Python | Lambda和map（）与示例
The map() function is used to apply the function to all items of an iterable collection like list, tuple etc and it returns the list of the result after performing the functionality defined in the applied function.
map()函數用于將函數應用于可迭代集合的所有項目，如list，tuple等，并在執行所應用函數中定義的功能后返回結果列表。
Example:
例：
Given a list of temperatures and we have to convert 1) all the values in Celsius and 2) all the values in Fahrenheit - using map() with lambda.
給定溫度列表，我們必須轉換1)攝氏溫度的所有值和2)華氏度的所有值-使用帶有lambda的map()。
1) Approach 1: Using normal way
1)方法1：使用常規方法
# function definition to convert temp. from c to f def ctof(c):f=9/5*c+32return f# function definition to convert temp. from f to c def ftoc(f):c=5/9*(f-32)return c# list of the values temp=[12,45,6,78,5,26,67] print("Orignal Data : ",temp)# list declration to store temp. in C cel=[] for t in temp:x=ftoc(t)cel.append(x) print("Celcuis Data : ",cel)# list declration to store temp. in F far=[] for t in temp:x=ctof(t)far.append(x) print("Farenhiet Data : ",far)Output
輸出量
Orignal Data : [12, 45, 6, 78, 5, 26, 67] Celcuis Data : [-11.11111111111111, 7.222222222222222, -14.444444444444445, 25.555555555555557, -15.0, -3.3333333333333335, 19.444444444444446] Farenhiet Data : [53.6, 113.0, 42.8, 172.4, 41.0, 78.80000000000001, 152.60000000000002]2) Approach 2: Using map() with lambda
2)方法2：將map()與lambda結合使用
# list of the values temp=[12,45,6,78,5,26,67] print("Orignal Data : ",temp)# converting values to cel using map and lambda cel=list(map(lambda f:5/9*(f-32),temp)) print("Celcuis Data : ",cel)# converting values to far using map and lambda far=list(map(lambda c:9/5*c+32,temp)) print("Farenhiet Data : ",far)Output
輸出量
Orignal Data : [12, 45, 6, 78, 5, 26, 67] Celcuis Data : [-11.11111111111111, 7.222222222222222, -14.444444444444445, 25.555555555555557, -15.0, -3.3333333333333335, 19.444444444444446] Farenhiet Data : [53.6, 113.0, 42.8, 172.4, 41.0, 78.80000000000001, 152.60000000000002]翻譯自: https://www.includehelp.com/python/lambda-and-map-with-example.aspx
總結
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