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FileUpload之单个文件上传

發布時間：2023/12/1 32 豆豆

生活随笔收集整理的這篇文章主要介紹了 FileUpload之单个文件上传小編覺得挺不錯的,現在分享給大家,幫大家做個參考.

拖一個FileUpload控件,設計如圖:

查看源：

雙擊Save按扭,在打開后置的cs文件:

在F盤新建一個文件夾Uploads:

??? protected void btnSave_Click(object sender, EventArgs e)
??? {
??????? string str = "";

??????? if (UploadFile.HasFile)
??????? {//檢測文本框中是否輸入了有效的完全限定文件名
??????????? try
??????????? {
??????????????? //獲取客戶端使用的文件名稱
??????????????? str += "Uploading file:" + UploadFile.FileName;

??????????????? //將上傳的文件保存到web服務器指定路徑
??????????????? //返回與web服務器上虛擬路徑的相對物理路徑
??????????????? UploadFile.SaveAs("F:\\Uploads\\" + UploadFile.FileName);
??????????????? //文件名稱
??????????????? str += " Saves As:" + UploadFile.PostedFile.FileName;
??????????????? //文件類型
??????????????? str += " File Type:" + UploadFile.PostedFile.ContentType;
??????????????? //文件大小
??????????????? str += " File Length(bytes):" + UploadFile.PostedFile.ContentLength;
??????????????? str += " PostedFile File Name:" + UploadFile.PostedFile.FileName;
??????????????? //UploadFile.SaveAs("F:\\Uploads\\" + UploadFile.FileName);
??????????????? //lblMessage.Text = "File name: " +
??????????????? //UploadFile.PostedFile.FileName + " " +
??????????????? //UploadFile.PostedFile.ContentLength + " kb " +
??????????????? //"Content type: " +
??????????????? //UploadFile.PostedFile.ContentType;
??????????? }
??????????? catch (Exception ex)
??????????? {
??????????????? str += " Error Unable to save UpLoad/" + UploadFile.FileName + " " + ex.Message;
??????????????? //lblMessage.Text = "ERROR: " + ex.Message.ToString();
??????????? }
??????? }
??????? else
??????? {
??????????? str = "No File uploaded";
??????????? //lblMessage.Text = "You have not specified a file.";
??????? }
??????? lblMessage.Text = str;
??????? lblDisplay.Text = "";
??? }

雙擊Display按鈕:

//顯示所選的文件,顯示文件的所有內容

??? protected void btnDisplay_Click(object sender, EventArgs e)
??? {
??????? string str = "File:" + UploadFile.FileName + " ";
??????? if (UploadFile.HasFile)
??????? {//檢測文本框中是否輸入了有效的完全限定文件名
??????????? try
??????????? {
??????????????? Stream stream = UploadFile.FileContent;
??????????????? //讀取字符
??????????????? StreamReader reader = new StreamReader(stream);
??????????????? string strLine = "";
??????????????? do
??????????????? {
??????????????????? //讀取一行并將數據作為字符串返回
??????????????????? strLine = reader.ReadLine();
??????????????????? str += strLine;
??????????????? } while (strLine != null);
??????????? }
??????????? catch (Exception ex)
??????????? {
??????????????? str += " Error Unable to display" + UploadFile.FileName + " " + ex.Message;
??????????? }
??????? }
??????? else
??????? {
??????????? str = "No file uploaded";
??????? }
??????? lblMessage.Text = str;
??????? lblDisplay.Text = "";
??? }

轉載于:https://www.cnblogs.com/scsuns520/archive/2009/12/26/1632952.html

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