進程間通信

socket通信

客戶端-->請求--> 路由轉(zhuǎn)發(fā) --> 服務(wù)端，取出資源 --> 封裝為可響應(yīng)給客戶端的請求報文從接收請求端口發(fā)出

SSL/TLS協(xié)議的實現(xiàn) OpenSSL

OpenSSL程序組件

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[root@localhost?CA]#?rpm?-ql?openssl? /usr/lib/libcrypto.so.10??//加密解密庫?(C，C++程序員調(diào)用的庫) /usr/lib/libssl.so.10????//ssl/tls實現(xiàn)?(C,C++程序員調(diào)用的庫)?HTTP?-->?HTTPS /usr/bin/openssl????????//命令行工具

SSL Secure Socket Layer 安全的套接字層

TLS Transfer Layer Secure ?傳輸層安全

SSL分層

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用組件拼裝而成的密碼學協(xié)議軟件(TLS,?SSL) 標準算法組合成半成品 算法實現(xiàn)：AES-128-CBC-PKCS7 算法原語：AES(對稱加密)，RSA(非對稱加密),MD5(單向加密)

NIST制定的安全標準:保密性、完整性、可用性

SOCKET通信模型中面臨的風險:竊聽、偽裝、重放、消息篡改、拒絕服務(wù)

保證安全的手段(安全機制)：加密、身份認證、訪問控制、完整性校驗、路由控制、公證

提供安全機制的服務(wù)：認證、訪問控制、保密性、完整性、不可否認性

保證服務(wù)的安全(算法和協(xié)議)：對稱、非對稱、單向、密鑰交換

加密解密的基礎(chǔ)原理

對稱加密、非對稱加密、單向加密、密鑰交換

證書頒發(fā)機構(gòu)CA、證書的作用

PKI

證書的規(guī)范

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#?openssl?x509?-in?/etc/pki/CA/certs/httpd.crt?-noout?-text?-subject?-serial Certificate: ????Data: ????????Version:?3?(0x2)????//版本號 ????????Serial?Number:?1?(0x1)?//序列號（每個從的惟一標識) ????Signature?Algorithm:?sha1WithRSAEncryption???//簽名算法ID ????????Issuer:?C=CD,?ST=CD,?L=ChengDu???????????//CA名稱 ?????????????????????????????????????????????????//證書有效期 ????????????Not?Before:?Sep?21?07:16:20?2017?GMT ????????????Not?After?:?Sep?21?07:16:20?2018?GMT ????????Subject:?C=CD,?ST=CD,?O=MageEdu,????????//主體名稱(主機名) ????????Subject?Public?Key?Info:????????????????//主體公鑰 ????????????????Modulus: ????????????????????00:eb:bd:58:2d:05:54:49:6d:ac:42:98:ee:cb:fb: ????????????????????ec:62:20:e1:1e:e4:64:ef:a3:0f:23:17:5b:fb:66: ????????????????????6d:a9:ce:81:c3:53:b5:f8:d9:87:da:c5:f3:2d:77: ????????????????????f2:de:3b:ed:92:81:a5:6c:73:f6:83:3c:c2:e5:71: ????????????????????49:02:02:ae:45:d0:e0:45:f2:41:34:f8:25:87:41: ????????????????????82:aa:27:e2:17:ca:fc:74:f3:50:98:b0:6c:b0:26: ????????????????????8b:a5:0d:a7:ca:4b:f5:72:f9:44:87:8b:15:51:ea: ????????????????????9a:84:6d:22:aa:fe:84:62:5a:59:33:c3:ff:29:51: ????????????????????a9:1a:56:c3:63:22:9a:6d:2c:65:10:a0:57:78:c2: ????????????????????aa:70:3d:32:eb:59:dc:f7:a9:0c:ea:e5:8e:29:1c: ????????????????????2f:27:0d:53:87:e1:2b:eb:fe:f8:8f:61:8f:86:ab: ????????????????????f1:9c:ee:29:11:c1:71:ca:41:24:3e:1d:e1:3c:84: ????????????????????60:8a:d8:4d:ad:4c:b2:ca:8f:25:29:8a:11:1a:6f: ????????????????????1c:03:88:4a:66:99:73:34:7d:76:da:85:77:da:65: ????????????????????3a:e5:d3:ca:58:9f:8c:3a:3b:d5:e2:9e:77:1e:b2: ????????????????????f3:c8:5a:b6:2d:2b:68:71:20:9f:94:41:0c:4b:2f: ????????????????????93:f5:11:4c:89:9e:d9:48:ac:de:62:d9:5e:16:73: ????????????????????5d:39 ????????????????Exponent:?65537?(0x10001) ????????X509v3?extensions:??????????//擴展信息 ????????????X509v3?Subject?Key?Identifier:???//發(fā)行者的惟一標識 ????????????????C5:AE:93:32:58:BC:DC:F4:97:E5:D7:52:15:37:11:4D:ED:4C:B1:8E ????????????X509v3?Authority?Key?Identifier:??//主體的惟一標識 ????????????????keyid:D4:F7:60:6F:E8:F4:2D:A6:F7:5D:09:55:D2:5D:56:DE:1F:93:91:33 ????Signature?Algorithm:?sha1WithRSAEncryption?????//發(fā)行者簽名，簽名算法 ?????????3c:90:f8:cf:d6:91:36:ab:4b:12:27:22:78:85:7f:32:15:4e: ?????????ac:60:30:63:65:fe:91:be:1b:e5:22:65:34:4d:f0:b2:2c:d9: ?????????43:38:b9:76:1e:10:ca:27:ab:e9:db:00:bd:d9:87:96:b5:a9: ?????????ee:34:34:01:05:88:fc:59:ef:1d:9b:3f:8e:49:fa:e8:c9:54: ?????????15:d0:63:14:7d:51:e9:c8:8c:50:77:81:5c:f2:56:f8:c2:ba: ?????????16:46:cc:7f:e2:72:27:56:4e:a7:c4:2c:b4:64:44:9a:84:bc: ?????????b2:19:5e:dd:3c:20:1c:a9:8c:93:ae:94:e4:8d:8e:d1:b7:47: ?????????3a:c5:f6:df:42:6f:d9:66:d8:25:97:03:94:01:60:f5:a7:60: ?????????c3:33:55:c3:cb:12:f8:14:1e:df:17:00:26:49:ce:74:fc:8f: ?????????56:16:10:b3:16:6e:09:06:8c:8f:84:e9:ec:e2:84:06:82:ac: ?????????27:8d:c5:f6:83:d8:3d:8d:de:d9:3e:e7:ae:15:41:a9:8d:42: ?????????e9:9d:8d:b8:d7:29:47:21:45:3c:39:49:7a:96:31:bb:95:93: ?????????7b:1b:29:07:dc:fe:ad:7c:f0:28:c5:cb:b5:65:8f:1f:7e:60: ?????????a3:86:50:9f:c3:da:53:1f:6b:ec:ab:7c:1a:7e:39:40:37:23: ?????????83:17:39:54 subject=?/C=CD/ST=CD/O=MageEdu/OU=Ops/CN=www.magedu.com/emailAddress=lccnx.foxmail.com serial=01 1、找到CA名，和簽名算法? 2、找到信任機構(gòu)的CA證書 3、用證書中的公鑰解密加密的數(shù)字簽名?????//身份認證 4、用相同的簽名算法對證書提取特征碼?????//完整性檢驗 5、比對特征碼是否相同

