic processing of either all the links in a （3） , all the pages that can be reached from a given URL through （4） that match a pattern, or a combination of both. WebSQL also provides transparent access to index servers that can be queried via the Common （5） Interface.

WebSQL is a SQL-like?（1）?language for extracting information from the web. Its capabilities for performing navigation of web?（2）?make it a useful tool for automating several web-related tasks that require the systematic processing of either all the links in a?（3）?, all the pages that can be reached from a given URL through?（4）?that match a pattern, or a combination of both. WebSQL also provides transparent access to index servers that can be queried via the Common?（5）?Interface.

Aquery

Btransaction

Ccommunication

Dprogramming

參考答案：A
解析：WebSQL是一種類似于SQL的查詢語(yǔ)言，用于從Web中提取信息。它能夠在Web超文本中巡航，這使得它成為自動(dòng)操作一個(gè)頁(yè)面中有關(guān)鏈接的有用工具，或是作為搜索從一個(gè)給定的URL可以到達(dá)的、所有匹配某種模式的頁(yè)面的有用工具。WebSQL也提供透明地訪問(wèn)索引服務(wù)器的手段，這種服務(wù)器可以通過(guò)公共網(wǎng)關(guān)接口進(jìn)行查詢。

Apaths

Bchips

Ctools

Ddirectories

Abrowsers

Bservers

Chypertexts

Dclients

參考答案：C
解析：WebSQL是一種類似于SQL的查詢語(yǔ)言，用于從Web中提取信息。它能夠在Web超文本中巡航，這使得它成為自動(dòng)操作一個(gè)頁(yè)面中有關(guān)鏈接的有用工具，或是作為搜索從一個(gè)給定的URL可以到達(dá)的、所有匹配某種模式的頁(yè)面的有用工具。WebSQL也提供透明地訪問(wèn)索引服務(wù)器的手段，這種服務(wù)器可以通過(guò)公共網(wǎng)關(guān)接口進(jìn)行查詢。

【題目解析】WebSQL是一種類似于SQL的查詢語(yǔ)言，用于從Web中提取信息。它能夠在Web超文本中巡航，這使得它成為自動(dòng)操作一個(gè)頁(yè)面中有關(guān)鏈接的有用工具，或是作為搜索從一個(gè)給定的URL可以到達(dá)的、所有匹配某種模式的頁(yè)面的有用工具。WebSQL也提供透明地訪問(wèn)索引服務(wù)器的手段，這種服務(wù)器可以通過(guò)公共網(wǎng)關(guān)接口進(jìn)行查詢。

16[單項(xiàng)選擇題]DOM is a platform- and language- （1） API that allows programs and scripts to dynamically access and update the content, structure and style of WWW documents（currently, definitions for HTML and XML documents are part of the specification）. The document can be further processed and the results of that processing can be incorporated back into the presented ?（2） . DOM is a ?（3） -based AP1 to documents, which requires the whole document to be represented in ?（4） ?while processing it. A simpler alternative to DOM is the event-based SAX, which can be used to process very large （5） documents that do not fit into the memory available for processing.

1.DOM is a platform- and language- （1） API that allows programs and scripts to dynamically access and update the content, structure and style of WWW documents（currently, definitions for HTML and XML documents are part of the specification）. The document can be further processed and the results of that processing can be incorporated back into the presented ?（2） . DOM is a ?（3） -based AP1 to documents, which requires the whole document to be represented in ?（4） ?while processing it. A simpler alternative to DOM is the event-based SAX, which can be used to process very large （5） documents that do not fit into the memory available for processing.

Aspecific

Bneutral

Ccontained

Drelated

參考答案：B

2.DOM is a platform- and language- （1） API that allows programs and scripts to dynamically access and update the content, structure and style of WWW documents（currently, definitions for HTML and XML documents are part of the specification）. The document can be further processed and the results of that processing can be incorporated back into the presented ?（2） . DOM is a ?（3） -based AP1 to documents, which requires the whole document to be represented in ?（4） ?while processing it. A simpler alternative to DOM is the event-based SAX, which can be used to process very large （5） documents that do not fit into the memory available for processing.

Adocument

Bprocessor

Cdisc

Dmemory

參考答案：D

3.DOM is a platform- and language- （1） API that allows programs and scripts to dynamically access and update the content, structure and style of WWW documents（currently, definitions for HTML and XML documents are part of the specification）. The document can be further processed and the results of that processing can be incorporated back into the presented ?（2） . DOM is a ?（3） -based AP1 to documents, which requires the whole document to be represented in ?（4） ?while processing it. A simpler alternative to DOM is the event-based SAX, which can be used to process very large （5） documents that do not fit into the memory available for processing.

Atable

Btree

Ccontrol

Devent

參考答案：B

4.DOM is a platform- and language- （1） API that allows programs and scripts to dynamically access and update the content, structure and style of WWW documents（currently, definitions for HTML and XML documents are part of the specification）. The document can be further processed and the results of that processing can be incorporated back into the presented ?（2） . DOM is a ?（3） -based AP1 to documents, which requires the whole document to be represented in ?（4） ?while processing it. A simpler alternative to DOM is the event-based SAX, which can be used to process very large （5） documents that do not fit into the memory available for processing.

Atext

Bimage

Cpage

Dgraphic

參考答案：C

5.DOM is a platform- and language- （1） API that allows programs and scripts to dynamically access and update the content, structure and style of WWW documents（currently, definitions for HTML and XML documents are part of the specification）. The document can be further processed and the results of that processing can be incorporated back into the presented ?（2） . DOM is a ?（3） -based AP1 to documents, which requires the whole document to be represented in ?（4） ?while processing it. A simpler alternative to DOM is the event-based SAX, which can be used to process very large （5） documents that do not fit into the memory available for processing.

AXML

BHTML

Cscript

DWeb

參考答案：A

17[單項(xiàng)選擇題]During the project, requirements change for a variety of reasons. As needs change and as work proceeds, additional requirements are derived and changes may have to be made to the existing requirements. It is essential to manage these additions and changes efficiently and effectively. To effectively analyze the impact of the changes, it is necessary that the source of each requirement is known and the rationale for any change is documented. The project manager may, however, want to track appropriate measures of requirements volatility to judge whether new or revised （）are necessary.

Aproceedings

Bcontrols

Cforecasting’s

Dprelibations

【參考答案】B

【題目解析】在一個(gè)項(xiàng)目的生命期內(nèi)，有多種原因可以引起對(duì)需求的變更。當(dāng)需要發(fā)生變更而工作正在進(jìn)行時(shí)，可導(dǎo)致新的需求產(chǎn)生并迫使現(xiàn)有的需求發(fā)生變更。需要快速而有效地管理這些新的需求和新的變更。為了有效地分析這些變更的影響，必須確定每一個(gè)需求源，并記錄變更的基本過(guò)程。無(wú)論如何，項(xiàng)目經(jīng)理希望能追蹤有關(guān)需求穩(wěn)定性的、恰當(dāng)?shù)拇胧?#xff0c;以判斷是否需要新的或修正的控制措施。

18[單項(xiàng)選擇題]The process of software development doesn’t include（）．

Averification function

Bwriting code

Cmanagement function

Dvalidation function

【參考答案】C

【題目解析】本題考查考生對(duì)專業(yè)術(shù)語(yǔ)的理解. A是驗(yàn)證功能,屬于單元測(cè)試：B是代碼編寫，屬于基本工作：C是管理功能，非計(jì)算機(jī)專業(yè)常用術(shù)語(yǔ)：D是功能確認(rèn)，測(cè)試工作之一.所以應(yīng)該選擇C.

19[單項(xiàng)選擇題]Sub-contractors should obey the contractor in information system project. When censoring sub-contractors, the supervisor mostly concerns about （）.

AAmount of subcontract

Bqualifications and abilities of sub-contractors

Cresponsibilities and obligations of sub-contractors

Dthe contents of the subcontract

【參考答案】B

【題目解析】在信息系統(tǒng)工程項(xiàng)目中分包商需服從總承包商。在審查分包合同時(shí)，監(jiān)理最主要關(guān)注的是____。

20[單項(xiàng)選擇題]Each machine in the internet is assigned a unique network address,called（）,that is used to identify the machine for communication purposes

AMAC address

BIP address

Chost address

Ddomain name address

【參考答案】B

【題目解析】在互聯(lián)網(wǎng)上的每個(gè)機(jī)器都被分配了一個(gè)IP地址，這個(gè)地址是用來(lái)和其他機(jī)器通信的。

21[單項(xiàng)選擇題]Adding 5 people to a 4 person team increases the communication channels by a factor of ( )

A、3 times

B4 times

C5 times

D6 times

【參考答案】D

【題目解析】本題的含義是：在四個(gè)人的團(tuán)隊(duì)中增加5人后，溝通的通道會(huì)增加多少倍，要和用計(jì)算機(jī)公式n（ n-1）/2, 4個(gè)人的時(shí)候溝通通道把6條，增加5人后..溝通渠道是36. 增加了 6倍，選擇答案D.

22[單項(xiàng)選擇題]（）is a collection of data sets, which is so large and complex that it becomes difficult to process using on-hand database management tools or traditional data processing applications.

ABig data

BCluster

CParallel computing

DData warehouse

【參考答案】A

【題目解析】（）是一個(gè)數(shù)據(jù)集合，它是如此龐大和復(fù)雜，使得很難使用一般的數(shù)據(jù)庫(kù)管理工具或傳統(tǒng)的數(shù)據(jù)處理應(yīng)用程序中對(duì)它進(jìn)行處理。
A. 大數(shù)據(jù)
B. 集群
C. 并行計(jì)算
D. 數(shù)據(jù)倉(cāng)庫(kù)

23[單項(xiàng)選擇題]Certificates are （1） documents attesting to the （2） of a public key to an individual or other entity. They allow verification of the claim that a given public key does in fact belong to a given individual. Certificates help prevent someone from using a phony key to （3） someone else. In their simplest form, Certificates contain a public key and a name. As commonly used, a certificate also contains an （4） date, the name of the CA that issued the certificate, a serial number, and perhaps other information. Most importantly, it contains the digital （5） of the certificate issuer. The most widely accepted format for certificates is X.509 , thus, Certificates can be read or written by any application complying with X.509.

1.Certificates are （1） documents attesting to the （2） of a public key to an individual or other entity. They allow verification of the claim that a given public key does in fact belong to a given individual. Certificates help prevent someone from using a phony key to （3） someone else. In their simplest form, Certificates contain a public key and a name. As commonly used, a certificate also contains an （4） date, the name of the CA that issued the certificate, a serial number, and perhaps other information. Most importantly, it contains the digital （5） of the certificate issuer. The most widely accepted format for certificates is X.509 , thus, Certificates can be read or written by any application complying with X.509.

Aconnecting

Bbinding

Ccomposing

Dconducting

參考答案：B
解析：證書是用來(lái)證明綁定給個(gè)人或其他實(shí)體的公鑰的數(shù)字文件。它們?cè)试S對(duì)一個(gè)給定的公鑰確實(shí)屬于一個(gè)給定的個(gè)體的聲明的確認(rèn)。認(rèn)證幫助防止某人使用假冒的密鑰去假扮其他人。在它們的最簡(jiǎn)化版本中，認(rèn)證包含一個(gè)公鑰和一個(gè)名字。在通常的使用中，一個(gè)認(rèn)證也包含一個(gè)過(guò)期時(shí)間，發(fā)布認(rèn)證的CA的名字，一個(gè)序列號(hào)還可能有其他信息。最重要的是認(rèn)證發(fā)布者的數(shù)字簽名。被接受的最廣泛的認(rèn)證格式是X.509，因此，認(rèn)證能夠被任何接受X.509的程序讀或?qū)憽?/p>

2.Certificates are （1） documents attesting to the （2） of a public key to an individual or other entity. They allow verification of the claim that a given public key does in fact belong to a given individual. Certificates help prevent someone from using a phony key to （3） someone else. In their simplest form, Certificates contain a public key and a name. As commonly used, a certificate also contains an （4） date, the name of the CA that issued the certificate, a serial number, and perhaps other information. Most importantly, it contains the digital （5） of the certificate issuer. The most widely accepted format for certificates is X.509 , thus, Certificates can be read or written by any application complying with X.509.

Asignature

Bmark

Cstamp

Dhypertext

參考答案：A
解析：證書是用來(lái)證明綁定給個(gè)人或其他實(shí)體的公鑰的數(shù)字文件。它們?cè)试S對(duì)一個(gè)給定的公鑰確實(shí)屬于一個(gè)給定的個(gè)體的聲明的確認(rèn)。認(rèn)證幫助防止某人使用假冒的密鑰去假扮其他人。在它們的最簡(jiǎn)化版本中，認(rèn)證包含一個(gè)公鑰和一個(gè)名字。在通常的使用中，一個(gè)認(rèn)證也包含一個(gè)過(guò)期時(shí)間，發(fā)布認(rèn)證的CA的名字，一個(gè)序列號(hào)還可能有其他信息。最重要的是認(rèn)證發(fā)布者的數(shù)字簽名。被接受的最廣泛的認(rèn)證格式是X.509，因此，認(rèn)證能夠被任何接受X.509的程序讀或?qū)憽?/p>

3.Certificates are （1） documents attesting to the （2） of a public key to an individual or other entity. They allow verification of the claim that a given public key does in fact belong to a given individual. Certificates help prevent someone from using a phony key to （3） someone else. In their simplest form, Certificates contain a public key and a name. As commonly used, a certificate also contains an （4） date, the name of the CA that issued the certificate, a serial number, and perhaps other information. Most importantly, it contains the digital （5） of the certificate issuer. The most widely accepted format for certificates is X.509 , thus, Certificates can be read or written by any application complying with X.509.

Acommunication

Bcomputation

Cexpectation

Dexpiration

參考答案：D
解析：證書是用來(lái)證明綁定給個(gè)人或其他實(shí)體的公鑰的數(shù)字文件。它們?cè)试S對(duì)一個(gè)給定的公鑰確實(shí)屬于一個(gè)給定的個(gè)體的聲明的確認(rèn)。認(rèn)證幫助防止某人使用假冒的密鑰去假扮其他人。在它們的最簡(jiǎn)化版本中，認(rèn)證包含一個(gè)公鑰和一個(gè)名字。在通常的使用中，一個(gè)認(rèn)證也包含一個(gè)過(guò)期時(shí)間，發(fā)布認(rèn)證的CA的名字，一個(gè)序列號(hào)還可能有其他信息。最重要的是認(rèn)證發(fā)布者的數(shù)字簽名。被接受的最廣泛的認(rèn)證格式是X.509，因此，認(rèn)證能夠被任何接受X.509的程序讀或?qū)憽?/p>

4.Certificates are （1） documents attesting to the （2） of a public key to an individual or other entity. They allow verification of the claim that a given public key does in fact belong to a given individual. Certificates help prevent someone from using a phony key to （3） someone else. In their simplest form, Certificates contain a public key and a name. As commonly used, a certificate also contains an （4） date, the name of the CA that issued the certificate, a serial number, and perhaps other information. Most importantly, it contains the digital （5） of the certificate issuer. The most widely accepted format for certificates is X.509 , thus, Certificates can be read or written by any application complying with X.509.

Aimpersonate

Bpersonate

Cdamage

Dcontrol

5.Certificates are （1） documents attesting to the （2） of a public key to an individual or other entity. They allow verification of the claim that a given public key does in fact belong to a given individual. Certificates help prevent someone from using a phony key to （3） someone else. In their simplest form, Certificates contain a public key and a name. As commonly used, a certificate also contains an （4） date, the name of the CA that issued the certificate, a serial number, and perhaps other information. Most importantly, it contains the digital （5） of the certificate issuer. The most widely accepted format for certificates is X.509 , thus, Certificates can be read or written by any application complying with X.509.

Atext

Bdata

Cdigital

Dstructured

參考答案：C
解析：證書是用來(lái)證明綁定給個(gè)人或其他實(shí)體的公鑰的數(shù)字文件。它們?cè)试S對(duì)一個(gè)給定的公鑰確實(shí)屬于一個(gè)給定的個(gè)體的聲明的確認(rèn)。認(rèn)證幫助防止某人使用假冒的密鑰去假扮其他人。在它們的最簡(jiǎn)化版本中，認(rèn)證包含一個(gè)公鑰和一個(gè)名字。在通常的使用中，一個(gè)認(rèn)證也包含一個(gè)過(guò)期時(shí)間，發(fā)布認(rèn)證的CA的名字，一個(gè)序列號(hào)還可能有其他信息。最重要的是認(rèn)證發(fā)布者的數(shù)字簽名。被接受的最廣泛的認(rèn)證格式是X.509，因此，認(rèn)證能夠被任何接受X.509的程序讀或?qū)憽?/p>

【題目解析】證書是用來(lái)證明綁定給個(gè)人或其他實(shí)體的公鑰的數(shù)字文件。它們?cè)试S對(duì)一個(gè)給定的公鑰確實(shí)屬于一個(gè)給定的個(gè)體的聲明的確認(rèn)。認(rèn)證幫助防止某人使用假冒的密鑰去假扮其他人。在它們的最簡(jiǎn)化版本中，認(rèn)證包含一個(gè)公鑰和一個(gè)名字。在通常的使用中，一個(gè)認(rèn)證也包含一個(gè)過(guò)期時(shí)間，發(fā)布認(rèn)證的CA的名字，一個(gè)序列號(hào)還可能有其他信息。最重要的是認(rèn)證發(fā)布者的數(shù)字簽名。被接受的最廣泛的認(rèn)證格式是X.509，因此，認(rèn)證能夠被任何接受X.509的程序讀或?qū)憽?/p>

24[單項(xiàng)選擇題]You are a project manager for a small project. Your project was budgeted for ￥500,000 over a six-week period. As of today, you've spent ￥260,000 of your budget to complete work that you originally expected to cost ￥280,000. According to your schedule, you should have spent ￥300,000 by this point. Based on these circumstances, your project could be BEST described as （） .

