hibernate臟數據

在使用Hibernate作為ORM開發服務器和嵌入式應用程序8年后，我全力以赴地尋求提高Hibernate性能的解決方案，閱讀博客和參加會議，我決定與您分享在這些年中獲得的知識。

這是更多新帖子中的第一篇：

去年，我以Devoxx的身份參加了演講，但是我也參加了關于Hibernate反模式的 Patrycja Wegrzynowicz會議。 在該演示中， Patrycja向我們展示了一種反模式，它使我震驚，因為事實證明它預料到了意外情況。

我們將看到當Hibernate檢測到一個骯臟的集合并應該重新創建它時所產生的效果。

讓我們從將要使用的模型開始，只有兩個與一對多關聯相關的類：

@Entity public class Starship {private Long id;@Id @GeneratedValue(strategy=GenerationType.SEQUENCE) public Long getId() {return id;}public void setId(Long id) {this.id = id;}private Date launched;@Temporal(TemporalType.DATE) public Date getLaunched() {return launched;}public void setLaunched(Date launched) {this.launched = launched;}private String registry;@Column(unique=true, nullable=false) public String getRegistry() {return registry;}public void setRegistry(String registry) {this.registry = registry;}private StarshipClassEnum starshipClassEnum;@Enumerated public StarshipClassEnum getStarshipClassEnum() {return starshipClassEnum;}public void setStarshipClassEnum(StarshipClassEnum starshipClassEnum) {this.starshipClassEnum = starshipClassEnum;}private AffiliationEnum affiliationEnum;@Enumerated public AffiliationEnum getAffiliationEnum() {return affiliationEnum;}public void setAffiliationEnum(AffiliationEnum affiliationEnum) {this.affiliationEnum = affiliationEnum;}private Physics physics;@Embedded public Physics getPhysics() {return physics;}public void setPhysics(Physics physics) {this.physics = physics;}private List<Officer> officers = new ArrayList<Officer>();@OneToMany(cascade={CascadeType.ALL}) public List<Officer> getOfficers() {return Collections.unmodifiableList(officers);}protected void setOfficers(List<Officer> officers) {this.officers = officers;}public void addOfficer(Officer officer) {officer.setStarship(this);this.officers.add(officer);}public Starship() {super();}public Starship(String registry) {setRegistry(registry);}@Overridepublic int hashCode() {final int prime = 31;int result = 1;result = prime * result+ ((registry == null) ? 0 : registry.hashCode());return result;}@Overridepublic boolean equals(Object obj) {if (this == obj)return true;if (obj == null)return false;if (getClass() != obj.getClass())return false;Starship other = (Starship) obj;if (registry == null) {if (other.registry != null)return false;} else if (!registry.equals(other.registry))return false;return true;} }@Entity public class Officer {private Long id;@Id @GeneratedValue(strategy=GenerationType.SEQUENCE)public Long getId() {return id;}protected void setId(Long id) {this.id = id;}private String name;@Column(unique=true, nullable=false) public String getName() {return this.name;}public void setName(String name) {this.name = name;}private SpeciesEnum speciesEnum;@Enumerated public SpeciesEnum getSpeciesEnum() {return speciesEnum;}public void setSpeciesEnum(SpeciesEnum speciesEnum) {this.speciesEnum = speciesEnum;}private PlanetEnum homePlanet;@Enumerated public PlanetEnum getHomePlanet() {return homePlanet;}public void setHomePlanet(PlanetEnum homePlanet) {this.homePlanet = homePlanet;}private AffiliationEnum affiliationEnum;@Enumerated public AffiliationEnum getAffiliationEnum() {return affiliationEnum;}public void setAffiliationEnum(AffiliationEnum affiliationEnum) {this.affiliationEnum = affiliationEnum;}private RankEnum rank;@Enumerated @NotNull public RankEnum getRank() {return rank;}public void setRank(RankEnum rank) {this.rank = rank;}private Starship starship; @ManyToOne public Starship getStarship() {return starship;}protected void setStarship(Starship starship) {this.starship = starship;}public Officer() {super();}public Officer(String name, RankEnum rank) {setName(name);setRank(rank);}@Overridepublic int hashCode() {final int prime = 31;int result = 1;result = prime * result + ((name == null) ? 0 : name.hashCode());return result;}@Overridepublic boolean equals(Object obj) {if (this == obj)return true;if (obj == null)return false;if (getClass() != obj.getClass())return false;Officer other = (Officer) obj;if (name == null) {if (other.name != null)return false;} else if (!name.equals(other.name))return false;return true;}}

