首先，將按條件查詢并排序的結果查詢出來。

1 mysql> select accepttime,user,job from tuser_job where user =8 order by accepttime desc; 2 +---------------------+------+-----+ 3 | accepttime | user | job | 4 +---------------------+------+-----+ 5 | 2015-07-27 15:32:45 | 8 | 1 | 6 | 2015-07-26 14:22:56 | 8 | 1 | 7 | 2015-07-26 10:24:39 | 8 | 2 | 8 | 2015-07-20 17:16:38 | 8 | 1 | 9 +---------------------+------+-----+ 10 4 rows in set

然后，從中分組選出最新一條記錄。

1 mysql> select accepttime,user,job from (select * from tuser_job where user =8 order by accepttime desc) as a group by job; 2 +---------------------+------+-----+ 3 | accepttime | user | job | 4 +---------------------+------+-----+ 5 | 2015-07-27 15:32:45 | 8 | 1 | 6 | 2015-07-26 10:24:39 | 8 | 2 | 7 +---------------------+------+-----+ 8 2 rows in set

?

轉載于:https://www.cnblogs.com/leov/p/4680370.html

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