AAhead of schedule

BBehind schedule

COn schedule

DHaving not enough information provided

【參考答案】B

【題目解析】你是一個(gè)項(xiàng)目經(jīng)理。你目前負(fù)責(zé)的項(xiàng)目預(yù)算是50萬(wàn)元，工期是6周。到目前為止，你已經(jīng)花費(fèi)了26萬(wàn)工程款，完成了預(yù)算中28萬(wàn)的工作量。根據(jù)你之前制定的進(jìn)度計(jì)劃，到目前為止，你應(yīng)該花費(fèi)30萬(wàn)元工程款。根據(jù)這些描述，你的工程目前____________。

25[單項(xiàng)選擇題]Project work packages are typically decomposed into smaller componentscalled activities to provide a basis for （）, scheduling, executing, and monitoring and controlling the project work.

Areviewing

Bestimating

Cauditing

Dexpecting

【參考答案】B

【題目解析】把項(xiàng)目工作包分解成更小的稱為活動(dòng)的單元，為估算、進(jìn)度安排、項(xiàng)目執(zhí)行、項(xiàng)目監(jiān)控提供了基礎(chǔ)。

26[單項(xiàng)選擇題]TCP（Transmission Control Protocol）was specifically designed to provide a reliable end-to-end byte stream over a(n) ( ).

AIP address

Breliable network

Csocket

Dunreliable internetwork

【參考答案】D

【題目解析】【解析】TCP(傳輸控制協(xié)議)被設(shè)計(jì)成一個(gè)基于不可靠的網(wǎng)絡(luò)上實(shí)現(xiàn)可靠的點(diǎn)到點(diǎn)的比特流協(xié)議。

27[單項(xiàng)選擇題]One tool that is useful during both analysis and design is the（） ,which is a pictorial representation of the items of information(entities)within the system and the relationships between these pieces of information.

Adata dictionary

Bdataflow diagram

Cuse case diagram

Dentity-relationship diagram

【參考答案】D

【題目解析】在系統(tǒng)分析和設(shè)計(jì)中同樣適用的工具是答案D實(shí)體關(guān)系圖，它通過(guò)圖形形式，表現(xiàn)系統(tǒng)內(nèi)的實(shí)體信息以及這些信息之間的關(guān)系。

28[單項(xiàng)選擇題]Stack is quite simple. Many computer systems have stacks built into theircircuitry. They also have machine-level instructions to operate the hardwarestack. Stack is （）in computer systems.

Auseless

Bnot important

Csimple but important

Dtoo simple to be useful

【參考答案】C

【題目解析】本題含義可表述為，棧是相當(dāng)簡(jiǎn)單的.后兩句從意思上看是計(jì)算機(jī)如何實(shí)現(xiàn)棧，實(shí)際說(shuō)棧是計(jì)算機(jī)組成的一個(gè)必要的部分，最后一句是對(duì)前面三句的歸納。所以應(yīng)該選擇 C (簡(jiǎn)單并重要的）?

29[單項(xiàng)選擇題]（）is not included in the main contents of the operation and maintenance of the information system.

ADaily operation and maintenance

BSystem change

CSecurity management

DBusiness change

【參考答案】D

【題目解析】下列（）不是信息系統(tǒng)運(yùn)維工作的內(nèi)容。
A、日常運(yùn)維?
B、系統(tǒng)更新?
C、安全管理?
D、業(yè)務(wù)更新

30[單項(xiàng)選擇題]The project maintains a current and approved set of requirements over the life of the project by doing the following:?
?（）all changes to the requirements?
? Maintaining the relationships among the requirements, the project plans, and the work products

AMonitoring

BManaging

CGathering

DReducing

【參考答案】B

【題目解析】在項(xiàng)目的生命周期里，項(xiàng)目通過(guò)如下措施維持一個(gè)最新的、經(jīng)批準(zhǔn)的需求集合：
理對(duì)需求的變更。
維持需求、項(xiàng)目計(jì)劃和工作產(chǎn)品之間的關(guān)聯(lián)。

31[單項(xiàng)選擇題]( ) is the process of obtaining the stakeholdrs'formal acceptance of the completed project scope.Verifying the scope includes reviewing deliverables and work results to ensure that all were completed satisfactorily.

Ascope definition

BWBS Creation

Cproject acceptance

Dscope verification

【參考答案】D

【題目解析】范圍驗(yàn)證是指獲取項(xiàng)目干系人對(duì)己完成的項(xiàng)目范圍的正式認(rèn)可的過(guò)程. 驗(yàn)證范圍包括了評(píng)審可交付物工作成果，以確定它們均已令人滿意地完成.

32[單項(xiàng)選擇題]The work that needs to be accomplished to deliver a product, service ,or result with the specified features and functions is called ( ).

AScope management

BIntegrated management

CSOW

DPMO

【參考答案】A

【題目解析】為提供具有規(guī)定特性和功能的產(chǎn)品、服務(wù)和成果的是工作被稱為（）。
A、范圍管理
B、集成管理
C、工作說(shuō)明書
D、項(xiàng)目管理辦公室

33[單項(xiàng)選擇題]Perform Quality Control is the process of monitoring and recording results of executing the Quality Plan activities to assess performance and recommend necessary changes.( ) are the techniques and tools in performing quality control.
①Activity network diagram ②Cause and effect diagrams ③Inspection④Flow chart⑤Work Breakdown Structure ⑥Pareto chart

A①③⑤

B①②④⑥

C②③④⑤⑥

D①②③④⑥

【參考答案】D

【題目解析】執(zhí)行質(zhì)量控制是一個(gè)監(jiān)督、評(píng)價(jià)項(xiàng)目質(zhì)量計(jì)劃活動(dòng)執(zhí)行結(jié)果和提出變更請(qǐng)求的過(guò)程。執(zhí)行質(zhì)量控制的技術(shù)和工具包括：活動(dòng)網(wǎng)絡(luò)圖（Activity network diagram)、因果圖 (Cause and effect diagrams)、檢查（Inspection)、流程圖（Flowchart)和帕累托圖 CPareto chart) 等，但不也括工作分解結(jié)構(gòu)（Work Breakdown Structure)o

34[單項(xiàng)選擇題]A well-designed system should be（）.
①easily understood
②reliable
③straightforward to implement
④straightforward to maintain

A①②

B①③④

C②③④

D①②③④

【參考答案】D

【題目解析】本題含義可表述為：一個(gè)優(yōu)秀的系統(tǒng)設(shè)計(jì)應(yīng)該易于理解、具有高可靠性、容易實(shí)現(xiàn)、容易維護(hù)，所以應(yīng)該選擇D,

35[單項(xiàng)選擇題]A requirement is simplya statement of what the system must do or what characteristics it needs to have. Requirements written from the perspective of user and focus on user needs are called _( )_.

Aoperationalrequirements

Bbusiness requirements

Ctechnicalrequirements

Dsystem requirements

【參考答案】B

【題目解析】簡(jiǎn)單說(shuō)需求就是關(guān)于系統(tǒng)必須做什么或需要有哪些特點(diǎn)的稱述。從用戶角度所撰寫的需求主要關(guān)注用戶的需求，稱為業(yè)務(wù)需求。?

36[單項(xiàng)選擇題]Perform Quality Control is the process of monitoring and recording results of executing the Quality Plan activities to assess performance and recommend necessary changes. ( ) are the techniques and tools in performing quality control.
1.Activity network diagram 2.Cause and effect diagrams?
3.Inspection 4.Flow chart
5.Work Breakdown Structure 6.Pareto char

A1.3.5.

B2.4.5.6.

C2.3.4.5.6.

D1.2.3.4.6.

【參考答案】D

【題目解析】執(zhí)行質(zhì)量控制是一個(gè)監(jiān)督、評(píng)價(jià)項(xiàng)目質(zhì)量計(jì)劃活動(dòng)執(zhí)行結(jié)果和提出變更請(qǐng)求的過(guò)程。執(zhí)行質(zhì)量控制的技術(shù)和工具包括：活動(dòng)網(wǎng)絡(luò)圖（Activity network diagram)、因果圖 (Cause and effect diagrams)、檢査(Inspection)、流程圖（Flowchart)和帕累托圖(Pareto chart) 等，但不括工作分解結(jié)構(gòu)（Work Breakdown Structure)。

37[單項(xiàng)選擇題]The metric assigned to each network depends on the type of protocol.Some simple protocol, like RIP, treats each network as equals.The 　（1）　 of passing through each network is the same;it is one 　（2）　 count.So if a packet passes through 10 network to reach the destination, the total cost is 10 hop counts.Other protocols, such as OSPF, allow the administrator to assign a cost for passing through a network based on the type of service required.A 　（3）　 through a network can have different costs（metrics）.For example, if maximum 　（4）　 is the desired type of service, a satellite link has a lower metric than a fiber-optic line.On the other hand, if minimum 　（5）　 is the desired type of service, a fiber-optic line has a lower metric than a satellite line.OSPF allow each router to have several routing table based on the required type of service.

The metric assigned to each network depends on the type of protocol.Some simple protocol, like RIP, treats each network as equals.The?　（1）　?of passing through each network is the same;it is one?　（2）　?count.So if a packet passes through 10 network to reach the destination, the total cost is 10 hop counts.Other protocols, such as OSPF, allow the administrator to assign a cost for passing through a network based on the type of service required.A?　（3）　?through a network can have different costs（metrics）.For example, if maximum?　（4）　?is the desired type of service, a satellite link has a lower metric than a fiber-optic line.On the other hand, if minimum?　（5）　?is the desired type of service, a fiber-optic line has a lower metric than a satellite line.OSPF allow each router to have several routing table based on the required type of service.

Aprocess

Bhop

Croute

Dflow

參考答案：B
解析：賦予每一個(gè)網(wǎng)絡(luò)的路由度量依賴于協(xié)議的類型。對(duì)于像RIP這樣的簡(jiǎn)單協(xié)議，可以認(rèn)為每個(gè)網(wǎng)絡(luò)都是相同的，因而通過(guò)每一個(gè)網(wǎng)絡(luò)的費(fèi)用也都是相同的，其費(fèi)用為1。所以，如果一個(gè)分組經(jīng)過(guò)10個(gè)網(wǎng)絡(luò)到達(dá)目標(biāo)，則總的費(fèi)用就是10跳。其他的協(xié)議，例如OSPF，允許網(wǎng)絡(luò)管理員根據(jù)要求的服務(wù)類型賦予所通過(guò)的網(wǎng)絡(luò)一個(gè)度量值。通過(guò)一個(gè)網(wǎng)絡(luò)的路由可以具有不同的費(fèi)用。例如，若期望的服務(wù)類型為最大吞吐率，則衛(wèi)星鏈路比光纖線路的費(fèi)用低。另一方面，如果期望的服務(wù)類型為最小延遲，則光纖線路比衛(wèi)星線路的費(fèi)用低。OSPF協(xié)議允許每一個(gè)路由器根據(jù)需要的服務(wù)類型設(shè)置幾個(gè)不同的路由表。?

Apacket

Bthroughput

Cerror

Dnumber

Anumber

Bconnection

Cconnection

Dcost

參考答案：D
解析：賦予每一個(gè)網(wǎng)絡(luò)的路由度量依賴于協(xié)議的類型。對(duì)于像RIP這樣的簡(jiǎn)單協(xié)議，可以認(rèn)為每個(gè)網(wǎng)絡(luò)都是相同的，因而通過(guò)每一個(gè)網(wǎng)絡(luò)的費(fèi)用也都是相同的，其費(fèi)用為1。所以，如果一個(gè)分組經(jīng)過(guò)10個(gè)網(wǎng)絡(luò)到達(dá)目標(biāo)，則總的費(fèi)用就是10跳。其他的協(xié)議，例如OSPF，允許網(wǎng)絡(luò)管理員根據(jù)要求的服務(wù)類型賦予所通過(guò)的網(wǎng)絡(luò)一個(gè)度量值。通過(guò)一個(gè)網(wǎng)絡(luò)的路由可以具有不同的費(fèi)用。例如，若期望的服務(wù)類型為最大吞吐率，則衛(wèi)星鏈路比光纖線路的費(fèi)用低。另一方面，如果期望的服務(wù)類型為最小延遲，則光纖線路比衛(wèi)星線路的費(fèi)用低。OSPF協(xié)議允許每一個(gè)路由器根據(jù)需要的服務(wù)類型設(shè)置幾個(gè)不同的路由表。?

Adelay

Bstream

Cpacket

Dpacket

參考答案：A
解析：賦予每一個(gè)網(wǎng)絡(luò)的路由度量依賴于協(xié)議的類型。對(duì)于像RIP這樣的簡(jiǎn)單協(xié)議，可以認(rèn)為每個(gè)網(wǎng)絡(luò)都是相同的，因而通過(guò)每一個(gè)網(wǎng)絡(luò)的費(fèi)用也都是相同的，其費(fèi)用為1。所以，如果一個(gè)分組經(jīng)過(guò)10個(gè)網(wǎng)絡(luò)到達(dá)目標(biāo)，則總的費(fèi)用就是10跳。其他的協(xié)議，例如OSPF，允許網(wǎng)絡(luò)管理員根據(jù)要求的服務(wù)類型賦予所通過(guò)的網(wǎng)絡(luò)一個(gè)度量值。通過(guò)一個(gè)網(wǎng)絡(luò)的路由可以具有不同的費(fèi)用。例如，若期望的服務(wù)類型為最大吞吐率，則衛(wèi)星鏈路比光纖線路的費(fèi)用低。另一方面，如果期望的服務(wù)類型為最小延遲，則光纖線路比衛(wèi)星線路的費(fèi)用低。OSPF協(xié)議允許每一個(gè)路由器根據(jù)需要的服務(wù)類型設(shè)置幾個(gè)不同的路由表。?

Aflow

Bwindow

Croute

Dcost

參考答案：C
解析：賦予每一個(gè)網(wǎng)絡(luò)的路由度量依賴于協(xié)議的類型。對(duì)于像RIP這樣的簡(jiǎn)單協(xié)議，可以認(rèn)為每個(gè)網(wǎng)絡(luò)都是相同的，因而通過(guò)每一個(gè)網(wǎng)絡(luò)的費(fèi)用也都是相同的，其費(fèi)用為1。所以，如果一個(gè)分組經(jīng)過(guò)10個(gè)網(wǎng)絡(luò)到達(dá)目標(biāo)，則總的費(fèi)用就是10跳。其他的協(xié)議，例如OSPF，允許網(wǎng)絡(luò)管理員根據(jù)要求的服務(wù)類型賦予所通過(guò)的網(wǎng)絡(luò)一個(gè)度量值。通過(guò)一個(gè)網(wǎng)絡(luò)的路由可以具有不同的費(fèi)用。例如，若期望的服務(wù)類型為最大吞吐率，則衛(wèi)星鏈路比光纖線路的費(fèi)用低。另一方面，如果期望的服務(wù)類型為最小延遲，則光纖線路比衛(wèi)星線路的費(fèi)用低。OSPF協(xié)議允許每一個(gè)路由器根據(jù)需要的服務(wù)類型設(shè)置幾個(gè)不同的路由表。?

【題目解析】賦予每一個(gè)網(wǎng)絡(luò)的路由度量依賴于協(xié)議的類型。對(duì)于像RIP這樣的簡(jiǎn)單協(xié)議，可以認(rèn)為每個(gè)網(wǎng)絡(luò)都是相同的，因而通過(guò)每一個(gè)網(wǎng)絡(luò)的費(fèi)用也都是相同的，其費(fèi)用為1。所以，如果一個(gè)分組經(jīng)過(guò)10個(gè)網(wǎng)絡(luò)到達(dá)目標(biāo)，則總的費(fèi)用就是10跳。其他的協(xié)議，例如OSPF，允許網(wǎng)絡(luò)管理員根據(jù)要求的服務(wù)類型賦予所通過(guò)的網(wǎng)絡(luò)一個(gè)度量值。通過(guò)一個(gè)網(wǎng)絡(luò)的路由可以具有不同的費(fèi)用。例如，若期望的服務(wù)類型為最大吞吐率，則衛(wèi)星鏈路比光纖線路的費(fèi)用低。另一方面，如果期望的服務(wù)類型為最小延遲，則光纖線路比衛(wèi)星線路的費(fèi)用低。OSPF協(xié)議允許每一個(gè)路由器根據(jù)需要的服務(wù)類型設(shè)置幾個(gè)不同的路由表。

38[單項(xiàng)選擇題]（）a method of obtaining early feedback on requirements by providing a working model of the expected product before actually building it

Aprototype

Bobject oriented

Cstructured method

Diterative method

【參考答案】A

【題目解析】在實(shí)際開發(fā)過(guò)程中提供預(yù)期產(chǎn)品的模型，以獲得早期反饋，這種方法稱為（）法
A、原型?
B、面向?qū)ο蠓?br /> C、結(jié)構(gòu)化方法?
D、迭代法

39[單項(xiàng)選擇題]（）is the budgeted amount for the work actually completed on the schedule activity or WBS component during a given time period.

