在正常的業務邏輯中,對客戶的分析是必須的也是最經常用到的,根據時間維度計算計算指標連續兩月環比情況也是一道必須面對的題目。

國慶放假 先寫代碼 后面再拆分解釋

SELECT a.*,b.年月 AS 上月,b.金額 AS 上月金額,(a.金額-b.金額) AS 金額較上月增長
FROM (SELECT a2.*,(@i:=@i+1) AS ID1FROM (SELECT a1.city AS 城市,username AS 用戶ID,DATE_FORMAT(a1.order_date,"%Y%m") AS 年月,SUM(a1.pay_money) AS 金額,LAST_DAY(order_date) AS 月最后一天FROM `test_a03order` AS a1WHERE a1.pay_money >0GROUP BY a1.city,a1.username,DATE_FORMAT(a1.order_date,"%Y%m")) AS a2,(SELECT @i:=0) AS it1 #ID1從1自增長
) AS a
LEFT JOIN (#和上面代碼一樣 無非是ID一個從1 一個從2  通過ID相等 把所有數據記錄下沉一行SELECT b2.*,(@j:=@j+1) AS ID2FROM (SELECT b1.city AS 城市,username AS 用戶ID,DATE_FORMAT(b1.order_date,"%Y%m") AS 年月,SUM(b1.pay_money) AS 金額,LAST_DAY(order_date) AS 月最后一天FROM `test_a03order` AS b1WHERE b1.pay_money >0GROUP BY b1.city,b1.username,DATE_FORMAT(b1.order_date,"%Y%m")) AS b2,(SELECT @j:=1) AS it2#ID2從2自增長
) AS b ON a.ID1=b.ID2 AND a.用戶ID=b.用戶ID AND PERIOD_DIFF(DATE_FORMAT(a.月最后一天,"%Y%m"),DATE_FORMAT(b.月最后一天,"%Y%m"))=1#同一用戶相連兩月金額保持在一行

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轉載于:https://www.cnblogs.com/Mr-Cxy/p/5919212.html

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