讓我們來分析下面這段代碼：

#include <iostream> #include <string> using namespace std;class Employee {private:static int sn;public:Employee() {cout << "Employee()" << endl;mysn = sn++;}Employee(const string &s) {cout << "Employee(const string &s)" << endl;name = s;mysn = sn++;}Employee (Employee &e) {cout << "Employee (Employee &e)" << endl;name = e.name;mysn = sn++;}Employee &operator=(Employee &rhs) {cout << "Employee &operator=(Employee &rhs)" << endl;name = rhs.name;return *this;}const string &get_name() {return name;}int get_mysn() {return mysn;}private:string name;int mysn; };int Employee::sn = 0;void f(Employee &s) {cout << s.get_name() << " " << s.get_mysn() << endl; }int main() {Employee a("趙"), b = a, c;c = b;Employee d = c;Employee e;e = c;f(a);f(b);f(c);f(d);f(e);return 0; }

測試結(jié)果:

Employee(“趙”):調(diào)用了Employee(const string &s)

Employee b = a 調(diào)用了Employee (Employee &e),可以看成Employee b(a),如果我們將Employee b = a改成：Employee b(a);也是調(diào)用Employee (Employee &e)

Employee c 調(diào)用了Employee()

c = b;調(diào)用了Employee &operator=(Employee &rhs)

Employee d = c;調(diào)用了Employee (Employee &e),可以看成Employee d( c )，如果我們將Employee d = c改成Employee d( c )，也是調(diào)用Employee (Employee &e)

Employee e;調(diào)用了Employee()

e = c;調(diào)用了Employee &operator=(Employee &rhs)

如有錯誤，請在評論區(qū)留言指正一下，謝謝 !!!

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