基于公鑰加密通信機制

SSL Hand shark：?一個IP地址只能建立一個SSL會話

openssl工具使用

對稱加密

使用示例

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使用示例： 1、創(chuàng)建臨時文件 #?mktemp?-p?/tmp?lcc.XXXX /tmp/lcc.hFdo 2、加密 ????#?openssl?enc?-e?-seed-cfb?-a?-salt?-in?lcc.hFdo?-out?lcc.ciphertext 3、解密 ????#?openssl?enc?-d?-seed-cfb?-a?-salt?-in?lcc.ciphertext?-out?lcc.txt

單向加密

使用示例

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#?sha1sum?lcc.txt? 5448d7dc19288c6ee87a25d4e2e990f72d786971??lcc.txt #?openssl?dgst?-sha1?-hex?lcc.txt? SHA1(lcc.txt)=?5448d7dc19288c6ee87a25d4e2e990f72d786971

生成用戶密碼

使用示例

1 2	#?openssl?passwd?-1?-salt?$(openssl?rand?-hex?4)? #?openssl?passwd?-1?-salt?$(openssl?rand?-hex?4)?123

生成隨機數(shù)

使用示例

1 2	#?openssl?rand?-hex?4??????(8位) #?openssl?rand?-base64?16?|?tr?-d?'='

生成密鑰對

使用示例

# openssl genrsa ?-out lcc.private 1024

# openssl ?rsa ?-in lcc.private -out lcc.pubkey -pubout

私有網(wǎng)絡(luò)安全通信的實現(xiàn)方案

構(gòu)建私有CA

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#??echo?"01"?>?/etc/pki/CA/serial????????//必須為01，否則簽發(fā)不了 #??touch?/etc/pki/CA/index.txt #?cd?/etc/pki/CA #?(umask?077;openssl?genrsa?-out?private/cakey.pem?1024) #?openssl?req?-new?-x509?-key??private/cakey.pem?-out?cacert.pem?-days?7300

