int MyInt(56); std::cout<<"MyInt="<<MyInt<<std::endl;
int MySecondInt = int();????????//int變量可以這樣初始化 std::cout<<MySecondInt<<std::endl;
//那么可不可以這樣初始化呢?? int MyThirdInt(int());? ??//error!!! now, this is exactly a function ????????
所以?MyThirdInt?正確的寫法是
int MyThirdInt(int()) { ? ? ? ? // other code... ? return 0; }
既然MyThirdInt?是一個函數(shù), 那么里面的參數(shù)是什么東東呢?
//我們在聲明一個函數(shù) int OtherInt() { return 33; }
//再看三行代碼 int (*pfunc)(); pfunc = OtherInt; std::cout<<"MyThirdInt is: "<<MyThirdInt(pfunc)<<std::endl;
MyThirdInt?的參數(shù)是個函數(shù)指針,但是函數(shù)指針好像不能取出來....

所以這個特殊的Int變量需要重新定義,就像下面這樣:
int MyThirdInt(int (*pInt)()) { return pInt();
}
======================完整代碼========================
// hellomsg.cpp :? //
#include "stdafx.h" #include <iostream>

int OtherInt() { return 33; }
int MyThirdInt(int (*pInt)()) {
return pInt(); }
int _tmain(int argc, _TCHAR* argv[]) { int MyInt(56); std::cout<<"MyInt="<<MyInt<<std::endl;
int MySecondInt = int(); std::cout<<MySecondInt<<std::endl;
int (*pfunc)(); pfunc = OtherInt; std::cout<<"MyThirdInt is: "<<MyThirdInt(pfunc)<<std::endl;
return 0; }



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