APlanned value

BEarned value

CActual cost

DCost variance

【參考答案】B

【題目解析】掙值是在給定時(shí)期內(nèi)按進(jìn)度活動(dòng)或WBS部件所完成工作的預(yù)算值。

40[單項(xiàng)選擇題]In all projects, needs must be tempered by schedule , cost and resource constraints. Project success depends primarily on().

AThe quality of the schedule and cost control analysis

BCustomer satistaction

CCustomer compromise in defining its needs

DExceeding customer requirements through gold-plating

【參考答案】B

【題目解析】在所有項(xiàng)目中，客戶的要求必須根據(jù)進(jìn)度，成本和資源約束。項(xiàng)目的成功主要取決于（）。?
A、質(zhì)量進(jìn)度成本控制分析?
B、客戶滿意度?
C、在定義需求時(shí)與客戶妥協(xié)?
D、通過(guò)鍍金超過(guò)客戶要求?

41[單項(xiàng)選擇題]（） is one of the tools and techniques of Sequence Activities

ADecomposition

BFishbone Diagram

CPrecedence Diagramming Method

DExpert Judgment

【參考答案】C

【題目解析】下列（）為活動(dòng)排序的方法。
A、分解?
B、魚骨圖
C、前導(dǎo)圖法?
D、專家判斷

42[單項(xiàng)選擇題]Serialization delay and （1） delay are the two components of network delay that are improved by increasing bandwidth. Serialization delay, i.e. the amount of time it takes to put the （2） on the wire, and queuing delay (depth of the queue) are improved by increasing the （3） from a 128kbps circuit to a T1. However, three other components of delay, routing/switching delay, distance delay, and protocol delay are components that can not be positively affected by an （4） in bandwidth. If the circuits are not over-utilized, then increasing the bandwidth to improve the （5） of the application will only result in an increased bandwidth with no positive effects on performance.

1.Serialization delay and ?（1） ?delay are the two components of network delay that are improved by increasing bandwidth. Serialization delay, i.e. the amount of time it takes to put the ?（2） ?on the wire, and queuing delay (depth of the queue) are improved by increasing the ?（3） ?from a 128kbps circuit to a T1. However, three other components of delay, routing/switching delay, distance delay, and protocol delay are components that can not be positively affected by an ?（4） ?in bandwidth. If the circuits are not over-utilized, then increasing the bandwidth to improve the ?（5） ?of the application will only result in an increased bandwidth with no positive effects on performance.

Abuffering

Bqueuing

Creceiving

Dtiming

參考答案：B

2.Serialization delay and ?（1） ?delay are the two components of network delay that are improved by increasing bandwidth. Serialization delay, i.e. the amount of time it takes to put the ?（2） ?on the wire, and queuing delay (depth of the queue) are improved by increasing the ?（3） ?from a 128kbps circuit to a T1. However, three other components of delay, routing/switching delay, distance delay, and protocol delay are components that can not be positively affected by an ?（4） ?in bandwidth. If the circuits are not over-utilized, then increasing the bandwidth to improve the ?（5） ?of the application will only result in an increased bandwidth with no positive effects on performance.

Aincrease

Bdecrease

Cmaintenance

Dextension

參考答案：A

3.Serialization delay and ?（1） ?delay are the two components of network delay that are improved by increasing bandwidth. Serialization delay, i.e. the amount of time it takes to put the ?（2） ?on the wire, and queuing delay (depth of the queue) are improved by increasing the ?（3） ?from a 128kbps circuit to a T1. However, three other components of delay, routing/switching delay, distance delay, and protocol delay are components that can not be positively affected by an ?（4） ?in bandwidth. If the circuits are not over-utilized, then increasing the bandwidth to improve the ?（5） ?of the application will only result in an increased bandwidth with no positive effects on performance.

Acapability

Bcost

Camount

Dperformance

參考答案：D

4.Serialization delay and ?（1） ?delay are the two components of network delay that are improved by increasing bandwidth. Serialization delay, i.e. the amount of time it takes to put the ?（2） ?on the wire, and queuing delay (depth of the queue) are improved by increasing the ?（3） ?from a 128kbps circuit to a T1. However, three other components of delay, routing/switching delay, distance delay, and protocol delay are components that can not be positively affected by an ?（4） ?in bandwidth. If the circuits are not over-utilized, then increasing the bandwidth to improve the ?（5） ?of the application will only result in an increased bandwidth with no positive effects on performance.

Amemory

Bcache

Cbandwidth

Ddelay

參考答案：C

5.Serialization delay and ?（1） ?delay are the two components of network delay that are improved by increasing bandwidth. Serialization delay, i.e. the amount of time it takes to put the ?（2） ?on the wire, and queuing delay (depth of the queue) are improved by increasing the ?（3） ?from a 128kbps circuit to a T1. However, three other components of delay, routing/switching delay, distance delay, and protocol delay are components that can not be positively affected by an ?（4） ?in bandwidth. If the circuits are not over-utilized, then increasing the bandwidth to improve the ?（5） ?of the application will only result in an increased bandwidth with no positive effects on performance.

Aelectricity

Bdigital

Cdata

Dvariable

參考答案：C

43[單項(xiàng)選擇題]Information,in its most restricted technical sense,is a seque of symbols that can be interpreted as a message.ingormation can be recorded as signs,or transmitted as（）

Asymbols

Bmessage

Csignals

Dwave

【參考答案】C

【題目解析】信息是用來(lái)代表消息的，可以被標(biāo)記，或者是以信號(hào)的方式傳輸

44[單項(xiàng)選擇題]Risk management allows the project manager and the project team not to（）.

Aeliminate most risks during the planning phase of the project

Bidentify project risks

Cidentify impacts of various risks

Dplan suitable responses

【參考答案】A

【題目解析】下面不屬于風(fēng)險(xiǎn)管理中項(xiàng)目經(jīng)理和項(xiàng)目團(tuán)隊(duì)職責(zé)的是()。
A．排除大部分項(xiàng)目執(zhí)行中的風(fēng)險(xiǎn)?
B．風(fēng)險(xiǎn)識(shí)別
C．風(fēng)險(xiǎn)分析?
D．妥善處理

45[單項(xiàng)選擇題]Observe that for the programmer, as for the chef, the urgency of the patron（顧客）may govern the scheduled completion of the task, but it cannot govern the actual completion.An omelette（煎雞蛋）, promised in two minutes, may appear to be progressing nicely. But when ?it ?has ?not ?set ?in ?two ?minutes, ?the ?customer ?has ?two ?choices—waits ?or ?eats ?it ?raw. Software customers have had ?（1） ?choices.Now I do not think software ?（2） ?have less inherent courage and firmness than chefs, nor than other engineering managers. But false ?（3） ?to match the patron's desired date is much more common in our discipline than elsewhere in engineering. It is very ?（4）to make a vigorous, plausible, and job risking defense of an estimate that is derived by no quantitative method, supported by little data, and certified chiefly by the hunches of the managers.Clearly two solutions are needed. We need to develop and publicize productivity figures, bug-incidence figures, estimating rules, and so on. The whole profession can only profit from ?（5） ?such data. Until estimating is on a sounder basis, individual managers will need to stiffen their backbones and defend their estimates with the assurance that their poor hunches are better than wish derived estimates.

1.Observe that for the programmer, as for the chef, the urgency of the patron（顧客）may govern the scheduled completion of the task, but it cannot govern the actual completion.An omelette（煎雞蛋）, promised in two minutes, may appear to be progressing nicely. But when it has not set in two minutes, the customer has two choices—waits or eats it raw. Software customers have had （1） choices.Now I do not think software （2） have less inherent courage and firmness than chefs, nor than other engineering managers. But false （3） to match the patron's desired date is much more common in our discipline than elsewhere in engineering. It is very （4）to make a vigorous, plausible, and job risking defense of an estimate that is derived by no quantitative method, supported by little data, and certified chiefly by the hunches of the managers.Clearly two solutions are needed. We need to develop and publicize productivity figures, bug-incidence figures, estimating rules, and so on. The whole profession can only profit from （5） such data. Until estimating is on a sounder basis, individual managers will need to stiffen their backbones and defend their estimates with the assurance that their poor hunches are better than wish derived estimates.

Atasks

Bjobs

Cworks

Dscheduling

參考答案：D
解析：觀察一下編程人員，你可能會(huì)發(fā)現(xiàn)，同廚師一樣，某項(xiàng)任務(wù)的計(jì)劃進(jìn)度，可能受限于顧客要求的緊迫程度，但緊迫程度無(wú)法控制實(shí)際的完成情況。就像約好在兩分鐘內(nèi)完成一個(gè)煎蛋，看上去可能進(jìn)行得非常好。但當(dāng)它無(wú)法在兩分鐘內(nèi)完成時(shí)，顧客只能選擇等待或者生吃煎蛋。軟件顧客的情況與此類似。 ? ?
我現(xiàn)在并不認(rèn)為軟件經(jīng)理內(nèi)在的勇氣和堅(jiān)持不如廚師．或者不如其他工程經(jīng)理。但為了滿足顧客期望的日期而造成的不合理進(jìn)度安排，在軟件領(lǐng)域中卻比其他的任何工程領(lǐng)域要普遍得多。而且，非量化方法的采用，少得可憐的數(shù)據(jù)支持，加上完全借助軟件經(jīng)理的直覺，這樣的方式很難生產(chǎn)出健壯可靠和規(guī)避風(fēng)險(xiǎn)的估計(jì)。 ? ?
顯然我們需要兩種解決方案。開發(fā)并推行生產(chǎn)率圖表、缺陷率、估算規(guī)則等等，整個(gè)組織最終會(huì)從這些數(shù)據(jù)的共享上獲益。或者在基于可靠基礎(chǔ)的估算出現(xiàn)之前，項(xiàng)目經(jīng)理需要挺直腰桿并堅(jiān)持他們的估計(jì)，確信自己的經(jīng)驗(yàn)和直覺總比從期望得出的估計(jì)要強(qiáng)得多。

2.Observe that for the programmer, as for the chef, the urgency of the patron（顧客）may govern the scheduled completion of the task, but it cannot govern the actual completion.An omelette（煎雞蛋）, promised in two minutes, may appear to be progressing nicely. But when it has not set in two minutes, the customer has two choices—waits or eats it raw. Software customers have had （1） choices.Now I do not think software （2） have less inherent courage and firmness than chefs, nor than other engineering managers. But false （3） to match the patron's desired date is much more common in our discipline than elsewhere in engineering. It is very （4）to make a vigorous, plausible, and job risking defense of an estimate that is derived by no quantitative method, supported by little data, and certified chiefly by the hunches of the managers.Clearly two solutions are needed. We need to develop and publicize productivity figures, bug-incidence figures, estimating rules, and so on. The whole profession can only profit from （5） such data. Until estimating is on a sounder basis, individual managers will need to stiffen their backbones and defend their estimates with the assurance that their poor hunches are better than wish derived estimates.

Atesters

Bconstructors

Cmanagers

Darchitects

參考答案：C
解析：觀察一下編程人員，你可能會(huì)發(fā)現(xiàn)，同廚師一樣，某項(xiàng)任務(wù)的計(jì)劃進(jìn)度，可能受限于顧客要求的緊迫程度，但緊迫程度無(wú)法控制實(shí)際的完成情況。就像約好在兩分鐘內(nèi)完成一個(gè)煎蛋，看上去可能進(jìn)行得非常好。但當(dāng)它無(wú)法在兩分鐘內(nèi)完成時(shí)，顧客只能選擇等待或者生吃煎蛋。軟件顧客的情況與此類似。 ? ?
我現(xiàn)在并不認(rèn)為軟件經(jīng)理內(nèi)在的勇氣和堅(jiān)持不如廚師．或者不如其他工程經(jīng)理。但為了滿足顧客期望的日期而造成的不合理進(jìn)度安排，在軟件領(lǐng)域中卻比其他的任何工程領(lǐng)域要普遍得多。而且，非量化方法的采用，少得可憐的數(shù)據(jù)支持，加上完全借助軟件經(jīng)理的直覺，這樣的方式很難生產(chǎn)出健壯可靠和規(guī)避風(fēng)險(xiǎn)的估計(jì)。 ? ?
顯然我們需要兩種解決方案。開發(fā)并推行生產(chǎn)率圖表、缺陷率、估算規(guī)則等等，整個(gè)組織最終會(huì)從這些數(shù)據(jù)的共享上獲益。或者在基于可靠基礎(chǔ)的估算出現(xiàn)之前，項(xiàng)目經(jīng)理需要挺直腰桿并堅(jiān)持他們的估計(jì)，確信自己的經(jīng)驗(yàn)和直覺總比從期望得出的估計(jì)要強(qiáng)得多。

Observe that for the programmer, as for the chef, the urgency of the patron（顧客）

may govern the scheduled completion of the task, but it cannot govern the actual completion.

An omelette（煎雞蛋）, promised in two minutes, may appear to be progressing nicely. But

when ?it ?has ?not ?set ?in ?two ?minutes, ?the ?customer ?has ?two ?choices—waits ?or ?eats ?it ?raw. Software customers have had ?（1） ?choices.Now I do not think software ?（2） ?have less inherent courage and firmness than chefs, nor than other engineering managers. But false ?（3） ?to match the patron's desired date is much more common in our discipline than elsewhere in engineering. It is very ?（4）to make a vigorous, plausible, and job risking defense of an estimate that is derived by no quantitative method, supported by little data, and certified chiefly by the hunches of the managers.Clearly two solutions are needed. We need to develop and publicize productivity figures, bug-incidence figures, estimating rules, and so on. The whole profession can only profit from ?（5） ?such data. Until estimating is on a sounder basis, individual managers will need to stiffen their backbones and defend their estimates with the assurance that their poor hunches are better than wish derived estimates.

Ano

Bthe same

Cother

Dlots of

參考答案：B
解析：觀察一下編程人員，你可能會(huì)發(fā)現(xiàn)，同廚師一樣，某項(xiàng)任務(wù)的計(jì)劃進(jìn)度，可能受限于顧客要求的緊迫程度，但緊迫程度無(wú)法控制實(shí)際的完成情況。就像約好在兩分鐘內(nèi)完成一個(gè)煎蛋，看上去可能進(jìn)行得非常好。但當(dāng)它無(wú)法在兩分鐘內(nèi)完成時(shí)，顧客只能選擇等待或者生吃煎蛋。軟件顧客的情況與此類似。 ? ?
我現(xiàn)在并不認(rèn)為軟件經(jīng)理內(nèi)在的勇氣和堅(jiān)持不如廚師．或者不如其他工程經(jīng)理。但為了滿足顧客期望的日期而造成的不合理進(jìn)度安排，在軟件領(lǐng)域中卻比其他的任何工程領(lǐng)域要普遍得多。而且，非量化方法的采用，少得可憐的數(shù)據(jù)支持，加上完全借助軟件經(jīng)理的直覺，這樣的方式很難生產(chǎn)出健壯可靠和規(guī)避風(fēng)險(xiǎn)的估計(jì)。 ? ?
顯然我們需要兩種解決方案。開發(fā)并推行生產(chǎn)率圖表、缺陷率、估算規(guī)則等等，整個(gè)組織最終會(huì)從這些數(shù)據(jù)的共享上獲益。或者在基于可靠基礎(chǔ)的估算出現(xiàn)之前，項(xiàng)目經(jīng)理需要挺直腰桿并堅(jiān)持他們的估計(jì)，確信自己的經(jīng)驗(yàn)和直覺總比從期望得出的估計(jì)要強(qiáng)得多。

4.Observe that for the programmer, as for the chef, the urgency of the patron（顧客）may govern the scheduled completion of the task, but it cannot govern the actual completion.An omelette（煎雞蛋）, promised in two minutes, may appear to be progressing nicely. But when it has not set in two minutes, the customer has two choices—waits or eats it raw. Software customers have had （1） choices.Now I do not think software （2） have less inherent courage and firmness than chefs, nor than other engineering managers. But false （3） to match the patron's desired date is much more common in our discipline than elsewhere in engineering. It is very （4）to make a vigorous, plausible, and job risking defense of an estimate that is derived by no quantitative method, supported by little data, and certified chiefly by the hunches of the managers.Clearly two solutions are needed. We need to develop and publicize productivity figures, bug-incidence figures, estimating rules, and so on. The whole profession can only profit from （5） such data. Until estimating is on a sounder basis, individual managers will need to stiffen their backbones and defend their estimates with the assurance that their poor hunches are better than wish derived estimates.

