日韩性视频-久久久蜜桃-www中文字幕-在线中文字幕av-亚洲欧美一区二区三区四区-撸久久-香蕉视频一区-久久无码精品丰满人妻-国产高潮av-激情福利社-日韩av网址大全-国产精品久久999-日本五十路在线-性欧美在线-久久99精品波多结衣一区-男女午夜免费视频-黑人极品ⅴideos精品欧美棵-人人妻人人澡人人爽精品欧美一区-日韩一区在线看-欧美a级在线免费观看

歡迎訪問 生活随笔!

生活随笔

當前位置: 首頁 > 编程语言 > python >内容正文

python

python空格怎么加密_使用Python的RSA加密

發布時間:2023/12/2 python 29 豆豆
生活随笔 收集整理的這篇文章主要介紹了 python空格怎么加密_使用Python的RSA加密 小編覺得挺不錯的,現在分享給大家,幫大家做個參考.

如果您想使用python高效地編碼RSA加密,我的github存儲庫肯定會理解和解釋python中RSA的數學定義

RSA密鑰生成def keyGen():

''' Generate Keypair '''

i_p=randint(0,20)

i_q=randint(0,20)

# Instead of Asking the user for the prime Number which in case is not feasible,

# generate two numbers which is much highly secure as it chooses higher primes

while i_p==i_q:

continue

primes=PrimeGen(100)

p=primes[i_p]

q=primes[i_q]

#computing n=p*q as a part of the RSA Algorithm

n=p*q

#Computing lamda(n), the Carmichael's totient Function.

# In this case, the totient function is the LCM(lamda(p),lamda(q))=lamda(p-1,q-1)

# On the Contrary We can also apply the Euler's totient's Function phi(n)

# which sometimes may result larger than expected

lamda_n=int(lcm(p-1,q-1))

e=randint(1,lamda_n)

#checking the Following : whether e and lamda(n) are co-prime

while math.gcd(e,lamda_n)!=1:

e=randint(1,lamda_n)

#Determine the modular Multiplicative Inverse

d=modinv(e,lamda_n)

#return the Key Pairs

# Public Key pair : (e,n), private key pair:(d,n)

return ((e,n),(d,n))

總結

以上是生活随笔為你收集整理的python空格怎么加密_使用Python的RSA加密的全部內容,希望文章能夠幫你解決所遇到的問題。

如果覺得生活随笔網站內容還不錯,歡迎將生活随笔推薦給好友。