mysql按日期获取最新_mysql获取按日期排序获取最新的记录
主要按照日期獲得最新的數(shù)據(jù);
今天記錄兩種方式,并不涉及效率等其他方面問題:
第一種, 利用GROUP BY原理:
select * from (
select * from `authenticationrecord` order by `authenticationtime` desc
) `temp` group by merchantrid order by `authenticationtime` desc
第二種,利用mysql內(nèi)置函數(shù)
select * from `test` where id in(select SUBSTRING_INDEX(group_concat(id order by `date` desc),',',1) from `test` group by category_id ) order by `date` desc
<<<<<<<><>
試驗?zāi)_本(自己玩):
create table STAFF(
id int,
sname varchar(50),
dept varchar(50),
salary int,
edlevel int,
hiredate datetime
)
insert into STAFF values('1','張三','開發(fā)部','2000','3','2009-10-11');
insert into STAFF values('2','李四','開發(fā)部','2500','3','2009-10-01');
insert into STAFF values('3','王五','設(shè)計部','2600','5','2010-10-02');
insert into STAFF values('4','王六','設(shè)計部','2300','4','2010-10-03');
insert into STAFF values('5','馬七','設(shè)計部','2100','4','2010-10-06');
insert into STAFF values('6','趙八','銷售部','3000','5','2010-10-05');
insert into STAFF values('7','錢九','銷售部','3100','7','2010-10-07');
insert into STAFF values('8','孫十','銷售部','3500','7','2010-10-06');
select group_concat(id order by hiredate desc) as test from staff
group by dept;
select * from STAFF;
select * from STAFF
group by dept
參考網(wǎng)站:http://blog.csdn.net/agileclipse/article/details/12184635
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