有N個葉子的草

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vertices = 1000
t = from 0 to (2*PI)
r = 10
n = rand_int2(3, 10)
p = 1 + cos(n*t) + sin(n*t)^2
x = p*cos(t)
y = p*sin(t)

N葉草面_1

vertices = D1:512 D2:100u = from 0 to (PI*2) D1
v = from 0.0 to 1.0 D2r = 10
n = rand_int2(3, 10)
p = 1 + v*cos(n*u) + sin(n*u)^2x = p*cos(u)
y = p*sin(u)

N葉草面_2

vertices = D1:512 D2:100u = from 0 to (PI*2) D1
v = from 0.0 to 4.0 D2r = 10
n = rand_int2(3, 10)
p = 1 + cos(n*u) + sin(n*u)^2*vx = p*cos(u)
y = p*sin(u)

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轉載于:https://www.cnblogs.com/WhyEngine/p/3831164.html

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