一、場景復現

報錯日志

*************************** APPLICATION FAILED TO START ***************************Description:A component required a bean of type 'com.mk.service.TestService' that could not be found.Action:Consider defining a bean of type 'com.mk.service.TestService' in your configuration @Service public class TestService implements ITestService{@Asyncpublic Future<String> doActionAsync(){return new AsyncResult(doAction());}@Overridepublic String doAction() {return "done";} }public interface ITestService {String doAction(); }@Component public class Runner implements ApplicationContextAware {@EventListener(ApplicationReadyEvent.class)public void run(){TestService testService = applicationContext.getBean(TestService.class);testService.doActionAsync();}private ApplicationContext applicationContext;@Overridepublic void setApplicationContext(ApplicationContext applicationContext) throws BeansException {this.applicationContext =applicationContext;} }@EnableAsync @Configuration @SpringBootApplication public class ServiceApplication {public static void main(String[] args) {SpringApplication.run(ServiceApplication.class, args);}}

二、分析原因

（1）doActionAsync加上接口方法，執行一樣報錯

@Service public class TestService implements ITestService{@Override@Asyncpublic Future<String> doActionAsync(){return new AsyncResult(doAction());}@Overridepublic String doAction() {return "done";} }

（2）使用ITestService調用就不報錯

@Component public class Runner implements ApplicationContextAware {@EventListener(ApplicationReadyEvent.class)public void run(){ITestService testService = applicationContext.getBean(ITestService.class);testService.doActionAsync();}private ApplicationContext applicationContext;@Overridepublic void setApplicationContext(ApplicationContext applicationContext) throws BeansException {this.applicationContext =applicationContext;} }

（3）Springboot 代理類型

Springboot 默認代理類型為jdk proxy

bean有實現接口使用jdk proxy代理，沒有實現接口則使用cglib代理

?

三、解決方案

（1）將方法抽象到接口

（2）強制使用cglib代理

@EnableAsync(proxyTargetClass = true) @Configuration @SpringBootApplication public class ServiceApplication {public static void main(String[] args) {SpringApplication.run(ServiceApplication.class, args);}}

?

總結

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