poj1008(Maya Calendar)玛雅历(c++实现)
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poj1008(Maya Calendar)玛雅历(c++实现)
小編覺得挺不錯(cuò)的,現(xiàn)在分享給大家,幫大家做個(gè)參考.
這道題目不難,就是簡(jiǎn)單的模擬算法。但是還是給了我一個(gè)教訓(xùn),就是以后看題要仔細(xì)仔細(xì),
因?yàn)閯傞_始老是評(píng)測(cè)不能過,后來發(fā)現(xiàn)是少輸出了個(gè)日期數(shù),就是一開始把日期數(shù)輸入了,然后把他輸出一遍就可以了。
1、
2、改進(jìn):把一維字符串?dāng)?shù)組改為二維的字符數(shù)組,將cin、cout改為scanf、printf。
效率提高了不少。耗時(shí)0s,內(nèi)存為160k。不過與排名靠前的0s,8k,還是有很大距離。
如果大家有什么好方法,請(qǐng)指教,謝謝!
改進(jìn)后代碼:
#include<stdio.h> #include<iostream> using namespace std; #include<string> int main() {int k,n,i;int day,year;char month[19][7]={"pop","no","zip","zotz","tzec","xul","yoxkin","mol","chen","yax","zac","ceh","mac","kankin","muan","pax","koyab","cumhu","uayet"};char month1[20][9]={"imix","ik","akbal","kan","chicchan","cimi","manik","lamat","muluk","ok","chuen","eb","ben","ix","mem","cib","caban","eznab","canac","ahau"};char mon[7];scanf("%d",&k);printf("%d\n",k);while (k--){scanf("%d.%s%d",&day,mon,&year);for (i=0;i<19;i++)if (!strcmp(mon,month[i])) n=20*i;n=year*365+n+day+1;year=(n-1)/260;if (n%260==0) n=260;else n=n%260;if (n%13==0) day=13;else day=n%13;if (n%20==0) n=20;else n=n%20;printf("%d %s %d\n",day,month1[n-1],year);} return 0; }總結(jié)
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