Oracle 主從表聯合查詢

表A

id???type???name

1????E??????AA

2????F

表B

id???Aid????name

1????2??????BB

2????2??????CC

表B?是表A的子表

如果表A中的type是F，就需要根據Aid?去表B里找對應的name，然后拼接起來

數據庫是Oracle10G?需要查詢的結果：

Aid?????type?????name

1???????E????????AA

2???????F????????BB,CC

------解決方案--------------------

with?a?as(

select?1?id,'E'?type,'AA'?name?from?dual

union?all

select?2,'F',null?from?dual

),b?as(

select?1?id,?2?aid,?'BB'?name?from?dual

union?all

select?2,2,'CC'?from?dual

)

select?a.id,?a.type,?wm_concat(nvl(a.name,?b.name))

from?a,?b

where?a.id?=?b.aid(+)

group?by?a.id,?a.type;

ID?TYPE?WM_CONCAT(NVL(A.NAME,B.NAME))

----------?----?--------------------------------------------

1?E????AA

2?F????BB,CC

------解決方案--------------------

WITH?TABLE1?AS(

SELECT?'1'?AS?Aid,?'E'?AS?type,'AA'?as?name?FROM?dual

union?all

SELECT?'2'?AS?Aid,?'F'?AS?type,''?as?name?FROM?dual

union?all

SELECT?'3'?AS?Aid,?'F'?AS?type,''?as?name?FROM?dual

union?all

SELECT?'4'?AS?Aid,?'A'?AS?type,'FF'?as?name?FROM?dual

),

TABLE2?AS?(

SELECT?'1'?AS?id,?'2'?AS?Aid,'BB'?as?name?FROM?dual

union?all

SELECT?'2'?AS?id,?'2'?AS?Aid,'CC'?as?name?FROM?dual

union?all

SELECT?'3'?AS?id,?'3'?AS?Aid,'DD'?as?name?FROM?dual

union?all

SELECT?'4'?AS?id,?'3'?AS?Aid,'EE'?as?name?FROM?dual

)

SELECT?T1.Aid,

T1.TYPE,

LISTAGG(nvl(T1.NAME,?T2.NAME),',')WITHIN?GROUP(ORDER?BY?id)?AS?NAME

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