在上一堂課中，我們應注意三個重點：

• 我們在屬性級別而不是字段級別進行注釋。
• @ OneToMany和@ ManyToOne使用默認選項（ 級聯定義除外）
• 星際飛船班的軍官getter返回一個不變的列表。

為了測試模型配置，我們將創建一個測試，該測試將創建并保留一個Starship和七個高級管理人員 ，并在不同的Transaction和EntityManager中找到創建的Starship 。

@ContextConfiguration @RunWith(SpringJUnit4ClassRunner.class) public class StarshipPersistenceTests {@Injectprivate EntityManagerFactory entityManagerFactory;@Testpublic void testSaveOrderWithItems() throws Exception {Starship starship = createData();findStarship(starship);}private Starship createData() {EntityManager entityManager = entityManagerFactory.createEntityManager();EntityTransaction transaction = entityManager.getTransaction();transaction.begin();Physics physics = physics().height(137.5D).length(642.5D).power("Wrap reactor").width(467.0D).build();Calendar launched = Calendar.getInstance();launched.set(2363, 9, 4);Starship starship = starship().registry("NCC-1701-D").physics(physics).launched(launched.getTime()).starshipClass(StarshipClassEnum.GALAXY).affiliation(AffiliationEnum.STARFLEET).build();Officer jeanLucPicard = officer().name("Jean-Luc Picard").rank(RankEnum.CAPTAIN).affiliation(AffiliationEnum.STARFLEET).homePlanet(PlanetEnum.EARTH).speciment(SpeciesEnum.HUMAN).build();starship.addOfficer(jeanLucPicard);Officer williamRiker = officer().name("William Riker").rank(RankEnum.COMMANDER).affiliation(AffiliationEnum.STARFLEET).homePlanet(PlanetEnum.EARTH).speciment(SpeciesEnum.HUMAN).build();starship.addOfficer(williamRiker);Officer data = officer().name("Data").rank(RankEnum.LIEUTENANT_COMMANDER).affiliation(AffiliationEnum.STARFLEET).homePlanet(PlanetEnum.OMICRON_THETA).speciment(SpeciesEnum.ANDROID).build();starship.addOfficer(data);Officer geordiLaForge = officer().name("Geordi La Forge").rank(RankEnum.LIEUTENANT).affiliation(AffiliationEnum.STARFLEET).homePlanet(PlanetEnum.EARTH).speciment(SpeciesEnum.HUMAN).build();starship.addOfficer(geordiLaForge);Officer worf = officer().name("Worf").rank(RankEnum.LIEUTENANT).affiliation(AffiliationEnum.STARFLEET).homePlanet(PlanetEnum.QONOS).speciment(SpeciesEnum.KLINGON).build();starship.addOfficer(worf);Officer beverlyCrusher = officer().name("Beverly Crusher").rank(RankEnum.COMMANDER).affiliation(AffiliationEnum.STARFLEET).homePlanet(PlanetEnum.EARTH).speciment(SpeciesEnum.HUMAN).build();starship.addOfficer(beverlyCrusher);Officer deannaTroi = officer().name("Deanna Troi").rank(RankEnum.COMMANDER).affiliation(AffiliationEnum.STARFLEET).homePlanet(PlanetEnum.BETAZED).speciment(SpeciesEnum.BETAZOID).build();starship.addOfficer(deannaTroi);entityManager.persist(starship);transaction.commit();entityManager.close();return starship;}private void findStarship(Starship starship) {EntityManager entityManager = this.entityManagerFactory.createEntityManager();EntityTransaction transaction = entityManager.getTransaction();transaction.begin();System.out.println("Before Find");Starship newStarship = entityManager.find(Starship.class, starship.getId());System.out.println("After Find Before Commit");transaction.commit();System.out.println("After commit");entityManager.close();} }

