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oracle全角字符转半角,Oracle 表字段全角字符轉換半角字符辦法

發布時間:2023/12/2 编程问答 36 豆豆
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在Oralce的某一個表中,一個地址字段包含了全角的字符,需要轉換為半角字符,以便進一步處理。

表名:a

包含全角字符的字段:address

編輯表結構,添加一列:address2

在PLSQL中,新建SQL窗口,輸入:update a set a.address2 =(to_single_byte(a.address))

執行,提交,即可。

函數解釋:

轉換成半角函數:

to_single_byte(s)

轉換成

全角

函數:

to_multi_byte(s)

以上這個to_single_byte(s)和to_multi_byte(s)函數發揮作用的前提是數據庫字符集包括單字節字符和多字節字符。

我的另外一臺數據庫安裝的是GBK字符集,但是查看表的內碼,發現表的數據是用unicode字符集存儲的,暫時還未搞明白是怎么回事。。。。。

如果數據庫不包含這些字符,需要用repalce()函數,分別手工去替換:

update a t set t.address = replace(t.address,'A','A')

update a t set t.address = replace(t.address,'B','B')

update a t set t.address = replace(t.address,'C','C')

update a t set t.address = replace(t.address,'D','D')

update a t set t.address = replace(t.address,'E','E')

update a t set t.address = replace(t.address,'F','F')

update a t set t.address = replace(t.address,'G','G')

update a t set t.address = replace(t.address,'H','H')

update a t set t.address = replace(t.address,'I','I')

update a t set t.address = replace(t.address,'J','J')

update a t set t.address = replace(t.address,'K','K')

update a t set t.address = replace(t.address,'L','L')

update a t set t.address = replace(t.address,'M','M')

update a t set t.address = replace(t.address,'N','N')

update a t set t.address = replace(t.address,'O','O')

update a t set t.address = replace(t.address,'P','P')

update a t set t.address = replace(t.address,'Q','Q')

update a t set t.address = replace(t.address,'R','R')

update a t set t.address = replace(t.address,'S','S')

update a t set t.address = replace(t.address,'T','T')

update a t set t.address = replace(t.address,'U','U')

update a t set t.address = replace(t.address,'V','V')

update a t set t.address = replace(t.address,'W','W')

update a t set t.address = replace(t.address,'X','X')

update a t set t.address = replace(t.address,'Y','Y')

update a t set t.address = replace(t.address,'Z','Z')

update a t set t.address = replace(t.address,'-','-')

update a t set t.address = replace(t.address,'0','0')

update a t set t.address = replace(t.address,'1','1')

update a t set t.address = replace(t.address,'2','2')

update a t set t.address = replace(t.address,'3','3')

update a t set t.address = replace(t.address,'4','4')

update a t set t.address = replace(t.address,'5','5')

update a t set t.address = replace(t.address,'6','6')

update a t set t.address = replace(t.address,'7','7')

update a t set t.address = replace(t.address,'8','8')

update a t set t.address = replace(t.address,'9','9')

手工寫入這些好麻煩,有沒有自動化的一點的辦法?

總結

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