您已經提供了數據樣本,說明這是一行,但已將其顯示為兩個不同的行.所以這個例子基于你的話.

-- Sample of data from your question + extra row for the sake of demonstration

-- id column is added to distinguish the rows(I assume you have one)

with t1(id, col) as(

select 1, '^FO360,065^AEN,25,10^FD{CUSTOMERS1.CUST_NAME}^FS^FO360,095^AAN,15,12^FD{CUSTOMERS1.CUST_ADDR1}^FS' from dual union all

select 2, '^FO360,065^AEN,25,10^FD{CUSTOMERS2.CUST_NAME}^FS^FO360,095^AAN,15,12^FD{CUSTOMERS2.CUST_ADDR2}^FS' from dual

),

cnt(c) as(

select level

from (select max(regexp_count(col, '{\w+.\w+}')) as o_c

from t1

) z

connect by level <= z.o_c

)

select t1.id, listagg(regexp_substr(t1.col, '{\w+.\w+}', 1, cnt.c)) within group(order by t1.id) res

from t1

cross join cnt

group by t1.id

結果：

ID RES

---------------------------------------------------------

1 {CUSTOMERS1.CUST_ADDR1}{CUSTOMERS1.CUST_NAME}

2 {CUSTOMERS2.CUST_ADDR2}{CUSTOMERS2.CUST_NAME}

根據問題的@a_horse_with_no_name comment,實際上,更換其他與模式不匹配的內容要簡單得多.這是一個例子：

with t1(col) as(

select '^FO360,065^AEN,25,10^FD{CUSTOMERS.CUST_NAME}^FS^FO360,095^AAN,15,12^FD{CUSTOMERS.CUST_ADDR1}^FS' from dual

)

select regexp_replace(t1.col, '({\w+.\w+})|.', '\1') res

from t1

結果：

RES

-------------------------------------------

{CUSTOMERS.CUST_NAME}{CUSTOMERS.CUST_ADDR1}

總結

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