MYSQL学习:GROUP BY分组取最新的一条记录
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日常開發(fā)當(dāng)中,經(jīng)常會(huì)遇到查詢分組數(shù)據(jù)中最新的一條記錄,比如統(tǒng)計(jì)當(dāng)前系統(tǒng)每個(gè)人的最新登錄記錄、外賣系統(tǒng)統(tǒng)計(jì)所有買家最新的一次訂單記錄、圖書管理系統(tǒng)借閱者最新借閱書籍的記錄等等。今天給大家介紹一下如何實(shí)現(xiàn)以上場景的SQL寫法,希望對大家能有所幫助!
1、初始化數(shù)據(jù)表
-- 借閱者表 CREATE TABLE `userinfo` (`uid` int(11) NOT NULL AUTO_INCREMENT COMMENT '主鍵',`uname` varchar(20) NOT NULL COMMENT '姓名',`uage` int(11) NOT NULL COMMENT '年齡',PRIMARY KEY (`uid`) USING BTREE ) ENGINE=InnoDB AUTO_INCREMENT=8 DEFAULT CHARSET=utf8 ROW_FORMAT=COMPACT; INSERT INTO `userinfo` VALUES (1, '小明', 20); INSERT INTO `userinfo` VALUES (2, '小張', 30); INSERT INTO `userinfo` VALUES (3, '小李', 28); -- 書籍表 CREATE TABLE `bookinfo` (`id` int(11) NOT NULL AUTO_INCREMENT COMMENT '主鍵',`book_no` varchar(20) NOT NULL COMMENT '書籍編號(hào)',`book_name` varchar(20) NOT NULL COMMENT '書籍名稱',PRIMARY KEY (`id`) USING BTREE ) ENGINE=InnoDB AUTO_INCREMENT=14 DEFAULT CHARSET=utf8 ROW_FORMAT=COMPACT; INSERT INTO `bookinfo` VALUES (1, 'ISBN001', '計(jì)算機(jī)基礎(chǔ)'); INSERT INTO `bookinfo` VALUES (2, 'ISBN002', '計(jì)算機(jī)網(wǎng)絡(luò)'); INSERT INTO `bookinfo` VALUES (3, 'ISBN003', '高等數(shù)學(xué)'); INSERT INTO `bookinfo` VALUES (4, 'ISBN004', '明朝那些事'); INSERT INTO `bookinfo` VALUES (5, 'ISBN005', '物理'); INSERT INTO `bookinfo` VALUES (13, 'ISBN006', '讀者'); -- 借閱記錄表 CREATE TABLE `borrow_record` (`id` int(11) NOT NULL AUTO_INCREMENT COMMENT '主鍵',`user_id` int(11) NOT NULL COMMENT '用戶id',`book_id` int(11) NOT NULL COMMENT '書籍id',`borrowtime` datetime NOT NULL COMMENT '書籍id',PRIMARY KEY (`id`) USING BTREE ) ENGINE=InnoDB AUTO_INCREMENT=16 DEFAULT CHARSET=utf8 ROW_FORMAT=COMPACT; INSERT INTO `borrow_record` VALUES (8, 1, 2, '2021-05-01 10:52:00'); INSERT INTO `borrow_record` VALUES (9, 2, 4, '2021-07-12 23:32:00'); INSERT INTO `borrow_record` VALUES (10, 2, 1, '2021-03-21 09:00:00'); INSERT INTO `borrow_record` VALUES (11, 1, 3, '2021-08-11 17:39:00'); INSERT INTO `borrow_record` VALUES (12, 1, 5, '2021-09-02 18:12:00'); INSERT INTO `borrow_record` VALUES (13, 3, 1, '2021-07-06 12:32:00'); INSERT INTO `borrow_record` VALUES (14, 2, 1, '2021-08-09 10:10:00'); INSERT INTO `borrow_record` VALUES (15, 4, 3, '2021-04-15 19:45:00' );寫法1 直接group by 根據(jù)userid ,使用聚合函數(shù)max取得最近的瀏覽時(shí)間
select a.user_id ,max(c.uname) uname ,max(a.borrowtime) borrowtime,max(b.book_name) book_name from borrow_record a INNER JOIN bookinfo b on b.id=a.book_id INNER JOIN userinfo c on c.uid=a.user_id GROUP BY a.user_id --?說明:?這樣會(huì)存在獲取書籍名稱錯(cuò)亂的情況, -- 因?yàn)槭褂镁酆虾瘮?shù)獲取的書籍名稱,不一定是對應(yīng)用戶 -- 最新瀏覽記錄對應(yīng)的書籍名稱寫法2 采用子查詢的方式,獲取借閱記錄表最近的瀏覽時(shí)間作為查詢條件
select a.user_id ,c.uname,a.borrowtime ,b.book_name book_namefrom borrow_record a INNER JOIN bookinfo b on b.id=a.book_id INNER JOIN userinfo c on c.uid=a.user_id where a.borrowtime=(select max(borrowtime) from borrow_record t where t.user_id=a.user_id) -- 說明:可以滿足查詢效果,不過性能不是最優(yōu)解寫法3 采用group by + join 性能最高,推薦采用
select a.user_id ,c.uname,a.borrowtime ,b.book_name book_namefrom ( select t.user_id,max(borrowtime) borrowtime from borrow_record t GROUP BY t.user_id) as e INNER JOIN borrow_record a on e.user_id=a.user_id and e.borrowtime=a.borrowtimeINNER JOIN bookinfo b on b.id=a.book_id INNER JOIN userinfo c on c.uid=a.user_id運(yùn)行效果如下:
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