特斯拉售后數據分析師

Q1:

Count male, female and total people of each city

CREATE TABLE test1 ([city] varchar(10), [gender] char(1)) INSERT INTO test1 ([city], [gender]) VALUES ('Delhi', 'M'),('Delhi', 'F'),('Delhi', 'M'),('Delhi', 'M'),('Pune', 'F'),('Pune', 'M'),('Pune', 'F'),('Pune', 'F'),('Banglore', 'F'),('Banglore', 'F') ; SELECTcity,COUNT(CASE gender WHEN 'M' THEN 1 ELSE 0 END) AS male_num,COUNT(CASE gender WHEN 'F' THEN 1 ELSE 0 END) AS female_num,COUNT(gender) AS people_num FROM test1 GROUP BY city

Q2:

You’re interviewing at a large social media company and are given two tables: registrations and logins. Each table consists of a user id and a date timestamp of the event. Each user has only one registration entry but could have multiple login entries (or none). The question is to write a query that will give the number of times each user login within their first week of registration (including none).

CREATE TABLE registration ([user_id] char(1), [registration_date] date) INSERT INTO registration ([user_id], [registration_date]) VALUES ('1','2020-01-15'),('2','2020-02-01'),('3','2020-03-10'),('4','2020-04-07'),('5','2020-05-25') ;CREATE TABLE logins ([user_id] char(1), [login_date] date) INSERT INTO logins ([user_id], [login_date]) VALUES ('1','2020-01-17'),('1','2020-01-19'),('1','2020-01-20'),('1','2020-01-25'),('2','2020-02-01'),('2','2020-02-05'),('2','2020-02-08'),('4','2020-04-08'),('4','2020-04-09'),('4','2020-04-10'),('4','2020-04-15'),('4','2020-04-20'),('5','2020-05-31'),('5','2020-06-05') ; SELECT registration.user_id, COUNT(login_date) AS login_num FROM registration LEFT JOIN logins ON registration.user_id = logins.user_id WHERE DATEDIFF(DAY,registration_date,login_date) <= 7 GROUP BY registration.user_id

Q3

Write a SQL query to prepare a table with salesman name, customer name and their city, for the salesman and customer who belongs to the same city.

CREATE TABLE salesman ([salesman_id] char(4), [name] varchar(20), [city] varchar(20), [commission] float(24)) INSERT INTO salesman ([salesman_id], [name], [city], [commission]) VALUES ('5001','James Hoog','New York',0.15), ('6785','Nail Knite','Paris',0.13),('2673','Pit Alex','London',0.11),('8736','Mc Lyon','Paris',0.14),('4783','Paul Adam','Rome',0.13),('9937','Lauson Hen','San Jose',0.12) ;CREATE TABLE customer ([customer_id] char(6), [name] varchar(20), [city] varchar(20), [grade] int, [salesman_id] char(4)) INSERT INTO customer ([customer_id], [name], [city], [grade],[salesman_id]) VALUES ('123456','Nick Rimando','New York',100,'5001'),('263574','Brad Davis','New York',200,'5001'),('736582','Graham Zusi','Los Angelas',200,'6785'),('208957','Julian Green','London',300,'6785'),('276893','Fabian Johnson','Paris',300,'8736'),('678396','Geoff Cameron','Berlin',100,'9937'),('290837','Jozy Altidor','Moscow',200,'4783') ; SELECT salesman.name AS salesmanname,customer.name AS customername,salesman.cityFROM salesmanJOIN customerON salesman.city = customer.city

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