Aeasy

Bdifficult

Csimple

Dpainless

5.Observe that for the programmer, as for the chef, the urgency of the patron（顧客）may govern the scheduled completion of the task, but it cannot govern the actual completion.An omelette（煎雞蛋）, promised in two minutes, may appear to be progressing nicely. But when it has not set in two minutes, the customer has two choices—waits or eats it raw. Software customers have had （1） choices.Now I do not think software （2） have less inherent courage and firmness than chefs, nor than other engineering managers. But false （3） to match the patron's desired date is much more common in our discipline than elsewhere in engineering. It is very （4）to make a vigorous, plausible, and job risking defense of an estimate that is derived by no quantitative method, supported by little data, and certified chiefly by the hunches of the managers.Clearly two solutions are needed. We need to develop and publicize productivity figures, bug-incidence figures, estimating rules, and so on. The whole profession can only profit from （5） such data. Until estimating is on a sounder basis, individual managers will need to stiffen their backbones and defend their estimates with the assurance that their poor hunches are better than wish derived estimates.

Asharing

Bexcluding

Comitting

Domitting

參考答案：A
解析：觀察一下編程人員，你可能會(huì)發(fā)現(xiàn)，同廚師一樣，某項(xiàng)任務(wù)的計(jì)劃進(jìn)度，可能受限于顧客要求的緊迫程度，但緊迫程度無(wú)法控制實(shí)際的完成情況。就像約好在兩分鐘內(nèi)完成一個(gè)煎蛋，看上去可能進(jìn)行得非常好。但當(dāng)它無(wú)法在兩分鐘內(nèi)完成時(shí)，顧客只能選擇等待或者生吃煎蛋。軟件顧客的情況與此類似。 ? ?
我現(xiàn)在并不認(rèn)為軟件經(jīng)理內(nèi)在的勇氣和堅(jiān)持不如廚師．或者不如其他工程經(jīng)理。但為了滿足顧客期望的日期而造成的不合理進(jìn)度安排，在軟件領(lǐng)域中卻比其他的任何工程領(lǐng)域要普遍得多。而且，非量化方法的采用，少得可憐的數(shù)據(jù)支持，加上完全借助軟件經(jīng)理的直覺，這樣的方式很難生產(chǎn)出健壯可靠和規(guī)避風(fēng)險(xiǎn)的估計(jì)。 ? ?
顯然我們需要兩種解決方案。開發(fā)并推行生產(chǎn)率圖表、缺陷率、估算規(guī)則等等，整個(gè)組織最終會(huì)從這些數(shù)據(jù)的共享上獲益。或者在基于可靠基礎(chǔ)的估算出現(xiàn)之前，項(xiàng)目經(jīng)理需要挺直腰桿并堅(jiān)持他們的估計(jì)，確信自己的經(jīng)驗(yàn)和直覺總比從期望得出的估計(jì)要強(qiáng)得多。

【題目解析】觀察一下編程人員，你可能會(huì)發(fā)現(xiàn)，同廚師一樣，某項(xiàng)任務(wù)的計(jì)劃進(jìn)度，可能受限于顧客要求的緊迫程度，但緊迫程度無(wú)法控制實(shí)際的完成情況。就像約好在兩分鐘內(nèi)完成一個(gè)煎蛋，看上去可能進(jìn)行得非常好。但當(dāng)它無(wú)法在兩分鐘內(nèi)完成時(shí)，顧客只能選擇等待或者生吃煎蛋。軟件顧客的情況與此類似。 ? ?
我現(xiàn)在并不認(rèn)為軟件經(jīng)理內(nèi)在的勇氣和堅(jiān)持不如廚師．或者不如其他工程經(jīng)理。但為了滿足顧客期望的日期而造成的不合理進(jìn)度安排，在軟件領(lǐng)域中卻比其他的任何工程領(lǐng)域要普遍得多。而且，非量化方法的采用，少得可憐的數(shù)據(jù)支持，加上完全借助軟件經(jīng)理的直覺，這樣的方式很難生產(chǎn)出健壯可靠和規(guī)避風(fēng)險(xiǎn)的估計(jì)。 ? ?
顯然我們需要兩種解決方案。開發(fā)并推行生產(chǎn)率圖表、缺陷率、估算規(guī)則等等，整個(gè)組織最終會(huì)從這些數(shù)據(jù)的共享上獲益。或者在基于可靠基礎(chǔ)的估算出現(xiàn)之前，項(xiàng)目經(jīng)理需要挺直腰桿并堅(jiān)持他們的估計(jì)，確信自己的經(jīng)驗(yàn)和直覺總比從期望得出的估計(jì)要強(qiáng)得多。

46[單項(xiàng)選擇題]（）are individuals and organizations that are actively involved in the project, or whose interests may be affected as a result of project execution or project completion; they may also exert influence over the project and its results.

AControls

BBaselines

CProject stakeholders

DProject managers

【參考答案】C

【題目解析】項(xiàng)目干系人是積極參與到項(xiàng)目中，或其利益可能會(huì)受項(xiàng)目執(zhí)行或完成結(jié)果影響的個(gè)人或組織；他們可能會(huì)對(duì)項(xiàng)目及其結(jié)果施加影響。

47[單項(xiàng)選擇題]Your company CEO just sent you an E-mail asking you to make a … on your project , which has been in progress for 10 months , to all Identified internal and external stakeholders. He scheduled the presentation for next Monday.You expect more than 50 people to attend. The first step in preparing the presentation is to ( ).

Adefine the audience

Bdetermine the objective

Cdecide on the general form of the presentation

Dplan a presentation strategy

【參考答案】B

【題目解析】你負(fù)責(zé)的項(xiàng)目已經(jīng)進(jìn)行了10個(gè)月，某天，公司的CEO給你發(fā)了一封電子郵件，要你向所有的、確定的、內(nèi)部和外部的干系人報(bào)告項(xiàng)目當(dāng)前的情況，報(bào)告的時(shí)間定在了下周一，你預(yù)計(jì)可能會(huì)有50多人出席。報(bào)告準(zhǔn)備的第一步是確定目標(biāo)。
A：明確報(bào)告的聽眾
B：確定目標(biāo)
C：確定報(bào)告的總體格式
D：設(shè)計(jì)一個(gè)報(bào)告戰(zhàn)略

48[單項(xiàng)選擇題]Project （） Management includes the processes required to ensure that the project includes all the work required, and only the work required, to complete the project successfully.

AIntegration

BScope

CConfiguration

DRequirement

【參考答案】B

【題目解析】項(xiàng)目范圍管理包括為確保項(xiàng)目包含且僅只包含成功完成項(xiàng)目必須工作的所需過(guò)程。

49[單項(xiàng)選擇題]（） is one of the techniques used for estimating activity durations.

AAnalogous Estimating

BPrecedence Diagramming Method (PDM)

CDependency Determination

DSchedule network Templates

【參考答案】A

【題目解析】下例用于活動(dòng)歷時(shí)估算的技術(shù)是答案A類比估算法。

50[單項(xiàng)選擇題]Most of the host operating system provides a way to automated confgure the IP information needed by a host. Automated configeration methods, such as （） ,are required to solve the problem.

AIPSec

BDHCP

CPPT

DSOAP

【參考答案】B

51[單項(xiàng)選擇題]Which of the following is not part of a modern quality management concept? （）

APerformance standard is zero defects

BQuality must be inspected in

C85% of failures occur because of the process, not the worker

DQuality is a 4 cycle process – plan/do/check/act

【參考答案】B

【題目解析】A.C.D是經(jīng)典質(zhì)量理論，只有B不是。

52[單項(xiàng)選擇題]Software engineers apply the principles of software engineering to the design, development, ( ),testing, and evaluation of the software and systems that make computers or anything containing software work.

ARequirement

Bconstruction

Cservice

Dmaintenance

【參考答案】D

【題目解析】軟件工程師利用軟件工程原理來(lái)設(shè)計(jì)、開發(fā)、（）、測(cè)試、以及評(píng)估軟件和系統(tǒng)。這些軟件好系統(tǒng)使得計(jì)算機(jī)或其他包含軟件的工作能夠正常運(yùn)行。
A、需求
B、建造
C、服務(wù)
D、維護(hù)

53[單項(xiàng)選擇題]The main types of social networking services are those that contain category places (such as former school year or classmates), means to connect with friends (usually with self-description pages), and a recommendation system linked to （）.

Anet

Binterests

Cothers

Dtrust

【參考答案】D

【題目解析】主流類型的社交網(wǎng)絡(luò)通常包含一些諸如校友或同學(xué)等分類的場(chǎng)所，這些朋友通常會(huì)有自我介紹，而且社交網(wǎng)絡(luò)也是一種基于（）關(guān)系的推薦系統(tǒng)
A、網(wǎng)絡(luò)
B、興趣
C、其它
D、信任

54[單項(xiàng)選擇題]Project Time Management includes the processes required to manage timelycompletion of the project, these processes interact with each other. （） isfollowing the process- Estimate Activity Durations.

A、Develop Schedule

BEstimate Activity Resources

CDefine Activities

DSequence Activities

E|*|項(xiàng)目進(jìn)度管理包含多個(gè)項(xiàng)目實(shí)效管理過(guò)程，這些過(guò)程相互彫響.其中緊接活動(dòng).歷時(shí)

【參考答案】E

55[單項(xiàng)選擇題]Traditional Internet access methods like dial-up were so slow that host computers were connected to the dial-up （1） at the customer premise over slow （2） ports. PPP was designed to run directly over these serial links. But with the advent of broadband Internet （3） technologies such as ADSL and cable modems there has been a considerable increase in the bandwidth delivered to the end users. This means that the host computers at the customer premise connect to the （4） or cable “modem” over a much faster medium such as Ethernet. It also means that multiple（5） can be connect to the Internet through the same connection.

1.Traditional Internet access methods like dial-up were so slow that host computers were connected to the dial-up （1） at the customer premise over slow （2） ports. PPP was designed to run directly over these serial links. But with the advent of broadband Internet （3） technologies such as ADSL and cable modems there has been a considerable increase in the bandwidth delivered to the end users. This means that the host computers at the customer premise connect to the （4） or cable “modem” over a much faster medium such as Ethernet. It also means that multiple（5） can be connect to the Internet through the same connection.

Abuffer

Bmodem

Ccomputer ?

Dserver

參考答案：B
解析：像撥接傳統(tǒng)的互聯(lián)網(wǎng)接入方式是如此之慢，主機(jī)均是在客戶端通過(guò)慢速（ 2 ）端口連接到撥號(hào)上網(wǎng)（ 1 ）。購(gòu)買力平價(jià)的目的是直接通過(guò)這些串行鏈路運(yùn)行。但隨著寬帶互聯(lián)網(wǎng)的出現(xiàn)（3）的技術(shù)，如ADSL和電纜調(diào)制解調(diào)器出現(xiàn)了在交付給最終用戶的帶寬大大增加。這意味著，主計(jì)算機(jī)在用戶駐地連接到（4）或電纜“調(diào)制解調(diào)器”過(guò)諸如以太網(wǎng)介質(zhì)中的速度要快得多。這也意味著，多個(gè)（5）可以通過(guò)相同的連接被連接到互聯(lián)網(wǎng)。
（1） A.buffer B.modem C.computer D.server
（2） A.parallel B.digital C.serial D.variable
（3） A.access B.cache C.cast D.storage
（4） A.FDDI B.HDSL C.ADSL D.CDMA
（5） A.cables B.hosts C.servers D.modems

Traditional Internet access methods like dial-up were so slow that host computers were connected to the dial-up ?（1） ?at the customer premise over slow ?（2） ?ports. PPP was designed to run directly over these serial links. But with the advent of broadband Internet ?（3） ?technologies such as ADSL and cable modems there has been a considerable increase in the bandwidth delivered to the end users. This means that the host computers at the customer premise connect to the ?（4） ?or cable?“modem”?over a much faster medium such as Ethernet. It also means that multiple（5） ?can be connect to the Internet through the same connection.

Aaccess

Bcache

Ccast

Dstorage

參考答案：A
解析：像撥接傳統(tǒng)的互聯(lián)網(wǎng)接入方式是如此之慢，主機(jī)均是在客戶端通過(guò)慢速（ 2 ）端口連接到撥號(hào)上網(wǎng)（ 1 ）。購(gòu)買力平價(jià)的目的是直接通過(guò)這些串行鏈路運(yùn)行。但隨著寬帶互聯(lián)網(wǎng)的出現(xiàn)（3）的技術(shù)，如ADSL和電纜調(diào)制解調(diào)器出現(xiàn)了在交付給最終用戶的帶寬大大增加。這意味著，主計(jì)算機(jī)在用戶駐地連接到（4）或電纜“調(diào)制解調(diào)器”過(guò)諸如以太網(wǎng)介質(zhì)中的速度要快得多。這也意味著，多個(gè)（5）可以通過(guò)相同的連接被連接到互聯(lián)網(wǎng)。?
（1） A.buffer B.modem C.computer D.server?
（2） A.parallel B.digital C.serial D.variable?
（3） A.access B.cache C.cast D.storage?
（4） A.FDDI B.HDSL C.ADSL D.CDMA?
（5） A.cables B.hosts C.servers D.modems

AFDDI

BHDSL

CADSL

DCDMA

參考答案：C
解析：像撥接傳統(tǒng)的互聯(lián)網(wǎng)接入方式是如此之慢，主機(jī)均是在客戶端通過(guò)慢速（ 2 ）端口連接到撥號(hào)上網(wǎng)（ 1 ）。購(gòu)買力平價(jià)的目的是直接通過(guò)這些串行鏈路運(yùn)行。但隨著寬帶互聯(lián)網(wǎng)的出現(xiàn)（3）的技術(shù)，如ADSL和電纜調(diào)制解調(diào)器出現(xiàn)了在交付給最終用戶的帶寬大大增加。這意味著，主計(jì)算機(jī)在用戶駐地連接到（4）或電纜“調(diào)制解調(diào)器”過(guò)諸如以太網(wǎng)介質(zhì)中的速度要快得多。這也意味著，多個(gè)（5）可以通過(guò)相同的連接被連接到互聯(lián)網(wǎng)。?
（1） A.buffer B.modem C.computer D.server?
（2） A.parallel B.digital C.serial D.variable?
（3） A.access B.cache C.cast D.storage?
（4） A.FDDI B.HDSL C.ADSL D.CDMA?
（5） A.cables B.hosts C.servers D.modems

Aparallel

Bdigital

Cserial ?

Dvariable

Acables

Bhosts

Cservers

Dmodems

參考答案：B
解析：像撥接傳統(tǒng)的互聯(lián)網(wǎng)接入方式是如此之慢，主機(jī)均是在客戶端通過(guò)慢速（ 2 ）端口連接到撥號(hào)上網(wǎng)（ 1 ）。購(gòu)買力平價(jià)的目的是直接通過(guò)這些串行鏈路運(yùn)行。但隨著寬帶互聯(lián)網(wǎng)的出現(xiàn)（3）的技術(shù)，如ADSL和電纜調(diào)制解調(diào)器出現(xiàn)了在交付給最終用戶的帶寬大大增加。這意味著，主計(jì)算機(jī)在用戶駐地連接到（4）或電纜“調(diào)制解調(diào)器”過(guò)諸如以太網(wǎng)介質(zhì)中的速度要快得多。這也意味著，多個(gè)（5）可以通過(guò)相同的連接被連接到互聯(lián)網(wǎng)。?
（1） A.buffer B.modem C.computer D.server?
（2） A.parallel B.digital C.serial D.variable?
（3） A.access B.cache C.cast D.storage?
（4） A.FDDI B.HDSL C.ADSL D.CDMA?
（5） A.cables B.hosts C.servers D.modems

【題目解析】像撥接傳統(tǒng)的互聯(lián)網(wǎng)接入方式是如此之慢，主機(jī)均是在客戶端通過(guò)慢速（ 2 ）端口連接到撥號(hào)上網(wǎng)（ 1 ）。購(gòu)買力平價(jià)的目的是直接通過(guò)這些串行鏈路運(yùn)行。但隨著寬帶互聯(lián)網(wǎng)的出現(xiàn)（3）的技術(shù)，如ADSL和電纜調(diào)制解調(diào)器出現(xiàn)了在交付給最終用戶的帶寬大大增加。這意味著，主計(jì)算機(jī)在用戶駐地連接到（4）或電纜“調(diào)制解調(diào)器”過(guò)諸如以太網(wǎng)介質(zhì)中的速度要快得多。這也意味著，多個(gè)（5）可以通過(guò)相同的連接被連接到互聯(lián)網(wǎng)。?
（1） A.buffer B.modem C.computer D.server?
（2） A.parallel B.digital C.serial D.variable?
（3） A.access B.cache C.cast D.storage?
（4） A.FDDI B.HDSL C.ADSL D.CDMA?
（5） A.cables B.hosts C.servers D.modems

56[單項(xiàng)選擇題]The earned value technique is a commonly used method of performance measurement. It integrates project scope, schedule, and cost measures to help the project management team assess project performance. If a project's Cost Performance Index(CPI=EV/AC) value less than 1.0, it means that ( )

Athe cost savings for work completed

Bthe project is ahead of its planned schedule

Cthe cost overrun for work completed

Dless work was completed than was planned

【參考答案】C

【題目解析】掙值管理（EVM)是一種常用的績(jī)效測(cè)量方法。它綜合考慮項(xiàng)目范圍、進(jìn)度與成本指標(biāo)，幫助項(xiàng)目管理團(tuán)隊(duì)評(píng)估項(xiàng)目績(jī)效。如果某個(gè)項(xiàng)目的成本績(jī)效指數(shù)（CP1=EV/AC) 值小于1.0,則說(shuō)明已完成的工作的成本超支（the cost overrun for work completed)。

57[單項(xiàng)選擇題]Object-oriented analysis (OOA) is a semiformal specification technique for the object-oriented paradigm. Object-oriented analysis consists of three steps. The first step is（1）. It determines how the various results are computed by the product and presents this information in the form of a （2） and associated scenarios. The second is （3） , which determines the classes and their attributes, then determines the interrelationships and interaction among the classes. The last step is （4） , which determines the actions performed by or to each class or subclass and presents this information in the form of （5） .

