strictmath

StrictMath類sqrt()方法 (StrictMath Class sqrt() method)

• sqrt() Method is available in java.lang package.

  sqrt()方法在java.lang包中可用。

• sqrt() Method is used to find the square root of the given parameter in the method. Here, "sqrt" stands for square root

• sqrt() Method is a static method so it is accessible with the class name and if we try to access the method with the class object then we will not get any error.
• sqrt() Method does not throw any exception at the time of finding the square root of the given number.

• sqrt()方法用于查找方法中給定參數的平方根。 在這里， “ sqrt”代表平方根

• sqrt()方法是靜態方法，因此可以使用類名進行訪問，如果嘗試使用類對象訪問該方法，則不會收到任何錯誤。
• sqrt()方法在查找給定數字的平方根時不會引發任何異常。

Syntax:

句法：

public static double sqrt(double d);

Parameter(s):

參數：

• double d – represents for which we have to find the square root.

  double d –代表我們必須找到其平方根。

Return value:

返回值：

The return type of the method is double, it returns the square root of the given parameter.

該方法的返回類型為double ，它返回給定參數的平方根。

Note:

注意：

• If we pass NaN, the method returns the same (i.e. NaN).

  如果我們通過NaN，則該方法返回相同的值(即NaN)。

• If we pass zero, the method returns the same value with the same sign.

  如果傳遞零，則該方法返回具有相同符號的相同值。

• If we pass an argument positive infinity, the method returns the same.

  如果我們傳遞參數正無窮大，則該方法將返回相同的結果。

Example:

例：

// Java program to demonstrate the example of sqrt(double d) // method of StrictMath class.public class Sqrt {public static void main(String[] args) {// variable declarationsdouble d1 = -0.0;double d2 = 0.0;double d3 = -7.0 / 0.0;double d4 = 7.0 / 0.0;double d5 = 1000.0;double d6 = -1000.0;// Display previous value of d1,d2,d3,d4,d5 and d6System.out.println("d1: " + d1);System.out.println("d2: " + d2);System.out.println("d3: " + d3);System.out.println("d4: " + d4);System.out.println("d5: " + d5);System.out.println("d6: " + d6);/*Here , we will get (-0.0) because we are passing parameter (-0.0) */System.out.println("StrictMath.sqrt(d1): " + StrictMath.sqrt(d1));// Here , we will get (0.0) because we are passing parameter // (0.0) so the square root is the sameSystem.out.println("StrictMath.sqrt(d2): " + StrictMath.sqrt(d2));// Here , we will get (NaN) because we are passing parameter // (-7.0/0.0) so the square root is (-Infinity)System.out.println("StrictMath.sqrt(d3): " + StrictMath.sqrt(d3));// Here , we will get (Infinity) because we are passing // parameter (7.0/0.0) so the square root is (Infinity)System.out.println("StrictMath.sqrt(d4): " + StrictMath.sqrt(d4));// Here , we will get (square root of given argument) because // we are passing parameter (1000.0) System.out.println("StrictMath.sqrt(d5): " + StrictMath.sqrt(d5));// Here , we will get (NaN) because we are passing parameter // (-1000.0) System.out.println("StrictMath.sqrt(d6): " + StrictMath.sqrt(d6));} }

Output

輸出量

d1: -0.0 d2: 0.0 d3: -Infinity d4: Infinity d5: 1000.0 d6: -1000.0 StrictMath.sqrt(d1): -0.0 StrictMath.sqrt(d2): 0.0 StrictMath.sqrt(d3): NaN StrictMath.sqrt(d4): Infinity StrictMath.sqrt(d5): 31.622776601683793 StrictMath.sqrt(d6): NaN

翻譯自: https://www.includehelp.com/java/strictmath-sqrt-method-with-example.aspx

strictmath

總結

以上是生活随笔為你收集整理的strictmath_Java StrictMath sqrt（）方法与示例的全部內容，希望文章能夠幫你解決所遇到的問題。

如果覺得生活随笔網站內容還不錯，歡迎將生活随笔推薦給好友。