現在我們已經創建了這個測試，我們可以運行它并且觀察Hibernate控制臺的輸出。

Hibernate: insert into Starship (affiliationEnum, launched, height, length, power, width, registry, starshipClassEnum, id) values (?, ?, ?, ?, ?, ?, ?, ?, ?) Hibernate: insert into Officer (affiliationEnum, homePlanet, name, rank, speciesEnum, starship_id, id) values (?, ?, ?, ?, ?, ?, ?) Hibernate: insert into Officer (affiliationEnum, homePlanet, name, rank, speciesEnum, starship_id, id) values (?, ?, ?, ?, ?, ?, ?) Hibernate: insert into Officer (affiliationEnum, homePlanet, name, rank, speciesEnum, starship_id, id) values (?, ?, ?, ?, ?, ?, ?) Hibernate: insert into Officer (affiliationEnum, homePlanet, name, rank, speciesEnum, starship_id, id) values (?, ?, ?, ?, ?, ?, ?) Hibernate: insert into Officer (affiliationEnum, homePlanet, name, rank, speciesEnum, starship_id, id) values (?, ?, ?, ?, ?, ?, ?) Hibernate: insert into Officer (affiliationEnum, homePlanet, name, rank, speciesEnum, starship_id, id) values (?, ?, ?, ?, ?, ?, ?) Hibernate: insert into Officer (affiliationEnum, homePlanet, name, rank, speciesEnum, starship_id, id) values (?, ?, ?, ?, ?, ?, ?) Hibernate: insert into Starship_Officer (Starship_id, officers_id) values (?, ?) Hibernate: insert into Starship_Officer (Starship_id, officers_id) values (?, ?) Hibernate: insert into Starship_Officer (Starship_id, officers_id) values (?, ?) Hibernate: insert into Starship_Officer (Starship_id, officers_id) values (?, ?) Hibernate: insert into Starship_Officer (Starship_id, officers_id) values (?, ?) Hibernate: insert into Starship_Officer (Starship_id, officers_id) values (?, ?) Hibernate: insert into Starship_Officer (Starship_id, officers_id) values (?, ?)Before Find Starship By IdHibernate: select starship0_.id as id1_0_, starship0_.affiliationEnum as affiliat2_1_0_, starship0_.launched as launched1_0_, starship0_.height as height1_0_, starship0_.length as length1_0_, starship0_.power as power1_0_, starship0_.width as width1_0_, starship0_.registry as registry1_0_, starship0_.starshipClassEnum as starship9_1_0_ from Starship starship0_ where starship0_.id=?After Find Starship By Id and Before CommitHibernate: select officers0_.Starship_id as Starship1_1_2_, officers0_.officers_id as officers2_2_, officer1_.id as id0_0_, officer1_.affiliationEnum as affiliat2_0_0_, officer1_.homePlanet as homePlanet0_0_, officer1_.name as name0_0_, officer1_.rank as rank0_0_, officer1_.speciesEnum as speciesE6_0_0_, officer1_.starship_id as starship7_0_0_, starship2_.id as id1_1_, starship2_.affiliationEnum as affiliat2_1_1_, starship2_.launched as launched1_1_, starship2_.height as height1_1_, starship2_.length as length1_1_, starship2_.power as power1_1_, starship2_.width as width1_1_, starship2_.registry as registry1_1_, starship2_.starshipClassEnum as starship9_1_1_ from Starship_Officer officers0_ inner join Officer officer1_ on officers0_.officers_id=officer1_.id left outer join Starship starship2_ on officer1_.starship_id=starship2_.id where officers0_.Starship_id=? Hibernate: delete from Starship_Officer where Starship_id=? Hibernate: insert into Starship_Officer (Starship_id, officers_id) values (?, ?) Hibernate: insert into Starship_Officer (Starship_id, officers_id) values (?, ?) Hibernate: insert into Starship_Officer (Starship_id, officers_id) values (?, ?) Hibernate: insert into Starship_Officer (Starship_id, officers_id) values (?, ?) Hibernate: insert into Starship_Officer (Starship_id, officers_id) values (?, ?) Hibernate: insert into Starship_Officer (Starship_id, officers_id) values (?, ?) Hibernate: insert into Starship_Officer (Starship_id, officers_id) values (?, ?)After commit

