運(yùn)行時(shí)報(bào)錯：

terminate called after throwing an instance of 'std::out_of_range'
what(): ?basic_string::substr：__pos

Aborted (core dumped)

內(nèi)存讀取越界。

解釋1：for example:
const std::string sTest( "test" );
sTest.substr( 0, 10 );
will raise the same exception, since you ask 10 characters, but only 5 ( sTest.length()) ) are available.

調(diào)試過，正常運(yùn)行，無報(bào)錯。

解釋2：

Chances are you did something like:

std::string s("foo");

s.substr(5,1); //the length of the string is 3, 5 is out of bounds

調(diào)試過，確實(shí)會報(bào)錯，out_of_range

?

解決方案：查找substr方法前后代碼，排除可能的越界條件。

轉(zhuǎn)載于:https://www.cnblogs.com/cthon/p/9349813.html

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