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C语言strtok函数使用实例以及注意事项

發布時間:2023/12/29 编程问答 26 豆豆
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C語言strtok函數使用

  • 使用場景
  • 代碼實例
  • 注意事項
  • 參考

使用場景

字符串內容中被某個或者某些字符分割成若干部分,需要取出被分隔的若干個子字符串又不想去確定特殊字符的個數。
比如將下列字符串2164B851B4544AE79A03F2B644985DD1,2164B851B4544AE79A03F2B644985DD2,2164B851B4544AE79A03F2B644985DD3,2164B851B4544AE79A03F2B644985DD4,2164B851B4544AE79A03F2B644985DD5
分割成
2164B851B4544AE79A03F2B644985DD1
2164B851B4544AE79A03F2B644985DD2
2164B851B4544AE79A03F2B644985DD3
2164B851B4544AE79A03F2B644985DD4
2164B851B4544AE79A03F2B644985DD5
5個字串。

代碼實例

#include <string.h> #include <stdio.h>int main(int argc, char *arg[]) { char str[] = "2164B851B4544AE79A03F2B644985DD1,\ 2164B851B4544AE79A03F2B644985DD2,\ 2164B851B4544AE79A03F2B644985DD3,\ 2164B851B4544AE79A03F2B644985DD4,\ 2164B851B4544AE79A03F2B644985DD5";printf( "str is \"%s\"\n", str);char delims[] = ",";char *result = NULL;result = strtok(str, delims);while(result != NULL){printf( "result is \"%s\"\n", result);printf( "str is \"%s\"\n", str);result = strtok(NULL, delims);} }

運行結果如下:
str is “2164B851B4544AE79A03F2B644985DD1,2164B851B4544AE79A03F2B644985DD2,2164B851B4544AE79A03F2B644985DD3,2164B851B4544AE79A03F2B644985DD4,2164B851B4544AE79A03F2B644985DD5”
result is “2164B851B4544AE79A03F2B644985DD1”
str is “2164B851B4544AE79A03F2B644985DD1”
result is “2164B851B4544AE79A03F2B644985DD2”
str is “2164B851B4544AE79A03F2B644985DD1”
result is “2164B851B4544AE79A03F2B644985DD3”
str is “2164B851B4544AE79A03F2B644985DD1”
result is “2164B851B4544AE79A03F2B644985DD4”
str is “2164B851B4544AE79A03F2B644985DD1”
result is “2164B851B4544AE79A03F2B644985DD5”
str is “2164B851B4544AE79A03F2B644985DD1”

注意事項

1.源字符串str 在執行完一次strtok后發生變化。
2.while循環中再次調用strtok時,第一個參數填 NULL。
3.若源字符串str結尾再增加一個分隔符 “,”,運行結果不變(除第一個str的打印)。
4.strtok函數也可以按不止一個字符分割字符串,比如:

#include <string.h> #include <stdio.h>int main(int argc, char *arg[]) { char str[] = "2164B851B4544AE79A03F2B644985DD1,\ 2164B851B4544AE79A03F2B644985DD2;\ 2164B851B4544AE79A03F2B644985DD3,\ 2164B851B4544AE79A03F2B644985DD4;\ 2164B851B4544AE79A03F2B644985DD5*\ 2164B851B4544AE79A03F2B644985DD6,";printf( "str is \"%s\"\n", str);char delims[] = ",;*";char *result = NULL;result = strtok(str, delims);while(result != NULL){printf( "result is \"%s\"\n", result);printf( "str is \"%s\"\n", str);result = strtok(NULL, delims);} }

運行結果如下:
str is “2164B851B4544AE79A03F2B644985DD1,2164B851B4544AE79A03F2B644985DD2;2164B851B4544AE79A03F2B644985DD3,2164B851B4544AE79A03F2B644985DD4;2164B851B4544AE79A03F2B644985DD5*2164B851B4544AE79A03F2B644985DD6,”
result is “2164B851B4544AE79A03F2B644985DD1”
str is “2164B851B4544AE79A03F2B644985DD1”
result is “2164B851B4544AE79A03F2B644985DD2”
str is “2164B851B4544AE79A03F2B644985DD1”
result is “2164B851B4544AE79A03F2B644985DD3”
str is “2164B851B4544AE79A03F2B644985DD1”
result is “2164B851B4544AE79A03F2B644985DD4”
str is “2164B851B4544AE79A03F2B644985DD1”
result is “2164B851B4544AE79A03F2B644985DD5”
str is “2164B851B4544AE79A03F2B644985DD1”
result is “2164B851B4544AE79A03F2B644985DD6”
str is “2164B851B4544AE79A03F2B644985DD1”

參考

https://www.cnblogs.com/roucheng/p/cfenge.html

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