查看在第一次提交（持久對象）和第二次事務提交（查找Starship ）期間執行的查詢數。 在忽略序列生成器的總數中，我們可以計數22個inserts ，2個selects和1個delete ，當我們僅創建8個對象和1個通過主鍵查找時就可以了。

此時，讓我們檢查為什么執行這些SQL查詢：

前8個插入是不可避免的。 通過將數據插入數據庫需要它們。

接下來的七都需要插入，因為我們已經注釋getOfficers財產沒有的mappedBy屬性。 如果我們仔細查看Hibernate文檔，它會指出“在不描述任何物理映射的情況下，將使用具有連接表的單向一對多 ”。

下一組查詢甚至更陌生，第一個選擇語句是通過id查找Starship，但是我們已經創建的這些數據刪除和插入是什么？

在提交期間， Hibernate通過比較對象引用來驗證集合屬性是否臟。 當一個集合被標記為臟集合時， Hibernate需要重新創建整個集合，甚至包含相同的對象。 在本例中，當我們要招募軍官時，我們將返回一個不同的集合實例，具體來說是一個不可修改的列表，因此Hibernate認為軍官的集合是骯臟的。

由于使用了聯接表，因此應重新創建Starship_Officer表，刪除先前插入的元組并插入新的元組（盡管它們具有相同的值）。

讓我們嘗試解決此問題。 我們首先映射一個雙向的一對多關聯，并以多對一的一方為擁有方。

private List<Officer> officers = new ArrayList<Officer>(); @OneToMany(mappedBy="starship", cascade={CascadeType.ALL}) public List<Officer> getOfficers() {return Collections.unmodifiableList(officers);} protected void setOfficers(List<Officer> officers) {this.officers = officers;} public void addOfficer(Officer officer) {this.officers.add(officer);}

現在，我們再次重新運行相同的測試，并再次檢查輸出。

Hibernate: insert into Starship (affiliationEnum, launched, height, length, power, width, registry, starshipClassEnum, id) values (?, ?, ?, ?, ?, ?, ?, ?, ?) Hibernate: insert into Officer (affiliationEnum, homePlanet, name, rank, speciesEnum, starship_id, id) values (?, ?, ?, ?, ?, ?, ?) Hibernate: insert into Officer (affiliationEnum, homePlanet, name, rank, speciesEnum, starship_id, id) values (?, ?, ?, ?, ?, ?, ?) Hibernate: insert into Officer (affiliationEnum, homePlanet, name, rank, speciesEnum, starship_id, id) values (?, ?, ?, ?, ?, ?, ?) Hibernate: insert into Officer (affiliationEnum, homePlanet, name, rank, speciesEnum, starship_id, id) values (?, ?, ?, ?, ?, ?, ?) Hibernate: insert into Officer (affiliationEnum, homePlanet, name, rank, speciesEnum, starship_id, id) values (?, ?, ?, ?, ?, ?, ?) Hibernate: insert into Officer (affiliationEnum, homePlanet, name, rank, speciesEnum, starship_id, id) values (?, ?, ?, ?, ?, ?, ?) Hibernate: insert into Officer (affiliationEnum, homePlanet, name, rank, speciesEnum, starship_id, id) values (?, ?, ?, ?, ?, ?, ?)Before Find Starship By IdHibernate: select starship0_.id as id1_0_, starship0_.affiliationEnum as affiliat2_1_0_, starship0_.launched as launched1_0_, starship0_.height as height1_0_, starship0_.length as length1_0_, starship0_.power as power1_0_, starship0_.width as width1_0_, starship0_.registry as registry1_0_, starship0_.starshipClassEnum as starship9_1_0_ from Starship starship0_ where starship0_.id=?After Find Starship By Id and Before CommitHibernate: select officers0_.starship_id as starship7_1_1_, officers0_.id as id1_, officers0_.id as id0_0_, officers0_.affiliationEnum as affiliat2_0_0_, officers0_.homePlanet as homePlanet0_0_, officers0_.name as name0_0_, officers0_.rank as rank0_0_, officers0_.speciesEnum as speciesE6_0_0_, officers0_.starship_id as starship7_0_0_ from Officer officers0_ where officers0_.starship_id=?After commit

