當(dāng)前位置：首頁 > 编程资源 > 编程问答 >内容正文

编程问答

C语言解析http请求表单内容

發(fā)布時間：2023/11/30 编程问答 30 豆豆

生活随笔收集整理的這篇文章主要介紹了 C语言解析http请求表单内容小編覺得挺不錯的,現(xiàn)在分享給大家,幫大家做個參考.

[1].[文件] cgi.h?~?405B????下載(105) 跳至 [1] [2] [3] [4] [5] [6] [7] [8]

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27

#ifndef CGI_H #define CGI_H #include <stdio.h> #include <string.h> #include <stdlib.h> typedef struct Node{ ????char *name; ????char *value; ????struct Node *next; }Node; typedef struct Index{ ????Node *head; ????char *buffer; }Index; Index *get_input(); void free_input(Index *); Node *analyze(char *); Node *analy_a(char *); Node *analy_m(char *, char *); char *get_value(Node *, char *); char fun1(char); #endif

[2].[文件] get_input.c?~?965B????下載(85) 跳至 [1] [2] [3] [4] [5] [6] [7] [8]

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39

#include "cgi.h" Index *get_input() { ????//獲得表單發(fā)送方法 ????char *get_method = getenv("REQUEST_METHOD"); ????Index *input = (Index *)malloc(sizeof(Index)); ????Node *head; ????char *buffer; ????if (strcmp(get_method,"GET") == 0) { ????????char *get_str = getenv("QUERY_STRING"); ????????if (get_str == NULL || *get_str == 0) { ????????????return NULL; ????????} ????????//get方法，通過環(huán)境變量得到內(nèi)容 ????????buffer = (char *)malloc(strlen(get_str) + 1); ????????strcpy(buffer, get_str); ????????//對內(nèi)容進行解析，以鏈表的形式存在 ????????head = analy_a(buffer); ????} else if (strcmp(get_method,"POST") == 0){ ????????int get_len = atoi(getenv("CONTENT_LENGTH")); ????????if (get_len == 0) { ????????????return NULL; ????????} ????????//post方法，通過標(biāo)準(zhǔn)輸入讀取內(nèi)容 ????????buffer = (char *)malloc(get_len + 1); ????????memset(buffer,0,get_len + 1); ????????int n = fread(buffer, 1,get_len, stdin); ????????if (n != get_len) { ????????????fprintf(stderr,"Read error!"); ????????} ????????head = analyze(buffer); ????} ????//鏈表頭 ????input -> head = head; ????//接受到的字符串 ????input -> buffer = buffer; ????return input; }

[3].[文件] analyze.c?~?610B????下載(81) 跳至 [1] [2] [3] [4] [5] [6] [7] [8]

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21

#include "cgi.h" //post方法獲取的內(nèi)容進行解析 Node *analyze(char *buffer) { ????//獲取內(nèi)容格式 ????char *c_type = getenv("CONTENT_TYPE"); ????char *bound; ????fprintf(stderr,"debug:c_type is %s\n",c_type); ????if (strcmp("application/x-www-form-urlencoded",c_type) == 0) { ????????//該格式表明獲取內(nèi)容為"name=value"形式 ????????return analy_a(buffer);???? ????} else if (strcmp("text/plain", c_type) == 0) { ????????//此種編碼格式暫不討論 ????} else { ????????//編碼格式為multipart/form-data，適用大流量數(shù)據(jù)傳送 ????????//獲取等號后面的分隔符 ????????bound = index(c_type,'=') + 1; ????????fprintf(stderr,"debug:bound is %s\n",bound); ????????return analy_m(buffer, bound); ????} }

[4].[文件] analy_a.c?~?961B????下載(78) 跳至 [1] [2] [3] [4] [5] [6] [7] [8]

