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【Opencv】直方图函数 calchist()

發(fā)布時間:2023/11/27 生活经验 38 豆豆
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calchist函數(shù)需要包含頭文件

#include <opencv2/imgproc/imgproc.hpp>

函數(shù)聲明(三個重載 calchist函數(shù)):

//! computes the joint dense histogram for a set of images.
CV_EXPORTS void calcHist( const Mat* images, int nimages,const int* channels, InputArray mask,OutputArray hist, int dims, const int* histSize,const float** ranges, bool uniform=true, bool accumulate=false );//! computes the joint sparse histogram for a set of images.
CV_EXPORTS void calcHist( const Mat* images, int nimages,const int* channels, InputArray mask,SparseMat& hist, int dims,const int* histSize, const float** ranges,bool uniform=true, bool accumulate=false );CV_EXPORTS_W void calcHist( InputArrayOfArrays images,const vector<int>& channels,InputArray mask, OutputArray hist,const vector<int>& histSize,const vector<float>& ranges,bool accumulate=false );

官方文檔:

The functions?calcHist?calculate the histogram of one or more arrays. The elements of a tuple used to increment a histogram bin are taken from the corresponding input arrays at the same location. The sample below shows how to compute a 2D Hue-Saturation histogram for a color image.

Parameters:
  • images?– Source arrays. They all should have the same depth,?CV_8U?or?CV_32F?, and the same size. Each of them can have an arbitrary number of channels.
  • nimages?– Number of source images.
  • channels?– List of the?dims?channels used to compute the histogram. The first array channels are numerated from 0 to?images[0].channels()-1?, the second array channels are counted from?images[0].channels()?to?images[0].channels()?+?images[1].channels()-1, and so on.
  • mask?– Optional mask. If the matrix is not empty, it must be an 8-bit array of the same size as?images[i]?. The non-zero mask elements mark the array elements counted in the histogram.
  • hist?– Output histogram, which is a dense or sparse?dims?-dimensional array.
  • dims?– Histogram dimensionality that must be positive and not greater than?CV_MAX_DIMS?(equal to 32 in the current OpenCV version).
  • histSize?– Array of histogram sizes in each dimension.
  • ranges?– Array of the?dims?arrays of the histogram bin boundaries in each dimension. When the histogram is uniform (?uniform?=true), then for each dimension?i?it is enough to specify the lower (inclusive) boundary??of the 0-th histogram bin and the upper (exclusive) boundary??for the last histogram bin?histSize[i]-1?. That is, in case of a uniform histogram each of?ranges[i]?is an array of 2 elements. When the histogram is not uniform (?uniform=false?), then each of?ranges[i]?contains?histSize[i]+1?elements:?. The array elements, that are not between??and??, are not counted in the histogram.
  • uniform?– Flag indicating whether the histogram is uniform or not (see above).
  • accumulate?– Accumulation flag. If it is set, the histogram is not cleared in the beginning when it is allocated. This feature enables you to compute a single histogram from several sets of arrays, or to update the histogram in time.

釋義:

images:源圖像矩陣(可以多個,但必須滿足一定條件:同等深度,同等大小,同種數(shù)據(jù)類型:CV_8U或CV_32F,通道數(shù)不需要一致)

nimages:源圖像個數(shù)

channels:用來計算直方圖

例程:

#include <cv.h>
#include <highgui.h>using namespace cv;int main( int argc, char** argv )
{Mat src, hsv;if( argc != 2 || !(src=imread(argv[1], 1)).data )return -1;cvtColor(src, hsv, CV_BGR2HSV);// Quantize the hue to 30 levels// and the saturation to 32 levelsint hbins = 30, sbins = 32;int histSize[] = {hbins, sbins};// hue varies from 0 to 179, see cvtColorfloat hranges[] = { 0, 180 };// saturation varies from 0 (black-gray-white) to// 255 (pure spectrum color)float sranges[] = { 0, 256 };const float* ranges[] = { hranges, sranges };MatND hist;// we compute the histogram from the 0-th and 1-st channelsint channels[] = {0, 1};calcHist( &hsv, 1, channels, Mat(), // do not use maskhist, 2, histSize, ranges,true, // the histogram is uniformfalse );double maxVal=0;minMaxLoc(hist, 0, &maxVal, 0, 0);int scale = 10;Mat histImg = Mat::zeros(sbins*scale, hbins*10, CV_8UC3);for( int h = 0; h < hbins; h++ )for( int s = 0; s < sbins; s++ ){float binVal = hist.at<float>(h, s);int intensity = cvRound(binVal*255/maxVal);rectangle( histImg, Point(h*scale, s*scale),Point( (h+1)*scale - 1, (s+1)*scale - 1),Scalar::all(intensity),CV_FILLED );}namedWindow( "Source", 1 );imshow( "Source", src );namedWindow( "H-S Histogram", 1 );imshow( "H-S Histogram", histImg );waitKey();
}

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轉(zhuǎn)載于:https://www.cnblogs.com/Atanisi/p/6910125.html

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