盡管我們已將SQL語句的數量從25個減少到10個，但仍然有不必要的查詢，這些查詢僅位于第二個事務的commit部分中。 為什么如果默認情況下軍官是懶惰的（ JPA規范），而我們又沒有讓軍官參與交易，那么Hibernate會在“軍官”表上執行選擇嗎？ 出于與先前配置相同的原因，返回的集合具有不同的Java標識符，因此Hibernate將其標記為新實例化的集合，但是現在顯然不再需要連接表操作。 我們減少了查詢數量，但是仍然存在性能問題。 可能我們需要其他解決方案，而該解決方案不是最明顯的解決方案，我們不會返回Hibernate返回的集合對象，我們稍后可能會對此進行擴展，但是我們將更改批注的位置。

我們要做的是將映射位置從屬性方法更改為使用字段映射。 簡單來說，我們將所有注釋移至類屬性，而不是getter上 。

@Entity public class Starship {@Id @GeneratedValue(strategy=GenerationType.SEQUENCE) private Long id;public Long getId() {return id;}protected void setId(Long id) {this.id = id;}@Temporal(TemporalType.DATE) private Date launched;public Date getLaunched() {return launched;}public void setLaunched(Date launched) {this.launched = launched;}...@OneToMany(mappedBy="starship", cascade={CascadeType.ALL}) private List<Officer> officers = new ArrayList<Officer>();public List<Officer> getOfficers() {return Collections.unmodifiableList(officers);}protected void setOfficers(List<Officer> officers) {this.officers = officers;}public void addOfficer(Officer officer) {officer.setStarship(this);this.officers.add(officer);}public Starship() {super();}public Starship(String registry) {setRegistry(registry);}@Overridepublic int hashCode() {final int prime = 31;int result = 1;result = prime * result+ ((registry == null) ? 0 : registry.hashCode());return result;}@Overridepublic boolean equals(Object obj) {if (this == obj)return true;if (obj == null)return false;if (getClass() != obj.getClass())return false;Starship other = (Starship) obj;if (registry == null) {if (other.registry != null)return false;} else if (!registry.equals(other.registry))return false;return true;} }@Entity public class Officer {@Id @GeneratedValue(strategy=GenerationType.SEQUENCE) private Long id;public Long getId() {return id;}protected void setId(Long id) {this.id = id;}@Column(unique=true, nullable=false) private String name;public String getName() {return this.name;}public void setName(String name) {this.name = name;}@Enumerated private SpeciesEnum speciesEnum;public SpeciesEnum getSpeciesEnum() {return speciesEnum;}public void setSpeciesEnum(SpeciesEnum speciesEnum) {this.speciesEnum = speciesEnum;}...@ManyToOne private Starship starship; public Starship getStarship() {return starship;}protected void setStarship(Starship starship) {this.starship = starship;}public Officer() {super();}public Officer(String name, RankEnum rank) {setName(name);setRank(rank);}@Overridepublic int hashCode() {final int prime = 31;int result = 1;result = prime * result + ((name == null) ? 0 : name.hashCode());return result;}@Overridepublic boolean equals(Object obj) {if (this == obj)return true;if (obj == null)return false;if (getClass() != obj.getClass())return false;Officer other = (Officer) obj;if (name == null) {if (other.name != null)return false;} else if (!name.equals(other.name))return false;return true;} }