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40

#include "cgi.h" //編碼格式為'application/x-www-form-urlencoded'的內(nèi)容 Node *analy_a(char *buffer) { ????//創(chuàng)建第一個節(jié)點 ????Node *head = (Node *)malloc(sizeof(Node)); ????Node *temp = head; ????temp -> name = buffer; ????char *b_temp = buffer; ????//通過移動、改變部分字符來分離字符串 ????while (*buffer != 0) { ????????if (*buffer == '=') { ????????????//'='，則表示name已經(jīng)結(jié)束，value將開始 ????????????*b_temp = 0; ????????????temp -> value = b_temp + 1;? ????????}else if (*buffer == '+') { ????????????//'+'代表空格 ????????????*b_temp = ' '; ????????}else if (*buffer == '%') { ????????????//'%'則緊跟兩位十六進制表示的特殊字符 ????????????*b_temp = fun1(*(buffer + 1)) * 16 + fun1(*(buffer + 2)); ????????????buffer += 2; ????????} ????????else if (*buffer == '&') { ????????????//'&'表示value已經(jīng)結(jié)束，name即將開始 ????????????*b_temp = 0; ????????????//重新申請內(nèi)存，存儲新內(nèi)容地址 ????????????temp -> next = (Node *)malloc(sizeof(Node)); ????????????temp = temp -> next; ????????????temp -> name = b_temp + 1;?? ????????}else { ????????????*b_temp = *buffer; ????????} ????????buffer++; ????????b_temp++;?????????? ????} ????//最后一個結(jié)束符 ????*b_temp = 0; ????return head; }

[5].[文件] analy_m.c?~?1KB????下載(80) 跳至 [1] [2] [3] [4] [5] [6] [7] [8]

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36

#include "cgi.h" //編碼格式為'multipart/form-data'的內(nèi)容 Node *analy_m(char *buffer, char *bound) { ????char *start; ????char *end; ????//第一個節(jié)點 ????Node *head = (Node*)malloc(sizeof(Node)); ????Node *temp = head; ????fprintf(stderr,"debug:buffer is %s\n", buffer); ????//開始解析內(nèi)容，name在兩個雙引號之間(詳見編碼格式) ????temp -> name = index(buffer, '"') + 1; ????end = index(temp -> name, '"'); ????*end = 0; ????fprintf(stderr,"debug:temp->name is %s\n", temp -> name); ????//中間間隔了兩個"\r\n" ????temp -> value = end + 5; ????buffer = strstr(temp -> value, bound); ????//到下一個間隔符，上面間隔兩個"\r\n" ????*(buffer - 4) = 0; ????fprintf(stderr,"debug:temp->valu is %s\n", temp -> value); ????while ((start = strstr(buffer,"name=")) != NULL) { ????????//循環(huán)獲取name與value地址，直到?jīng)]有name為止 ????????temp -> next = (Node *)malloc(sizeof(Node)); ????????temp = temp -> next; ????????temp -> name = index(start, '"') + 1; ????????end = index(temp -> name, '"'); ????????*end = 0; ????????fprintf(stderr,"debug:temp->name is %s\n", temp -> name); ????????temp -> value = end + 5; ????????buffer = strstr(temp -> value, bound); ????????*(buffer - 4) = 0; ????????fprintf(stderr,"debug:temp->valu is %s\n", temp -> value); ????} ????return head; }

[6].[文件] fun1.c?~?203B????下載(76) 跳至 [1] [2] [3] [4] [5] [6] [7] [8]

1 2 3 4 5 6 7 8 9 10 11 12 13

//將十六進制字符轉(zhuǎn)化為十進制數(shù) char fun1(char ch) { ????char buffer; ????if (ch < 'A') { ????????buffer = ch - 48;?????????????????????????? ????}else if (ch < 'a'){ ????????buffer = ch - 55; ????}else { ????????buffer = ch - 87; ????} ????return buffer;? }

[7].[文件] get_value.c?~?241B????下載(77) 跳至 [1] [2] [3] [4] [5] [6] [7] [8]

1 2 3 4 5 6 7 8 9 10 11 12 13 14

#include "cgi.h" //根據(jù)name獲取相應(yīng)的value char *get_value(Node *head, char *name) {?? ????Node *p; ????while (head != NULL) { ????????if (strcmp(head -> name, name) == 0) { ????????????return head -> value; ????????} ????????p = head -> next; ????????head = p; ????} ????return NULL; }

[8].[文件] free_input.c?~?222B????下載(79) 跳至 [1] [2] [3] [4] [5] [6] [7] [8]