Object-oriented ?analysis ?(OOA) ?is ?a ?semiformal ?specification ?technique ?for ?the object-oriented ?paradigm. ?Object-oriented ?analysis ?consists ?of ?three ?steps. ?The ?first ?step ?is（1）. ?It ?determines ?how ?the ?various ?results ?are ?computed ?by ?the ?product ?and ?presents ?this information in the form of a ?（2） ?and associated scenarios. The second is ?（3） ?, which determines the classes and their attributes, then determines the interrelationships and interaction among the classes. The ?last step is ?（4） ?, ?which determines ?the ?actions ?performed ?by or to each class or subclass and presents this information in the form of ?（5） ?.

Ause-case modeling

Bclass modeling

Cdynamic modeling

Dbehavioral modeling

參考答案：A
解析：面向別象的分析〔ooA)是一種面向?qū)ο蠓缎偷陌胄问交枋黾夹g(shù).面向?qū)ο蟮姆治霭?個(gè)步驟：第I步是用例建模。它決定了如何由產(chǎn)品得到各項(xiàng)計(jì)算結(jié)果.并以用例圖和相關(guān)場(chǎng)景的方式展現(xiàn)出來(lái)：笫2步是類建模，它決定了類及其屬性.然后確定類之間的關(guān)系和交互:第3步是動(dòng)態(tài)建模.它決定了類或每個(gè)子類的行為.并以狀態(tài)圖的形式進(jìn)行表示。

（

Ause-case modeling

Bclass modeling

Cdynamic modeling

Dbehavioral modeling

參考答案：B
解析：面向別象的分析〔ooA)是一種面向?qū)ο蠓缎偷陌胄问交枋黾夹g(shù).面向?qū)ο蟮姆治霭?個(gè)步驟：第I步是用例建模。它決定了如何由產(chǎn)品得到各項(xiàng)計(jì)算結(jié)果.并以用例圖和相關(guān)場(chǎng)景的方式展現(xiàn)出來(lái)：笫2步是類建模，它決定了類及其屬性.然后確定類之間的關(guān)系和交互:第3步是動(dòng)態(tài)建模.它決定了類或每個(gè)子類的行為.并以狀態(tài)圖的形式進(jìn)行表示。

Ause-case modeling

Bclass modeling

Cdynamic modeling

Dbehavioral modeling

參考答案：C
解析：面向別象的分析〔ooA)是一種面向?qū)ο蠓缎偷陌胄问交枋黾夹g(shù).面向?qū)ο蟮姆治霭?個(gè)步驟：第I步是用例建模。它決定了如何由產(chǎn)品得到各項(xiàng)計(jì)算結(jié)果.并以用例圖和相關(guān)場(chǎng)景的方式展現(xiàn)出來(lái)：笫2步是類建模，它決定了類及其屬性.然后確定類之間的關(guān)系和交互:第3步是動(dòng)態(tài)建模.它決定了類或每個(gè)子類的行為.并以狀態(tài)圖的形式進(jìn)行表示。

Aactivity diagram

Bcomponent diagram

Csequence diagram

Dstate diagram

參考答案：D
解析：面向別象的分析〔ooA)是一種面向?qū)ο蠓缎偷陌胄问交枋黾夹g(shù).面向?qū)ο蟮姆治霭?個(gè)步驟：第I步是用例建模。它決定了如何由產(chǎn)品得到各項(xiàng)計(jì)算結(jié)果.并以用例圖和相關(guān)場(chǎng)景的方式展現(xiàn)出來(lái)：笫2步是類建模，它決定了類及其屬性.然后確定類之間的關(guān)系和交互:第3步是動(dòng)態(tài)建模.它決定了類或每個(gè)子類的行為.并以狀態(tài)圖的形式進(jìn)行表示。

Acollaboration diagram

Bsequence diagram

Cuse-case diagram

Dactivity diagram

【題目解析】面向別象的分析〔ooA)是一種面向?qū)ο蠓缎偷陌胄问交枋黾夹g(shù).面向?qū)ο蟮姆治霭?個(gè)步驟：第I步是用例建模。它決定了如何由產(chǎn)品得到各項(xiàng)計(jì)算結(jié)果.并以用例圖和相關(guān)場(chǎng)景的方式展現(xiàn)出來(lái)：笫2步是類建模，它決定了類及其屬性.然后確定類之間的關(guān)系和交互:第3步是動(dòng)態(tài)建模.它決定了類或每個(gè)子類的行為.并以狀態(tài)圖的形式進(jìn)行表示。

58[單項(xiàng)選擇題]（）Development is a structured design methodology that proceeds ina sequence from one phase to the next.

AWaterfall

BPhased

CPrototyping

DParallel

【參考答案】A

【題目解析】本題含義可表述為，瀑布摸型是一種結(jié)構(gòu)化設(shè)計(jì)方法，是一個(gè)階段接有一個(gè)階段的順序過(guò)程。所以應(yīng)該選擇A

59[單項(xiàng)選擇題]Perform Quality Control is the process of monitoring and recording results of executing the Quality Plan activities to assess performance and recommend necessary changes．( ) are the techniques and tools in performing quality control．
① Statistical sampling?
②Run chart Perform Quality Control is the process of monitoring and recording results of executing the Quality Plan activities to assess performance and recommend necessary changes．( ) are the techniques and tools in performing quality control．
①Statistical sampling?
②Run chart?
③Control charts
④Critical Path Method?
⑤Pareto chart?
⑥Cause and effect diagrams

A①②③④

B②③④⑤

C①②③⑤⑥

D①③④⑤⑥

【參考答案】C

【題目解析】實(shí)現(xiàn)項(xiàng)目質(zhì)量控制的方法、技術(shù)和工具包括統(tǒng)計(jì)抽樣（statistical sampling）、運(yùn)行圖（Run chart）、控制圖（Control charts）、帕累托圖（Pareto chart）。以及因果圖（Cause and effect diagrams）等。?
關(guān)鍵路徑法（Critical Path Method）是制定項(xiàng)目進(jìn)度計(jì)劃的方法，因此選C.

60[單項(xiàng)選擇題]A project manager is called to an informal meeting with the customer and a problem is raised. This problem has major implications for the project manager’s company, but the customer wants to pursue a solutionat the meeting, The project manager should（）. A．Tell the customer that he will not address any problems

ATell the customer that the problem is not sufficiently defined to company to a solution

BCollect as much information on the problem without committing hiscompany to a solution

CGive the customer a range of solutions that might be acceptable to his company

【參考答案】B

【題目解析】在本題案例中，客戶在與項(xiàng)目經(jīng)理的一次非正式會(huì)議上提出了一個(gè)問(wèn)題，并試圖在會(huì)上獲得問(wèn)題的解決方案。由于這個(gè)問(wèn)題主要牽扯到項(xiàng)目經(jīng)理所在公司，該項(xiàng)目經(jīng)理無(wú)法馬上解決的這一問(wèn)題。這時(shí)，作為項(xiàng)目經(jīng)理，應(yīng)該特別注意與客戶的溝通方式，并采取一定的溝通技巧。
選項(xiàng)A和選項(xiàng)B的做法都屬于簡(jiǎn)單回絕型的應(yīng)對(duì)方式。缺乏經(jīng)驗(yàn)的項(xiàng)目經(jīng)理，在與客戶溝通時(shí)，總會(huì)不自覺地當(dāng)場(chǎng)給客戶一個(gè)“是”或“否”的結(jié)論，這種做法是不恰當(dāng)?shù)?#xff0c;特別是當(dāng)場(chǎng)回絕客戶更不可取。因?yàn)橹苯咏o出結(jié)論型回答，一方面可能會(huì)出現(xiàn)回復(fù)給客戶的結(jié)論不當(dāng)，另一方面也會(huì)讓客尸感覺到?jīng)]有真正用心對(duì)待他們的需求。當(dāng)客戶提出一些難以處理的問(wèn)題時(shí)，一定不能當(dāng)場(chǎng)直接回絕客戶，正確的做法應(yīng)該是先把問(wèn)題記錄下來(lái)，并盡量收集相關(guān)信息，等進(jìn)行仔細(xì)評(píng)估或報(bào)告上級(jí)批準(zhǔn)后再答復(fù)客戶，甚至可以請(qǐng)公司高層與客戶溝通。這樣做既會(huì)讓問(wèn)題得到一個(gè)比較妥善的解決，同時(shí)也會(huì)讓客戶感覺到項(xiàng)目經(jīng)理是一個(gè)做事穩(wěn)健、思維嚴(yán)謹(jǐn)、對(duì)事負(fù)責(zé)的人，從而為以后的合作打好基礎(chǔ)。選項(xiàng)C的處理方式就是這種正確的做法。
而選項(xiàng)D的做法看似合理，但在沒(méi)有充分搞清楚問(wèn)題前所給出這一系列所謂的解決方案將來(lái)能否被公司所接受尚不能確定，而且項(xiàng)目經(jīng)理所給出的這些方案讓用戶選擇，實(shí)際上是把問(wèn)題又拋回給了用戶，并不能真正解決問(wèn)題，反而容易導(dǎo)致和客戶之間進(jìn)一步的糾纏不清，既可能讓用戶感到對(duì)多種選擇無(wú)所適從，又可能在客戶選擇了某項(xiàng)解決方案后，由于項(xiàng)目經(jīng)理的考慮不周而導(dǎo)致將來(lái)喪失在真正解決問(wèn)題時(shí)的靈活主動(dòng)。
因此，根據(jù)上述分析可知，正確答案應(yīng)選C。

61[單項(xiàng)選擇題]he approved change requests have an effect on the project scope, then the corresponding component documents and cost baselines, and（） of the project management plan. Are revised and reissued to reflect the approved changes

Adeveloping baselines

Btesting baselines

Cschedule baselines

Dending baselines

【參考答案】C

【題目解析】如果批準(zhǔn)的變更請(qǐng)求對(duì)項(xiàng)目范圍的影響，那么相應(yīng)的組件文件和成本基線，和（）的項(xiàng)目管理計(jì)劃。修訂再版反映批準(zhǔn)的變更
A、發(fā)展基線
B、測(cè)試基線
C、進(jìn)度基線
D、結(jié)束基線

62[單項(xiàng)選擇題]The Unified Modeling Language is a standard graphical language for modeling object-oriented software．（）can show the behavior of systems in terms of how objects interact with each other．

AClass diagram

BComponent diagram

CSequence diagram

DUse case diagram

【參考答案】C

【題目解析】統(tǒng)一建模語(yǔ)言是為面向?qū)ο筌浖５囊环N標(biāo)準(zhǔn)圖形語(yǔ)言。順序圖可以根據(jù)對(duì)象間如何交互來(lái)展示系統(tǒng)的行為。?
選項(xiàng)A是類圖，選項(xiàng)B是組件圖，選項(xiàng)C是順序圖，選項(xiàng)D是用例圖。

63[單項(xiàng)選擇題]Organizations perform work to achieve a set of objectives. Generally, work can be categorized as either projects or operations, although the two sometimes are （） .

Aconfused

Bsame

Coverlap

Ddissever

【參考答案】C

【題目解析】組織執(zhí)行工作以達(dá)成一組目標(biāo)。通常，工作可被分為項(xiàng)目或是運(yùn)營(yíng)，雖然兩者在某些時(shí)候會(huì)有所重疊。

64[單項(xiàng)選擇題]Routing protocols use different techniques for assigning （1） to individual network. Further, each routing protocol forms a metric aggregation in a different way. Most routing protocols can use multiple paths if the paths has an equal （2） . Some routing protocols can even use multiple paths when paths have an unequal cost. In either case, load （3） can improve overall allocation of network bandwidth. When multiple paths are used, there are several ways to distribute the packets. The two most common mechanisms are per-packet load balancing and per-destination load balancing. Per-packet load balancing distributes the （4） across the possible routes in a manner proportional to the route metrics. Per-destination load balancing distributes packets across the possible routes based on （5） .

（4）destinations ?

Aresources

Bresources

Cpackets

Dpackets

參考答案：C
解析：路由協(xié)議使用各種技術(shù)來(lái)確定到達(dá)不同網(wǎng)絡(luò)的跳數(shù)。此外，每個(gè)路由協(xié)議用不同的方法形成一個(gè)跳數(shù)聚集。大多數(shù)路由協(xié)議可以使用多條路徑，如果它們代價(jià)相等，一些路由協(xié)議甚至可以在路徑代價(jià)不等時(shí)也使用多條路徑。在任何情況下，負(fù)載均衡可以提高整體的網(wǎng)絡(luò)帶寬分配。當(dāng)使用多條路徑時(shí)，有幾種方法分配數(shù)據(jù)包。最常見的兩種機(jī)制是按包負(fù)載平衡和按目的地負(fù)載平衡。按包負(fù)載均衡是按路由跳數(shù)成比例地分配數(shù)據(jù)包。按目的地負(fù)載平衡是基于目的地來(lái)分配數(shù)據(jù)包。

Routing protocols use different techniques for assigning?（1）?to individual network. Further, each routing protocol forms a metric aggregation in a different way. Most routing protocols can use multiple paths if the paths has an equal?（2）?. Some routing protocols can even use multiple paths when paths have an unequal cost. In either case, load?（3）?can improve overall allocation of network bandwidth. When multiple paths are used, there are several ways to distribute the packets. The two most common mechanisms are per-packet load balancing and per-destination load balancing. Per-packet load balancing distributes the?（4）?across the possible routes in a manner proportional to the route metrics. Per-destination load balancing distributes packets across the possible routes based on?（5）?.

Adestinations

Bresources

Cpackets

Dsources

參考答案：A
解析：路由協(xié)議使用各種技術(shù)來(lái)確定到達(dá)不同網(wǎng)絡(luò)的跳數(shù)。此外，每個(gè)路由協(xié)議用不同的方法形成一個(gè)跳數(shù)聚集。大多數(shù)路由協(xié)議可以使用多條路徑，如果它們代價(jià)相等，一些路由協(xié)議甚至可以在路徑代價(jià)不等時(shí)也使用多條路徑。在任何情況下，負(fù)載均衡可以提高整體的網(wǎng)絡(luò)帶寬分配。當(dāng)使用多條路徑時(shí)，有幾種方法分配數(shù)據(jù)包。最常見的兩種機(jī)制是按包負(fù)載平衡和按目的地負(fù)載平衡。按包負(fù)載均衡是按路由跳數(shù)成比例地分配數(shù)據(jù)包。按目的地負(fù)載平衡是基于目的地來(lái)分配數(shù)據(jù)包。

Acalls

Bmetrics

Clinks

Ddestinations

參考答案：B
解析：路由協(xié)議使用各種技術(shù)來(lái)確定到達(dá)不同網(wǎng)絡(luò)的跳數(shù)。此外，每個(gè)路由協(xié)議用不同的方法形成一個(gè)跳數(shù)聚集。大多數(shù)路由協(xié)議可以使用多條路徑，如果它們代價(jià)相等，一些路由協(xié)議甚至可以在路徑代價(jià)不等時(shí)也使用多條路徑。在任何情況下，負(fù)載均衡可以提高整體的網(wǎng)絡(luò)帶寬分配。當(dāng)使用多條路徑時(shí)，有幾種方法分配數(shù)據(jù)包。最常見的兩種機(jī)制是按包負(fù)載平衡和按目的地負(fù)載平衡。按包負(fù)載均衡是按路由跳數(shù)成比例地分配數(shù)據(jù)包。按目的地負(fù)載平衡是基于目的地來(lái)分配數(shù)據(jù)包。

Abracketing

Bbalancing

Cdownloading

Dtransmitting

Auser

Bdistance

Centity

Dcost

參考答案：D
解析：路由協(xié)議使用各種技術(shù)來(lái)確定到達(dá)不同網(wǎng)絡(luò)的跳數(shù)。此外，每個(gè)路由協(xié)議用不同的方法形成一個(gè)跳數(shù)聚集。大多數(shù)路由協(xié)議可以使用多條路徑，如果它們代價(jià)相等，一些路由協(xié)議甚至可以在路徑代價(jià)不等時(shí)也使用多條路徑。在任何情況下，負(fù)載均衡可以提高整體的網(wǎng)絡(luò)帶寬分配。當(dāng)使用多條路徑時(shí)，有幾種方法分配數(shù)據(jù)包。最常見的兩種機(jī)制是按包負(fù)載平衡和按目的地負(fù)載平衡。按包負(fù)載均衡是按路由跳數(shù)成比例地分配數(shù)據(jù)包。按目的地負(fù)載平衡是基于目的地來(lái)分配數(shù)據(jù)包。

【題目解析】路由協(xié)議使用各種技術(shù)來(lái)確定到達(dá)不同網(wǎng)絡(luò)的跳數(shù)。此外，每個(gè)路由協(xié)議用不同的方法形成一個(gè)跳數(shù)聚集。大多數(shù)路由協(xié)議可以使用多條路徑，如果它們代價(jià)相等，一些路由協(xié)議甚至可以在路徑代價(jià)不等時(shí)也使用多條路徑。在任何情況下，負(fù)載均衡可以提高整體的網(wǎng)絡(luò)帶寬分配。當(dāng)使用多條路徑時(shí)，有幾種方法分配數(shù)據(jù)包。最常見的兩種機(jī)制是按包負(fù)載平衡和按目的地負(fù)載平衡。按包負(fù)載均衡是按路由跳數(shù)成比例地分配數(shù)據(jù)包。按目的地負(fù)載平衡是基于目的地來(lái)分配數(shù)據(jù)包。

65[單項(xiàng)選擇題]The network layer provides services to the ( ) layer. It can be based on either virtual circuits or datagrams .In both cases, its main job is routing packets from the source to the destination.