最后，我們將再次運行測試，看看會發生什么：

Hibernate: insert into Starship (affiliationEnum, launched, height, length, power, width, registry, starshipClassEnum, id) values (?, ?, ?, ?, ?, ?, ?, ?, ?) Hibernate: insert into Officer (affiliationEnum, homePlanet, name, rank, speciesEnum, starship_id, id) values (?, ?, ?, ?, ?, ?, ?) Hibernate: insert into Officer (affiliationEnum, homePlanet, name, rank, speciesEnum, starship_id, id) values (?, ?, ?, ?, ?, ?, ?) Hibernate: insert into Officer (affiliationEnum, homePlanet, name, rank, speciesEnum, starship_id, id) values (?, ?, ?, ?, ?, ?, ?) Hibernate: insert into Officer (affiliationEnum, homePlanet, name, rank, speciesEnum, starship_id, id) values (?, ?, ?, ?, ?, ?, ?) Hibernate: insert into Officer (affiliationEnum, homePlanet, name, rank, speciesEnum, starship_id, id) values (?, ?, ?, ?, ?, ?, ?) Hibernate: insert into Officer (affiliationEnum, homePlanet, name, rank, speciesEnum, starship_id, id) values (?, ?, ?, ?, ?, ?, ?) Hibernate: insert into Officer (affiliationEnum, homePlanet, name, rank, speciesEnum, starship_id, id) values (?, ?, ?, ?, ?, ?, ?)Before Find Hibernate: select starship0_.id as id1_0_, starship0_.affiliationEnum as affiliat2_1_0_, starship0_.launched as launched1_0_, starship0_.height as height1_0_, starship0_.length as length1_0_, starship0_.power as power1_0_, starship0_.width as width1_0_, starship0_.registry as registry1_0_, starship0_.starshipClassEnum as starship9_1_0_ from Starship starship0_ where starship0_.id=?After Find Before Commit After commit

為什么使用屬性映射Hibernate在提交期間運行查詢，而未執行使用字段映射？ 提交事務后，Hibernate執行刷新操作，以使基礎持久性存儲與內存中保持的可持久狀態同步。 當使用屬性映射時，Hibernate調用getter / setter方法來同步數據，對于getOfficers方法，它將返回一個臟集合（由于進行了unmodifiableList調用）。 另一方面，當我們使用字段映射時， Hibernate直接獲取字段，因此收集不被認為是骯臟的，不需要重新創建。

但是我們還沒有完成，我想您想知道為什么我們還沒有從getter中刪除Collections.unmodifiableList，而是返回Hibernate集合？ 是的，我同意您的意見，我們很快完成了工作，更改看起來像@ OneToMany（cascade = {CascadeType.ALL} ）public List <Officer> getOfficers（）{ 但返回原始集合最終會導致封裝問題，實際上我們的封裝已損壞！ 我們可以將任何我們喜歡的東西添加到可變列表中； 我們可以將不受控制的更改應用于對象的內部狀態。

使用unmodifiableList是避免破壞封裝的一種方法，但是我們當然可以對公共訪問和Hibernate訪問使用不同的訪問器，而不用調用Collections.unmodifiableList方法。

考慮到我們今天所看到的，我建議您使用始終字段注釋而不是屬性映射，我們將避免很多意外。

希望您發現這篇文章有用。

此示例的屏幕截圖：

下載代碼

參考： Hibernate性能提示： JCG合作伙伴的 臟回收效應 ? 在一個罐子統治他們所有博客的亞歷克斯·索托。

翻譯自: https://www.javacodegeeks.com/2012/03/hibernate-performance-tips-dirty.html

hibernate臟數據

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