??? 題意是求倆字符串的編輯距離，編輯定義有三種1、插入字符 2、刪除字符 3、替換字符。

int minDistance(string word1, string word2) 

{

    if (word1.size() == 0) return (int)word2.size();

    if (word2.size() == 0) return (int)word1.size();

    int result = 0;

    int *dist = new int[(word1.size() + 1) * (word2.size() + 1)];

    for (size_t i = 0; i <= word1.size(); ++i)

    {

        dist[i] = (int)i;

    }

    for (size_t j = 0; j <= word2.size(); ++j)

    {

        dist[j * word1.size()] = (int)j;

    }

    for (size_t i = 1; i <= word1.size(); ++i)

    {

        for (size_t j = 1; j <= word2.size(); ++j)

        {

            if (word1[i - 1] == word2[j - 1])

            {

                // dist[i, j] = dist[i - 1, j - 1]

                dist[j * word1.size() + i] = 

                        dist[(j - 1) * word1.size() + i - 1];

            }

            else

            {

                // minDist = min(dist[i - 1, j], dist[i, j - 1])

                const int minDist = min(

                        dist[j * word1.size() + (i - 1)],

                        dist[(j - 1) * word1.size() + i]);

                // dist[i, j] = min(minDist, dist[i - 1, j - 1]) + 1

                dist[j * word1.size() + i] = min(minDist,

                        dist[(j - 1) * word1.size() + i - 1]) + 1;

            }

        }

    }

    result = dist[word2.size() * word1.size() + word1.size()];

    delete[] dist;

    return result;

}

轉載于:https://www.cnblogs.com/codingmylife/archive/2012/09/09/2677301.html

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