申請請求

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#?install?-d?/etc/httpd/ssl #?cd?/etc/httpd/ssl #?(umask?077;openssl?genrsa?-out?httpd.key?1024) #?openssl?req?-new?-key?httpd.key?-out?httpd.csr?-days?365

傳給CA

CA所在的主機必須有軟件能得以實現(xiàn)SSH協(xié)議<dropbear, telnet, openssh-server>，才能使用客戶端工具<scp, sftp, ssh>

1	#?scp?-P?9999?/etc/httpd/ssl/httpd.csr?root@192.168.80.129

CA驗證

CA簽發(fā)

1	#?openssl?ca?-in?/tmp/httpd.csr?-out?/tmp/httpd.crt?-days?365

從證書存取庫中獲取證書

1	#?scp?-P?9999?root@192.168.80.129:/etc/pki/CA/certs/httpd.crt?/etc/httpd/ssl/

驗證證書

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#?openssl?x509?-in?certs/httpd.crt?-noout?-serial?-subject serial=01 subject=?/C=CD/ST=CD/O=MageEdu/OU=Ops/CN=www.magedu.com/emailAddress=lccnx.foxmail.com

在客戶端進行吊銷證書

1、獲取serial

1	#?openssl?x509?-in?/etc/httpd/ssl/httpd.crt?-noout?-serial?-subject

2、在CA，index.txt中查看serial與客戶端是否相同

吊銷

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#?openssl?ca?-revoke?newcerts/01.pem? Using?configuration?from?/etc/pki/tls/openssl.cnf Revoking?Certificate?01. Data?Base?Updated

3、生成吊銷證書編號

1	#?echo?"01"?>?/etc/pki/CA/crlnumber

4、更新吊銷列表?

1 2	#?openssl?ca?-gencrl?-out?thisca.crl Using?configuration?from?/etc/pki/tls/openssl.cnf

5、查看crl文件

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#?openssl?crl?-in?thisca.crl?-noout?-text Certificate?Revocation?List?(CRL): ????????Version?2?(0x1)????????//版本號 ????Signature?Algorithm:?sha1WithRSAEncryption???????//簽名算法 ????????Issuer:?/C=CD/ST=CD/L=ChengDu/O=MageEdu/OU=Ops/CN=ca.magedu.com/emailAddress=lccnx@foxmail.com ????????Last?Update:?Sep?21?08:14:35?2017?GMT?有效期 ????????Next?Update:?Oct?21?08:14:35?2017?GMT ????????CRL?extensions:????擴展信息 ????????????X509v3?CRL?Number:??吊銷號碼 ????????????????1 Revoked?Certificates: ????Serial?Number:?01 ????????Revocation?Date:?Sep?21?08:12:49?2017?GMT ????Signature?Algorithm:?sha1WithRSAEncryption ?????????5d:9e:a2:60:e3:78:9d:24:42:92:b6:72:81:92:43:d7:02:12: ?????????54:f0:8e:08:21:d8:55:34:1c:70:53:8d:ac:bd:44:15:37:30: ?????????ba:ef:d2:79:24:52:83:a1:bb:39:70:af:93:10:64:06:b6:e6: ?????????76:fd:12:cf:b5:f7:07:16:c6:cd:08:a9:46:d3:76:64:24:93: ?????????7d:b4:5a:6d:da:38:08:31:7b:6e:76:a6:4e:5a:c2:cc:e6:24: ?????????be:76:b9:38:46:ed:c7:16:61:88:8c:ac:90:bd:4e:c9:9d:e5: ?????????73:8a:76:c4:57:82:80:29:06:c8:81:cd:7b:37:08:ee:81:25: ?????????d6:04:8e:dd:dd:d8:1b:47:44:e4:bb:bc:3c:7f:cb:97:68:27: ?????????b0:32:ea:fb:d1:84:91:7e:50:05:14:0a:1d:65:2a:5e:ba:41: ?????????1d:dd:a4:39:e5:d2:b5:2b:33:b0:56:b3:78:cc:99:69:c9:89: ?????????0e:a0:71:f1:5f:ca:40:57:73:72:4d:f0:3d:ea:57:d7:53:6d: ?????????90:ca:59:57:65:1b:ec:b5:4d:6f:7e:41:64:c1:c6:d4:ab:b1: ?????????01:b5:a3:e3:67:0c:59:c9:bc:e6:6c:d1:ae:20:05:3f:85:87: ?????????32:f8:bf:3c:9a:ba:e8:c2:e9:fd:e8:b8:54:92:86:45:95:ca: ?????????c3:53:13:41

本文轉(zhuǎn)自 lccnx 51CTO博客，原文鏈接：http://blog.51cto.com/sonlich/1965404，如需轉(zhuǎn)載請自行聯(lián)系原作者

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