Atransport

Bapplication

Cpresentation

Ddata link

【參考答案】A

【題目解析】網(wǎng)絡(luò)層為傳輸（transport)層提供服務(wù)，它基于虛電路或數(shù)據(jù)報(bào)方式，其主要工作是對(duì)源節(jié)點(diǎn)的數(shù)據(jù)包進(jìn)行路由選擇，轉(zhuǎn)發(fā)到目的節(jié)點(diǎn)。

66[單項(xiàng)選擇題]The software architecture of a program or computing system is the structure or structures of the system, which comprise software( ), the externally visible properties of those components, and the relationships between them.

Apattern

Bmodels

Ccomponents

Dmetadata

【參考答案】C

【題目解析】一個(gè)程序和計(jì)算機(jī)系統(tǒng)軟件體系結(jié)構(gòu)（或軟件架構(gòu)）是指系統(tǒng)的一個(gè)或者多個(gè)結(jié)構(gòu)，結(jié)構(gòu)中包括軟件的構(gòu)件（components)、構(gòu)件的外部可見屬性，以及它們之間的相互關(guān)系。

67[單項(xiàng)選擇題]（）means that every project has a definite beginning and a definite end.

AProject phase

BUnique

C.Temporary

DClosure

【參考答案】C

【題目解析】臨時(shí)性是指每一個(gè)項(xiàng)目都要一個(gè)明確的開始時(shí)間和結(jié)束時(shí)間。

68[單項(xiàng)選擇題]You have just taken control of a project in the middle of execution and need to learn who has approval authority for revisions in scope. ( ) document provides this information.

AResource assignment matrix

BChange control plan

CProject charter

DClient organization chart

【參考答案】B

【題目解析】你剛剛接受了一個(gè)執(zhí)行到中期的項(xiàng)目，你需要了解誰(shuí)負(fù)責(zé)授權(quán)對(duì)項(xiàng)目范圍進(jìn)行修訂。提供這些信息的文檔是（）。
A、資源分配矩陣
B、變更控制計(jì)劃
C、項(xiàng)目章程
D、客戶的組織結(jié)構(gòu)圖

69[單項(xiàng)選擇題]There are strategies typically deal with threats or risk that may have negative impacts on project objectives if they occur, some other strategies are suggested to deal with risks with potentially positive impacts.（） is a risk response strategy that may be adopted for either threats or opportunities.

Ashare

BMitigate

CTransfer

DAcceptance

【參考答案】D

【題目解析】一部分策略用于應(yīng)對(duì)威脅或可能給項(xiàng)目目標(biāo)帶來(lái)消極影響的風(fēng)險(xiǎn)；另一部分策略用于處理對(duì)項(xiàng)目目標(biāo)有潛在積極影響的風(fēng)險(xiǎn)，接受（Acceptance）是一個(gè)既可用來(lái)應(yīng)對(duì)威脅，也可用來(lái)應(yīng)對(duì)機(jī)會(huì)的風(fēng)險(xiǎn)應(yīng)對(duì)策略。?
A選項(xiàng)：風(fēng)險(xiǎn)；B選項(xiàng)：減輕；C選項(xiàng)：轉(zhuǎn)移

70[單項(xiàng)選擇題]（）describes,in detail,the project’s deliverables and the work required to create those deliverables.

AProduct scope description

BProject objectives

CStakeholder Analysis

DThe projects cope statement

【參考答案】D

71[單項(xiàng)選擇題]Precedence Diagramming Method(PDM) is a method used in activity sequencing.There are four types of dependencies or precedence relationships in PDM. The initiation of the successor activity depends upon the completion of the predecessor activity is called （）.

AFinish-to-Start

BFinish-to-Finish

CStart-to-Start

DStart-to-Finish

【參考答案】A

【題目解析】前導(dǎo)圖法（PDM）是用在活動(dòng)排序過(guò)程的技術(shù)之一，PDM包括4種活動(dòng)依賴（或前導(dǎo)）關(guān)系，后續(xù)活動(dòng)的開始依賴于前置活動(dòng)的完成，這稱之為結(jié)束——開始（F-S）的關(guān)系

72[單項(xiàng)選擇題]All Of followings should be done by the project manager during project control except().

ADetermine that a change has occurred

BEnsure thata change is agreed

CMake sure all changes are approved by management

DManage changes as they occur

【參考答案】C

【題目解析】下列中,（）不是項(xiàng)目經(jīng)理在項(xiàng)目控制過(guò)程組要完成的工作。?
A、確定變更已經(jīng)發(fā)生?
B、確保變更被同意?
C、確保所有變更均被管理人員批準(zhǔn)?
D、變更發(fā)生時(shí)對(duì)其進(jìn)行管理?

73[單項(xiàng)選擇題]Circuit-switching technology is used in Publish Switched Telephone Network(PSTN), Global System for Mobile Communications(GSM) and code Division Multiple Access (CMDA) . It is a ( ) information transfer mode.

Aconnection oriented

Bconnectionless

Chigh bandwidth utilization

Dpoor real-time

【參考答案】A

【題目解析】電路交換技術(shù)用戶PSTN、GSM和CDMA，它采用的是面向連接的通信方式。

74[單項(xiàng)選擇題]A schedule is commonly used in project planning and project portfolio management. （） on a schedule may be closely related to the work breakdown structure (WBS)terminal elements, the statement of work, or a contract data requirements list.

AEssences

BElements

CPurposes

DIssues

【參考答案】B

【題目解析】進(jìn)度計(jì)劃經(jīng)常用來(lái)進(jìn)行項(xiàng)目規(guī)劃和項(xiàng)目組合管理。進(jìn)度計(jì)劃的（）與WBS的末端元素、工作說(shuō)明書或者合同數(shù)據(jù)需求列表緊密相關(guān)。
A、本質(zhì)
B、元素
C、目的
D、問(wèn)題

75[單項(xiàng)選擇題]The work breakdown structure comprises several levels of decompositionof the total project. The lowest level of definition is always the（）

APlanning element

BWork package

Csubtask

DWorking ineterface

【參考答案】B

【題目解析】創(chuàng)建工作分解結(jié)構(gòu)是一個(gè)把項(xiàng)目可交付物和項(xiàng)目工作逐步分層分解為更小的、更易于管理的項(xiàng)目單元的過(guò)程，它組織并定義了整個(gè)項(xiàng)目范圍。項(xiàng)目的工作分解結(jié)構(gòu)( Work Breakdown Structure，WBS)是管理項(xiàng)目范圍的基礎(chǔ)，詳細(xì)描述了項(xiàng)目所要完成的工作。WBS的組成元素有助于項(xiàng)目干系人檢查項(xiàng)目的最終產(chǎn)品。WBS的最低層元素是能夠被評(píng)估的、可以安排進(jìn)度的和被追蹤的。
WBS的最底層的工作單元被稱為工作包(Work Package)，它是定義工作范圍、定義項(xiàng)目組織、設(shè)定項(xiàng)目產(chǎn)品的質(zhì)量和規(guī)格、估算和控制費(fèi)用、估算時(shí)間周期和安排進(jìn)度的基礎(chǔ)。
因此，根據(jù)上述內(nèi)容可知，正確答案應(yīng)選B。

76[單項(xiàng)選擇題]hich factors must be most considered when developing acceptance creteria?（）

AMatch with requirements

BUser availability

CAblity to benchmark system

DSchedule of system delivery

【參考答案】A

【題目解析】

77[單項(xiàng)選擇題]ervice (1) Architecture aims to provide a model for the creation of service components in a wide range of languages and a model for assembling service components into a business solution - activities which are at the heart of building applications using a (2) ? architecture.Service Data Objects aims to provide consistent means of handling (3) within applications,whatever its source or (4) may be. SDO provides a way of unifying data handling for databases and for services. SDO also has mechanisms for the handling of data while (5) from its source.

1.ervice (1) Architecture aims to provide a model for the creation of service components in a wide range of languages and a model for assembling service components into a business solution - activities which are at the heart of building applications using a (2) ? architecture.Service Data Objects aims to provide consistent means of handling (3) within applications,whatever its source or (4) may be. SDO provides a way of unifying data handling for databases and for services. SDO also has mechanisms for the handling of data while (5) from its source.

Aconsisted

Bbuilded

Cassembled

Ddetached

參考答案：D
解析：(1)C； (2)B； (3)A： (4)B： (5)D?參考譯文：服務(wù)構(gòu)件架構(gòu)（Service Component Architecture) 致力于為使用廣泛的編程語(yǔ)言來(lái)構(gòu)造服務(wù)構(gòu)件提供一種編程模型，并且也為把這些服務(wù)構(gòu)件組裝為一個(gè)業(yè)務(wù)上的解決方案提供了一種模型，這種組裝的活動(dòng)正是采用面向服務(wù)的架構(gòu)（service-oriented architecture) 來(lái)搭建應(yīng)用系統(tǒng)的核心的.?
服務(wù)數(shù)據(jù)對(duì)象（Service Data Objects)致力于為應(yīng)用系統(tǒng)中處理數(shù)據(jù)（data)提供統(tǒng)一的方式，而不論數(shù)據(jù)的來(lái)源、格式（format)是什么樣的。SDO提供了一種對(duì)數(shù)據(jù)庫(kù)和對(duì)服務(wù)來(lái)說(shuō)統(tǒng)一的數(shù)據(jù)處理方式，它也提供了相應(yīng)的機(jī)制，用來(lái)實(shí)現(xiàn)當(dāng)數(shù)據(jù)同其來(lái)源分離（detached)時(shí)的處理。

2.ervice (1) Architecture aims to provide a model for the creation of service components in a wide range of languages and a model for assembling service components into a business solution - activities which are at the heart of building applications using a (2) ? architecture.Service Data Objects aims to provide consistent means of handling (3) within applications,whatever its source or (4) may be. SDO provides a way of unifying data handling for databases and for services. SDO also has mechanisms for the handling of data while (5) from its source.

Adata

Bcommand

Cappliance

Dcomponent

參考答案：A
解析：(1)C； (2)B； (3)A： (4)B： (5)D?參考譯文：服務(wù)構(gòu)件架構(gòu)（Service Component Architecture) 致力于為使用廣泛的編程語(yǔ)言來(lái)構(gòu)造服務(wù)構(gòu)件提供一種編程模型，并且也為把這些服務(wù)構(gòu)件組裝為一個(gè)業(yè)務(wù)上的解決方案提供了一種模型，這種組裝的活動(dòng)正是采用面向服務(wù)的架構(gòu)（service-oriented architecture) 來(lái)搭建應(yīng)用系統(tǒng)的核心的.?
服務(wù)數(shù)據(jù)對(duì)象（Service Data Objects)致力于為應(yīng)用系統(tǒng)中處理數(shù)據(jù)（data)提供統(tǒng)一的方式，而不論數(shù)據(jù)的來(lái)源、格式（format)是什么樣的。SDO提供了一種對(duì)數(shù)據(jù)庫(kù)和對(duì)服務(wù)來(lái)說(shuō)統(tǒng)一的數(shù)據(jù)處理方式，它也提供了相應(yīng)的機(jī)制，用來(lái)實(shí)現(xiàn)當(dāng)數(shù)據(jù)同其來(lái)源分離（detached)時(shí)的處理。

3.ervice (1) Architecture aims to provide a model for the creation of service components in a wide range of languages and a model for assembling service components into a business solution - activities which are at the heart of building applications using a (2) ? architecture.Service Data Objects aims to provide consistent means of handling (3) within applications,whatever its source or (4) may be. SDO provides a way of unifying data handling for databases and for services. SDO also has mechanisms for the handling of data while (5) from its source.

Alink

Bformat

Cprocedure

Dstructure

參考答案：B
解析：(1)C； (2)B； (3)A： (4)B： (5)D?參考譯文：服務(wù)構(gòu)件架構(gòu)（Service Component Architecture) 致力于為使用廣泛的編程語(yǔ)言來(lái)構(gòu)造服務(wù)構(gòu)件提供一種編程模型，并且也為把這些服務(wù)構(gòu)件組裝為一個(gè)業(yè)務(wù)上的解決方案提供了一種模型，這種組裝的活動(dòng)正是采用面向服務(wù)的架構(gòu)（service-oriented architecture) 來(lái)搭建應(yīng)用系統(tǒng)的核心的.?
服務(wù)數(shù)據(jù)對(duì)象（Service Data Objects)致力于為應(yīng)用系統(tǒng)中處理數(shù)據(jù)（data)提供統(tǒng)一的方式，而不論數(shù)據(jù)的來(lái)源、格式（format)是什么樣的。SDO提供了一種對(duì)數(shù)據(jù)庫(kù)和對(duì)服務(wù)來(lái)說(shuō)統(tǒng)一的數(shù)據(jù)處理方式，它也提供了相應(yīng)的機(jī)制，用來(lái)實(shí)現(xiàn)當(dāng)數(shù)據(jù)同其來(lái)源分離（detached)時(shí)的處理。

4.ervice (1) Architecture aims to provide a model for the creation of service components in a wide range of languages and a model for assembling service components into a business solution - activities which are at the heart of building applications using a (2) ? architecture.Service Data Objects aims to provide consistent means of handling (3) within applications,whatever its source or (4) may be. SDO provides a way of unifying data handling for databases and for services. SDO also has mechanisms for the handling of data while (5) from its source.

Aobject-oriented

Bservice-oriented

Cany

Dparticular

參考答案：B
解析：(1)C； (2)B； (3)A： (4)B： (5)D?參考譯文：服務(wù)構(gòu)件架構(gòu)（Service Component Architecture) 致力于為使用廣泛的編程語(yǔ)言來(lái)構(gòu)造服務(wù)構(gòu)件提供一種編程模型，并且也為把這些服務(wù)構(gòu)件組裝為一個(gè)業(yè)務(wù)上的解決方案提供了一種模型，這種組裝的活動(dòng)正是采用面向服務(wù)的架構(gòu)（service-oriented architecture) 來(lái)搭建應(yīng)用系統(tǒng)的核心的.
服務(wù)數(shù)據(jù)對(duì)象（Service Data Objects)致力于為應(yīng)用系統(tǒng)中處理數(shù)據(jù)（data)提供統(tǒng)一的方式，而不論數(shù)據(jù)的來(lái)源、格式（format)是什么樣的。SDO提供了一種對(duì)數(shù)據(jù)庫(kù)和對(duì)服務(wù)來(lái)說(shuō)統(tǒng)一的數(shù)據(jù)處理方式，它也提供了相應(yīng)的機(jī)制，用來(lái)實(shí)現(xiàn)當(dāng)數(shù)據(jù)同其來(lái)源分離（detached)時(shí)的處理。

5.ervice (1) Architecture aims to provide a model for the creation of service components in a wide range of languages and a model for assembling service components into a business solution - activities which are at the heart of building applications using a (2) ? architecture.Service Data Objects aims to provide consistent means of handling (3) within applications,whatever its source or (4) may be. SDO provides a way of unifying data handling for databases and for services. SDO also has mechanisms for the handling of data while (5) from its source.

