這么寫直接彈框報python運行出錯，/尷尬，那這個怎么多線程調用getA/getB/getC/getD/getE呢？每次傳參還要循環個arg2list列表

class ThreadTest():

def __init__(self):

pass

def getA(self, args1, args2):

pass

def getB(self, args1, args2):

pass

def getC(self, args1, args2):

pass

def getD(self, args1, args2):

pass

def getE(self, args2):

pass

if __name__ == "__main__":

Test = ThreadTest()

args2list = ['table1','table2']

args1 = 2

thread_ = []

for args2 in args2list:

t1 = threading.Thread(target=Test.getA, args = (args1, args2))

t2 = threading.Thread(target=Test.getB, args = (args1, args2))

t3 = threading.Thread(target=Test.getE, args = (args2))

t4 = threading.Thread(target=Test.getC, args = (args1, args2))

t5 = threading.Thread(target=Test.getrace, args = (args1, args2))

thread_.append(t1)

thread_.append(t2)

thread_.append(t3)

thread_.append(t4)

thread_.append(t5)

print(thread_)

for t in thread_:

t.setDaemon(True)

t.start()

t.join()

總結

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