AOriented

BLevel

CComponent

DConference

參考答案：C
解析：(1)C； (2)B； (3)A： (4)B： (5)D?參考譯文：服務(wù)構(gòu)件架構(gòu)（Service Component Architecture) 致力于為使用廣泛的編程語(yǔ)言來(lái)構(gòu)造服務(wù)構(gòu)件提供一種編程模型，并且也為把這些服務(wù)構(gòu)件組裝為一個(gè)業(yè)務(wù)上的解決方案提供了一種模型，這種組裝的活動(dòng)正是采用面向服務(wù)的架構(gòu)（service-oriented architecture) 來(lái)搭建應(yīng)用系統(tǒng)的核心的.
服務(wù)數(shù)據(jù)對(duì)象（Service Data Objects)致力于為應(yīng)用系統(tǒng)中處理數(shù)據(jù)（data)提供統(tǒng)一的方式，而不論數(shù)據(jù)的來(lái)源、格式（format)是什么樣的。SDO提供了一種對(duì)數(shù)據(jù)庫(kù)和對(duì)服務(wù)來(lái)說(shuō)統(tǒng)一的數(shù)據(jù)處理方式，它也提供了相應(yīng)的機(jī)制，用來(lái)實(shí)現(xiàn)當(dāng)數(shù)據(jù)同其來(lái)源分離（detached)時(shí)的處理。

【題目解析】(1)C； (2)B； (3)A： (4)B： (5)D?參考譯文：服務(wù)構(gòu)件架構(gòu)（Service Component Architecture) 致力于為使用廣泛的編程語(yǔ)言來(lái)構(gòu)造服務(wù)構(gòu)件提供一種編程模型，并且也為把這些服務(wù)構(gòu)件組裝為一個(gè)業(yè)務(wù)上的解決方案提供了一種模型，這種組裝的活動(dòng)正是采用面向服務(wù)的架構(gòu)（service-oriented architecture) 來(lái)搭建應(yīng)用系統(tǒng)的核心的.?
服務(wù)數(shù)據(jù)對(duì)象（Service Data Objects)致力于為應(yīng)用系統(tǒng)中處理數(shù)據(jù)（data)提供統(tǒng)一的方式，而不論數(shù)據(jù)的來(lái)源、格式（format)是什么樣的。SDO提供了一種對(duì)數(shù)據(jù)庫(kù)和對(duì)服務(wù)來(lái)說(shuō)統(tǒng)一的數(shù)據(jù)處理方式，它也提供了相應(yīng)的機(jī)制，用來(lái)實(shí)現(xiàn)當(dāng)數(shù)據(jù)同其來(lái)源分離（detached)時(shí)的處理。

78[單項(xiàng)選擇題]（）involves comparing actual or planned project practices to those of other projects to generate ideas for improvement and to provide a basis by which to measure performance. These other projects can be within the performing organization or outside of it, and can be within the same or in another application area.

AMetrics

BMeasurement

CBenchmarking

DBaseline

【參考答案】C

【題目解析】基準(zhǔn)分析涉及到將實(shí)際或計(jì)劃的項(xiàng)目實(shí)踐與其他項(xiàng)目進(jìn)行比較，以產(chǎn)生改進(jìn)的思想并提供一個(gè)測(cè)量績(jī)效的基準(zhǔn)。其他項(xiàng)目可以是執(zhí)行組織內(nèi)部的，也可以是外部的，可以是同一個(gè)應(yīng)用領(lǐng)域的，也可以是其他應(yīng)用領(lǐng)域的。

79[單項(xiàng)選擇題]Which of the following elements can be called the key element of a computer? （）

Aprinter

BCPU

Cmouse

Dkeyboard

【參考答案】B

【題目解析】A.C.D是計(jì)算機(jī)的外設(shè)，不是基本元件。

80[單項(xiàng)選擇題]Since RAM is only active when the computer is on, your computer uses diskto store information even when the computer is off. Which of the following istrue? （）

AWhen your computer is on, only RAM is used to store information.

BWhen your computer is on, only disk drives are used to storeinformation.

CWhen your computer is off, only RAM is used to store information.

DWhen your computer is off, only disk drives are used to storeinformation.

【參考答案】D

【題目解析】本題含義可表述為，由于RAN只有當(dāng)計(jì)算機(jī)運(yùn)行時(shí)是工作的，所以當(dāng)計(jì)算機(jī)關(guān)閉時(shí)使用磁盤來(lái)存儲(chǔ)信息。所以應(yīng)該選擇D（當(dāng)計(jì)算機(jī)關(guān)閉后，只有磁盤被用于存儲(chǔ)信息〉。

81[單項(xiàng)選擇題]Networks can be interconnected by different devices. In the physical layer，networks can be connected by（71）or hubs， which just move the bits from one network to an identical network. One layer up we find bridges and switches，which operate at data link layer. They can accept（72），examine the MAC address，and forward the frames to a different network while doing minor protocol translation in the process. In the network layer， we have routers that can connect two networks. If two networks have（73）network layer， the router may be able to translate between the packet formats. In the transport layer we find transport gateway， which can interface between two transport connections. Finally，in the application layer， application gateways translate message （74）. As an example， gateways between Internet e-mail and X.400 e-mail must（75）the e-mail message and change various header fields.

1.Networks can be interconnected by different devices. In the physical layer，networks can be connected by（71）or hubs， which just move the bits from one network to an identical network. One layer up we find bridges and switches，which operate at data link layer. They can accept（72），examine the MAC address，and forward the frames to a different network while doing minor protocol translation in the process. In the network layer， we have routers that can connect two networks. If two networks have（73）network layer， the router may be able to translate between the packet formats. In the transport layer we find transport gateway， which can interface between two transport connections. Finally，in the application layer， application gateways translate message （74）. As an example， gateways between Internet e-mail and X.400 e-mail must（75）the e-mail message and change various header fields.

Areapers

Brelays

Cconnectors

Dmodems

參考答案：A

2.Networks can be interconnected by different devices. In the physical layer，networks can be connected by（71）or hubs， which just move the bits from one network to an identical network. One layer up we find bridges and switches，which operate at data link layer. They can accept（72），examine the MAC address，and forward the frames to a different network while doing minor protocol translation in the process. In the network layer， we have routers that can connect two networks. If two networks have（73）network layer， the router may be able to translate between the packet formats. In the transport layer we find transport gateway， which can interface between two transport connections. Finally，in the application layer， application gateways translate message （74）. As an example， gateways between Internet e-mail and X.400 e-mail must（75）the e-mail message and change various header fields.

Aanalyze

Bparse

Cdelete

Ddelete

參考答案：B

3.Networks can be interconnected by different devices. In the physical layer，networks can be connected by（71）or hubs， which just move the bits from one network to an identical network. One layer up we find bridges and switches，which operate at data link layer. They can accept（72），examine the MAC address，and forward the frames to a different network while doing minor protocol translation in the process. In the network layer， we have routers that can connect two networks. If two networks have（73）network layer， the router may be able to translate between the packet formats. In the transport layer we find transport gateway， which can interface between two transport connections. Finally，in the application layer， application gateways translate message （74）. As an example， gateways between Internet e-mail and X.400 e-mail must（75）the e-mail message and change various header fields.

Aframes

Bpackets

Cpackages

Dcells

參考答案：A

4.Networks can be interconnected by different devices. In the physical layer，networks can be connected by（71）or hubs， which just move the bits from one network to an identical network. One layer up we find bridges and switches，which operate at data link layer. They can accept（72），examine the MAC address，and forward the frames to a different network while doing minor protocol translation in the process. In the network layer， we have routers that can connect two networks. If two networks have（73）network layer， the router may be able to translate between the packet formats. In the transport layer we find transport gateway， which can interface between two transport connections. Finally，in the application layer， application gateways translate message （74）. As an example， gateways between Internet e-mail and X.400 e-mail must（75）the e-mail message and change various header fields.

Aspecial

Bdependent

Csimilar

Ddissimilar

參考答案：D

5.Networks can be interconnected by different devices. In the physical layer，networks can be connected by（71）or hubs， which just move the bits from one network to an identical network. One layer up we find bridges and switches，which operate at data link layer. They can accept（72），examine the MAC address，and forward the frames to a different network while doing minor protocol translation in the process. In the network layer， we have routers that can connect two networks. If two networks have（73）network layer， the router may be able to translate between the packet formats. In the transport layer we find transport gateway， which can interface between two transport connections. Finally，in the application layer， application gateways translate message （74）. As an example， gateways between Internet e-mail and X.400 e-mail must（75）the e-mail message and change various header fields.

Asyntax

Bsemantics

Clanguage

Dformat

參考答案：A

82[單項(xiàng)選擇題]In fixed price contract which of the following holds true? ( )

AMore risk is placed on the buyer.

BIf the amount of the contract is exceeded the seller is not obligated to perform further unless the buyer increases the funds.

CThe seller agrees to perform a service or furnish supplies at the established contract price.

DThe seller agrees to use his best effort to fulfill the contrail within the estimated contract amount.

【參考答案】C

【題目解析】以下關(guān)于固定單價(jià)合同的描述中.正確的是：賣方同意在確定的合同價(jià)格上提供服務(wù)成供應(yīng).

83[單項(xiàng)選擇題]DOM is a platform-and language-(1) API that allows programs and scripts to dynamically access and update the content,structure and style of WWW documents (currently,definitions for HTML and XML documents are part of the specification).The document can be further processed and the results of that processing can be incorporated back into the presented (2) .DOM is a (3) -based API to documents,which requires the whole document to be represented in (4) while processing it.A simpler alternative to DOM is the event-based SAX ,which can be used to process very large (5) documents that do not fit into the memory available for processing.

DOM is a platform-and language-(1) API that allows programs and scripts to dynamically access and update the content,structure and style of WWW documents (currently,definitions for HTML and XML documents are part of the specification).The document can be further processed and the results of that processing can be incorporated back into the presented (2) .DOM is a (3) -based API to documents,which requires the whole document to be represented in (4) while processing it.A simpler alternative to DOM is the event-based SAX ,which can be used to process very large (5) documents that do not fit into the memory available for processing.

Atext

Bimage

Cpage

Dgraphic

參考答案：C
解析：DOM是一種與平臺(tái)和語(yǔ)言無(wú)關(guān)的應(yīng)用程序接口（API），它可以動(dòng)態(tài)地訪問(wèn)程序和腳本，更新其內(nèi)容、結(jié)構(gòu)和WWW文檔的風(fēng)格（目前，HTML和XML文檔是通過(guò)說(shuō)明部分定義的）。文檔可以進(jìn)一步被處理，處理的結(jié)果可以加入到當(dāng)前的頁(yè)面。DOM是一種基于樹的API文檔，它要求在處理過(guò)程中整個(gè)文檔都表示在存儲(chǔ)器中。另外一種簡(jiǎn)單的API是基于事件的SAX，它可以用于處理很大的XML文檔，由于大，所以不適合全部放在存儲(chǔ)器中處理。?

Adocument

Bprocessor

Cdisc

Dmemory

參考答案：D
解析：DOM是一種與平臺(tái)和語(yǔ)言無(wú)關(guān)的應(yīng)用程序接口（API），它可以動(dòng)態(tài)地訪問(wèn)程序和腳本，更新其內(nèi)容、結(jié)構(gòu)和WWW文檔的風(fēng)格（目前，HTML和XML文檔是通過(guò)說(shuō)明部分定義的）。文檔可以進(jìn)一步被處理，處理的結(jié)果可以加入到當(dāng)前的頁(yè)面。DOM是一種基于樹的API文檔，它要求在處理過(guò)程中整個(gè)文檔都表示在存儲(chǔ)器中。另外一種簡(jiǎn)單的API是基于事件的SAX，它可以用于處理很大的XML文檔，由于大，所以不適合全部放在存儲(chǔ)器中處理。?

Atable

Btree

Ccontrol

Devent

參考答案：B
解析：DOM是一種與平臺(tái)和語(yǔ)言無(wú)關(guān)的應(yīng)用程序接口（API），它可以動(dòng)態(tài)地訪問(wèn)程序和腳本，更新其內(nèi)容、結(jié)構(gòu)和WWW文檔的風(fēng)格（目前，HTML和XML文檔是通過(guò)說(shuō)明部分定義的）。文檔可以進(jìn)一步被處理，處理的結(jié)果可以加入到當(dāng)前的頁(yè)面。DOM是一種基于樹的API文檔，它要求在處理過(guò)程中整個(gè)文檔都表示在存儲(chǔ)器中。另外一種簡(jiǎn)單的API是基于事件的SAX，它可以用于處理很大的XML文檔，由于大，所以不適合全部放在存儲(chǔ)器中處理。?

Aspecific

Bneutra

Ccontained

Drelated

AXML

BHTML

Cscript

DWeb

參考答案：A
解析：DOM是一種與平臺(tái)和語(yǔ)言無(wú)關(guān)的應(yīng)用程序接口（API），它可以動(dòng)態(tài)地訪問(wèn)程序和腳本，更新其內(nèi)容、結(jié)構(gòu)和WWW文檔的風(fēng)格（目前，HTML和XML文檔是通過(guò)說(shuō)明部分定義的）。文檔可以進(jìn)一步被處理，處理的結(jié)果可以加入到當(dāng)前的頁(yè)面。DOM是一種基于樹的API文檔，它要求在處理過(guò)程中整個(gè)文檔都表示在存儲(chǔ)器中。另外一種簡(jiǎn)單的API是基于事件的SAX，它可以用于處理很大的XML文檔，由于大，所以不適合全部放在存儲(chǔ)器中處理。?

【題目解析】DOM是一種與平臺(tái)和語(yǔ)言無(wú)關(guān)的應(yīng)用程序接口（API），它可以動(dòng)態(tài)地訪問(wèn)程序和腳本，更新其內(nèi)容、結(jié)構(gòu)和WWW文檔的風(fēng)格（目前，HTML和XML文檔是通過(guò)說(shuō)明部分定義的）。文檔可以進(jìn)一步被處理，處理的結(jié)果可以加入到當(dāng)前的頁(yè)面。DOM是一種基于樹的API文檔，它要求在處理過(guò)程中整個(gè)文檔都表示在存儲(chǔ)器中。另外一種簡(jiǎn)單的API是基于事件的SAX，它可以用于處理很大的XML文檔，由于大，所以不適合全部放在存儲(chǔ)器中處理。

84[單項(xiàng)選擇題]Consumption of the total life-cycle effort in software maintenance is （） that in software development．

Aless than

Blarger than

Cequal or less than

Dequal or larger than

【參考答案】B

【題目解析】本題要表達(dá)的含義是軟件維護(hù)工作在整個(gè)軟件生命周期中所付出的成本、努力要比單純的軟件開發(fā)多?所以應(yīng)該選擇B。

85[單項(xiàng)選擇題]Project （） Management is the Knowledge Area that employs the processes required to ensure timely and appropriate generation, collection, distribution, storage, retrieval, and ultimate disposition of project information.

AIntegration

BTime

CPlanning

DCommunication

【參考答案】D

【題目解析】項(xiàng)目溝通管理是使用所需過(guò)程以確保及時(shí)、恰當(dāng)?shù)禺a(chǎn)生、收集、分發(fā)、存儲(chǔ)、收回和最終處置項(xiàng)目信息的知識(shí)域。

86[單項(xiàng)選擇題]GIF files are limited to a maximum of 8 bits/ I pixel，it simply means that no more than 256 colors are allowed in （） .

Aan image

Ba file

Ca window

Da page

【參考答案】A

【題目解析】GIF格式的文件規(guī)定每個(gè)像素最多8位，這就意味著GIF圖像不能超過(guò)256色。

87[單項(xiàng)選擇題]Which of the following is not part of the quality assurance process? （）

AOperational definitions

BQuality policy

CQuality audits

DQuality improvement

【參考答案】B

【題目解析】A.C.D都是質(zhì)量過(guò)程中重要內(nèi)容，只有B不是。

88[單項(xiàng)選擇題]A milestone is a significant （） in a project.

Aactivity

Bevent

Cphase

Dprocess

【參考答案】B

【題目解析】里程碑是一個(gè)項(xiàng)目中重要的（）。
A.活動(dòng)
B.事件
C.階段
D.過(guò)程

89[單項(xiàng)選擇題]Managing risk and documenting them is very important in project planning process. You are in the process of defining key risks, including constraints and assumptions, and planned responses and contingencies. These details will be included in the（）

Aproject management plan

Bproject baseline

Crisk response plan

Drisk baseline

【參考答案】A

【題目解析】風(fēng)險(xiǎn)相關(guān)的內(nèi)容應(yīng)該在項(xiàng)目管理計(jì)劃中。

90[單項(xiàng)選擇題]An example of scope verification is ( ).

Areview the performance of an installed software module

Bmanaging changes to the project schedule

Cdecomposing the WBS a work package level

Dperforming a benefit/cost analysis to determine if we should proceed with the project

【參考答案】A

【題目解析】范圍驗(yàn)證的一個(gè)示例是（）?
A、查看已安裝的軟件模塊的性能?
B、項(xiàng)目進(jìn)度變更管理?
C、分解到工作包級(jí)別WBS?
D、執(zhí)行成本/效益分析，以確定是否我們應(yīng)該繼續(xù)進(jìn)行項(xiàng)目。?
范圍驗(yàn)證，這一過(guò)程用于正式驗(yàn)收項(xiàng)目的階段成果或項(xiàng)目的最終成果，也叫范圍確認(rèn)，驗(yàn)收的作用就是檢查系統(tǒng)或軟件是否能正常運(yùn)行。

91[單項(xiàng)選擇題]（）is a property of object-oriented software by which an abstract operation may be performed in different ways in different classes．

AMethod

BPolymorphism

CInheritance

DEncapsulation

【參考答案】B

【題目解析】多態(tài)是面向?qū)ο蟮奶卣髦?#xff0c;它提供了一個(gè)抽象操作，在不同的類中能夠執(zhí)行不同的方法。?
選項(xiàng)A是方法，
選項(xiàng)B是多態(tài)，
選項(xiàng)C是繼承，
選項(xiàng)D是封裝

92[單項(xiàng)選擇題]Plan Quality is the process of identifying quality requirements and standards for the project and product, and documenting how the project will demonstrate compliance．（）is a method that analyze all the costs incurred over the life of the product by investment in preventing nonconformance to requirements, appraising the product or service for conformance to requirement, and failing to meet requirements．

ACost-Benefit analysis

BControl charts

CQuality function deployment

DCost of quality analysis

【參考答案】D

【題目解析】質(zhì)量分析成本Cost of quality analysis是對(duì)產(chǎn)品或服務(wù)進(jìn)行需求一致性分析所產(chǎn)生的成本；
成本效益分析Cost-Benefit analysi是通過(guò)比較項(xiàng)目的全部成本和效益來(lái)評(píng)估項(xiàng)目?jī)r(jià)值的一種方法；
控制圖Control charts是項(xiàng)目質(zhì)量控制方法；
質(zhì)量功能展開Quality function deployment是把顧客或市場(chǎng)的要求轉(zhuǎn)化為設(shè)計(jì)要求、零部件特性、工藝要求、生產(chǎn)要求的多層次演繹分析方法
因此，因此選D

93[單項(xiàng)選擇題]（）is responsible for the attraction, selection, training, assessment, and rewarding of employees, while also overseeing organizational leadership and culture, and ensuring compliance with employment and labor laws.

AHuman resource management

BStrategic analysis

CTeam management

DRACI

【參考答案】A

【題目解析】（）用來(lái)吸引、選擇、培訓(xùn)、考核以及獎(jiǎng)勵(lì)員工，同時(shí)負(fù)責(zé)組織領(lǐng)導(dǎo)和企業(yè)文化，并確保組織遵守相關(guān)雇傭和勞動(dòng)法。
A. 人力資源管理
B. 策略分析
C. 團(tuán)隊(duì)建設(shè)
D. RACI
RACI：是一個(gè)相對(duì)直觀的模型，用以明確組織變革過(guò)程中的各個(gè)角色及其相關(guān)責(zé)任。

94[單項(xiàng)選擇題]As an operating system repeatedly allocates and frees storage space, many physicallyseparated unused areas appear. This phenomenon is called （） .

Afragmentation

Bcompaction

Cswapping

Dpaging

【參考答案】A

【題目解析】隨著操作系統(tǒng)反復(fù)分配與釋放存儲(chǔ)空間，就會(huì)出現(xiàn)許多不連續(xù)的未用物理區(qū)域，這種現(xiàn)象稱為碎片。

95[單項(xiàng)選擇題]Workarounds are determined during which risk management process?（）。

ARisk identification

BQuantitative risk analysis

CPlan risk responses

DRisk monitoring and control

【參考答案】D

【題目解析】風(fēng)險(xiǎn)管理過(guò)程的解決方法??
A、風(fēng)險(xiǎn)識(shí)別?
B、定量風(fēng)險(xiǎn)分析;?
C、規(guī)劃風(fēng)險(xiǎn)應(yīng)對(duì)?
D、風(fēng)險(xiǎn)監(jiān)測(cè)與控制

96[單項(xiàng)選擇題]The（） has several major components, including the system kernel, a memory management system, the file system manager, device drivers, and the system libraries.

Aapplication

Binformation system

Coperating system

Diterative

【參考答案】C

【題目解析】本題考操作系統(tǒng)的管理要素。

97[單項(xiàng)選擇題]Ethernet is the commonly used local area network communication protocol. The standard of Ethernet is （）.

AIEEE 802.1

BIEEE 802.2

CIEEE 802.3

DIEEE 802.11

【參考答案】C

【題目解析】以太網(wǎng)是一種常用的局域網(wǎng)通信協(xié)議網(wǎng)絡(luò)，以太網(wǎng)遵循()標(biāo)準(zhǔn)。

98[單項(xiàng)選擇題]”Cost of quality ” is a project management concept that includes cost of ( ).

Aexceedings requirements

BChanged to the requirements

CEnsuring conformance to requirements

DThe quality control requirements

【參考答案】C

99[單項(xiàng)選擇題]Configuration management is the process of managing change in hardware,software, firmware, documentation, measurements, etc. As change requires aninitial state and next state, the marking of significant states within a seriesof several changes becomes important. The identification of significant stateswithin the revision history of a configuration item is the central purpose of（） identification.

Abaseline

Bvalue

Ccost

Dcontrol

【參考答案】A

【題目解析】配置管理是在硬件、軟件、固件、文件、測(cè)量等的過(guò)程管理的變化，作為變化需要有一個(gè)初始狀態(tài)和下一個(gè)狀態(tài)，標(biāo)識(shí)上一狀態(tài)變化非常重要，配置項(xiàng)目需確定重要狀態(tài)的修訂歷史記錄，主要目的是基線的確定。

100[單項(xiàng)選擇題]Your project is behind schedule due to conflict between team members .Haring resolved the conflict, to get the project back on schedule，you should consider （）.

Acrashing the Schedule

Bperforming resource leveling

Cconducting reverse resource allocation Scheduling

Dutilizing the critical chair resources

【參考答案】A

【題目解析】由于團(tuán)隊(duì)成員之間的沖突，造成了項(xiàng)目進(jìn)度落后于計(jì)劃，為了解決沖突以使得項(xiàng)目如期完成，你應(yīng)該考慮（）?
A、重新安排時(shí)間表?
B、執(zhí)行資源調(diào)配?
C、進(jìn)行反向資源分配調(diào)度?
D、利用關(guān)鍵的主要資源

101[單項(xiàng)選擇題]（） is one of the quality planning outputs.

AScope base line

BCost of quality

CProduct specification

DQuality checklist

【參考答案】D

102[單項(xiàng)選擇題]A 10BaseT Ethernet LAN has ( ).

Aa star topology

Bb ring topology

Ca bus topology

Da linear topology

【參考答案】A

【題目解析】本題的含義是：10Baset以太網(wǎng)絡(luò)是星型結(jié)構(gòu)的，選擇答案A正確

103[單項(xiàng)選擇題]The（）defines the phases that connect the beginning of a project to its end.

Aschedule

Bproject life cycle

Ctemporary

Dmilestone

【參考答案】B

【題目解析】項(xiàng)目生命周期定義了從項(xiàng)目開始直至結(jié)束的項(xiàng)目階段

104[單項(xiàng)選擇題]In the project management context, （） includes characteristics of unification, consolidation, articulation, and integrative actions that are crucial to project completion, successfully meeting customer and other stakeholder requirements, and managing expectations.

Aintegration

Bscope

Cprocess

Dcharter

【參考答案】A

【題目解析】在項(xiàng)目管理語(yǔ)境中，“整體”包含了統(tǒng)一、合并、聯(lián)接的特性，以及對(duì)于完成項(xiàng)目、成功滿足顧客和其他干系人的需求及管理期望至關(guān)重要的整體行動(dòng)

105[單項(xiàng)選擇題]Cloud-computing providers offer their “services” according to different models, which happen to form a stack（）, platform as a service (Paas), software as a service (SaaS)

Ahardware as a service (Haas)

Bnetwork as a service (NaaS)

Cinfrastructure as a service (IaaS)

Ddata as a service (DaaS)

【參考答案】C

【題目解析】云計(jì)算供應(yīng)商提供他們的“服務(wù)”，根據(jù)不同的類型，恰好形成（），平臺(tái)即服務(wù)（PaaS），軟件即服務(wù)（SaaS）
A、硬件即服務(wù)（HAAS）
B、網(wǎng)絡(luò)作為一種服務(wù)（NAAS）
C、基礎(chǔ)設(shè)施即服務(wù)（IaaS）
D、數(shù)據(jù)即服務(wù)（DaaS）

106[單項(xiàng)選擇題]The ( ) provides the project manager with the authority to apply organizational resources to project activities。

Aproject management plan

Bproject charter

Cproject human resource plan

Dproject stakeholders

【參考答案】B

【題目解析】項(xiàng)程（project charier)為項(xiàng)目經(jīng)理使用組織資源進(jìn)行項(xiàng)目活動(dòng)提供了授權(quán)。

107[單項(xiàng)選擇題]Maintenance activities do not include ( ).

Amaking enhancements to software products

Bdeveloping a new software product

Ccorrecting problems

Dadapting products to new environments

【參考答案】B

【題目解析】維護(hù)活動(dòng)不包括（）。
A、增強(qiáng)軟件產(chǎn)品
B、開發(fā)一個(gè)新的軟件產(chǎn)品
C、糾正問(wèn)題
D、調(diào)整產(chǎn)品新環(huán)境

108[單項(xiàng)選擇題]Project selection methods involve measuring value or attractiveness to the project owner or sponsor and may include other organizational decision criteria. （）is not a project selection method.

ABenefit contribution

BExpert judgment

CScoring models

DFlow charting

【參考答案】D

【題目解析】項(xiàng)目選擇方法包括測(cè)量項(xiàng)目業(yè)主的價(jià)值和吸引力，并可能包括組織層面其他決策準(zhǔn)則。流程圖（Flow charting）不是一個(gè)項(xiàng)目選擇方法。?
A選項(xiàng)是收益分析，B選項(xiàng)是專家判斷，C選項(xiàng)是平分模型，D選項(xiàng)是流程圖

109[單項(xiàng)選擇題]（）is a method used in Critical Path Methodology for constructing a project schedule network diagram that uses boxes or rectangles, referred to as nodes, to represent activities and connects them with arrows that show the logical relationships that exist between them.

APERT

BAOA

CWBS

DPDM

【參考答案】D

【題目解析】（）用于關(guān)鍵路徑法，是用于編制項(xiàng)目進(jìn)度網(wǎng)絡(luò)圖的一種方法，它使用方框或
者長(zhǎng)方形（被稱作節(jié)點(diǎn)）代表活動(dòng)，它們之間用箭頭連接，顯示彼此之問(wèn)存在的邏輯
關(guān)系。?

110[單項(xiàng)選擇題]The connection between two networks to form an internet is handled bya machine known as a （） .

Abridge

Bclient

Crouter

Dswitch

【參考答案】C

【題目解析】答案C路由，是用來(lái)鏈接兩個(gè)網(wǎng)絡(luò)，并使現(xiàn)實(shí)互聯(lián)的設(shè)備。

111[單項(xiàng)選擇題]Quality managenent ( ).

Ais another name for careful inspections

Bis inversely related to productivity

Cis primarily the responsibility of management

Dis primaritily the responsibility of the workers

【參考答案】C

【題目解析】質(zhì)量管理主要是管理的責(zé)任

112[單項(xiàng)選擇題]Risk management’s ( ) is to assure uncertainty does not deflect the endeavor from the business goals

Atrend

Bdetail

Cobjective

Drule

【參考答案】C

【題目解析】風(fēng)險(xiǎn)管理的（）是為了保證不確定不偏離經(jīng)營(yíng)目標(biāo)的努力
A、趨勢(shì)
B、詳述
C、目標(biāo)
D、規(guī)則

113[單項(xiàng)選擇題]（）are the four major activities of software configuration management.

Aonfiguration identification ②statement report ③change control

Breparation of requirement document ⑤configuration auditing

C①②③④

D①②④⑤

E①②③⑤

F②③④⑤

【參考答案】E

【題目解析】較件配置管理的4個(gè)主要活動(dòng)是()。
①配置識(shí)別 ②狀態(tài)報(bào)告 ③變更控制 ④準(zhǔn)備需求文檔 ⑤配置審計(jì)
A①②③④ B.①②④⑤ C.①②③⑤D.②⑧④⑤
根據(jù)《系統(tǒng)集成項(xiàng)目管理工程師教程》（全國(guó)計(jì)算機(jī)專業(yè)技術(shù)資格考試辦公室組編）第15 2節(jié)的內(nèi)容可知，軟件配置管理包括4個(gè)主要活動(dòng)：配置識(shí)別、變更控制、狀態(tài)報(bào)告和配置審計(jì)。
因此，正確答案應(yīng)選C。

114[單項(xiàng)選擇題]Which statement about the preliminary design stage of a software development project is true? （） .

AThe preliminary design is an internal document used only by programmers

BThe preliminary design is the result of mapping product requirements info software and hardware functions

CThe preliminary design of the product comes from the requirement specification

DThe developers produce the preliminary design by defining the software structure in enough detail to permit coding

【參考答案】C

【題目解析】下面關(guān)于軟件開發(fā)項(xiàng)目初步設(shè)計(jì)階段的描述，正確的是：
A．初步設(shè)計(jì)是供編碼人員使用的內(nèi)部文檔
B．初步設(shè)計(jì)是產(chǎn)品需求到軟硬件功能的映射
C．產(chǎn)品概要設(shè)計(jì)來(lái)源于需求規(guī)格說(shuō)明
D．開發(fā)人員在進(jìn)行初步設(shè)計(jì)時(shí)，對(duì)軟件結(jié)構(gòu)描述細(xì)致到可以指導(dǎo)編碼的程度

115[單項(xiàng)選擇題]The standard (IEEE 802) format for printing （） in human-friendly formis six groups of two hexadecimal digits, separated by hyphens (-) or colons (:),in transmission order, e.g. 01-23-45-67-89-ab, 01:23:45:67:89:ab. This form isalso commonly used for EUI-64.

Ahard disk logical block address

BIP address

Cmail address

DMAC address

【參考答案】D

【題目解析】標(biāo)準(zhǔn)IEEE 802中，MAC地址輸入的格式是6組兩個(gè)十六進(jìn)制數(shù)字，分隔的連字符用(-)或冒號(hào)(:)，例如 01-23-45-67-89-ab、01:23:45:67:89:ab，這種形式也常用于 EUI-64標(biāo)識(shí)。

116[單項(xiàng)選擇題]In the （） phase team members begin to work together and adjust their work habits and behaviors to support the team. The team learns to trust each other

Astorming

Bperforming

Cnorming

Dadjourning

【參考答案】C

【題目解析】在（）階段，團(tuán)隊(duì)成員開始一起協(xié)調(diào)工作并調(diào)整他們的工作習(xí)慣和行為來(lái)支持團(tuán)隊(duì)工作。團(tuán)隊(duì)開始學(xué)會(huì)相互信任
A、風(fēng)暴
B、表現(xiàn)
C、規(guī)范
D、解散

117[單項(xiàng)選擇題]To determine whether or not the employee correctly understands the message, the project manger needs to （）

Areduce the filtering

Beliminate barriers

Cobtain feedback

Duse more than one medium

【參考答案】C

【題目解析】要確定是否正確地理解員工信息，項(xiàng)目經(jīng)理需要（）

118[單項(xiàng)選擇題]A ( ) is a dedicated storage network that provides access to consolidated,block level storage.It is primarily used to mark storage devices accessible to servers so that the devices appear as locally attached to the operating system.

Anetwork-attached storage

Bstorge area network

Cdirect attached storage

Dcomputer cluster

【參考答案】B

【題目解析】存儲(chǔ)區(qū)域網(wǎng)絡(luò)（storge area network，SAN）是一個(gè)專用的存儲(chǔ)網(wǎng)絡(luò)，提供綜合、塊級(jí)存儲(chǔ)的訪問(wèn)。它主要用來(lái)連接網(wǎng)絡(luò)服務(wù)器和存儲(chǔ)設(shè)備，使存儲(chǔ)設(shè)備出現(xiàn)在操作系統(tǒng)本地磁盤盤符中

119[單項(xiàng)選擇題]（） from one phase are usually reviewed for completeness and accuracy and approved before work starts on the next phase.

AProcess

BMilestone

CWork

DDeliverables

【參考答案】D

【題目解析】一個(gè)階段所產(chǎn)生的可交付物通常要在開始下一階段的工作之前對(duì)其完備性和正確性進(jìn)行評(píng)審并獲得批準(zhǔn)。

120[單項(xiàng)選擇題]Project schedule management is made up of six management processes including:activity definition, activity sequencing,（） , and schedule control by order．

Aactivity duration estimating, schedule developing, activity resource estimating

B.activity resource estimating, activity duration estimating, schedule development

Cschedule developing, activity resource estimating, activity duration estimating

Dactivity resource estimating, schedule developing, activity duration estimating

【參考答案】B

【題目解析】項(xiàng)目時(shí)間管理包括使項(xiàng)目按時(shí)完成所必需的管理過(guò)程。進(jìn)度安排的準(zhǔn)確程度可能比成本估計(jì)的準(zhǔn)確程度更重要。考慮進(jìn)度安排時(shí)要把人員的工作量與花費(fèi)的時(shí)間聯(lián)系起來(lái)，合理分配工作量，利用進(jìn)度安排的有效分析方法來(lái)嚴(yán)格監(jiān)視項(xiàng)目的進(jìn)展情況，以使得項(xiàng)目的進(jìn)度不致被拖延。
項(xiàng)目時(shí)間管理過(guò)程包括：活動(dòng)定義、活動(dòng)排序、活動(dòng)的資源估算、活動(dòng)歷史估算、制定進(jìn)度計(jì)劃及進(jìn)度控制六個(gè)步驟。
以上六個(gè)步驟具有先后順序，因此選擇“活動(dòng)的資源估算”activity resource estimating、“活動(dòng)歷史估算”activity duration estimating、制定進(jìn)度計(jì)劃schedule development，所以選B。

121[單項(xiàng)選擇題]The project budget has been finalized.Additional work has been discovered that was not planned for in the budget or project scope. （）could provide the fund to cover the newly discovered work item.

AContingency reserve

BClass diagram

CComponent diagram

DSequence diagram

EUse case diagram

【參考答案】D

【題目解析】統(tǒng)一建模語(yǔ)言（UML)是一種通用的、可視化的面向?qū)ο筌浖膱D形語(yǔ)言。序列圖(Sequence diagram)用于展現(xiàn)一組對(duì)象如何互相交流消息方面的系統(tǒng)行為。

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