C語言之復數的加減乘除

• 1 源代碼
• 2 結果

1 源代碼

#include<stdio.h> #include<stdlib.h>// 定義一個結構體 typedef struct//結構體{double real;double img;}complex;complex a={1,2}; //第一個數的實部和虛部 1+2icomplex b={3,4};complex c; //計算結果/*****************************子函數聲明 *****************************/void add(complex ,complex ,complex *); //復數加法void mul(complex ,complex ,complex *); //復數乘法void sub(complex ,complex ,complex *); //復數減法void divi(complex ,complex ,complex *); //復數除法/*****************************主函數 *****************************/ int main() {add(a,b, &c);printf("和的實部為%f\n",c.real);printf("和的虛部為%f\n",c.img);printf("\n");mul(a,b, &c);printf("積的實部為%f\n",c.real);printf("積的虛部為%f\n",c.img);printf("\n");sub(a,b, &c);printf("差的實部為%f\n",c.real);printf("差的虛部為%f\n",c.img);printf("\n");divi(a,b, &c);printf("商的實部為%f\n",c.real);printf("商的虛部為%f\n",c.img);printf("\n");return 0;}/*****************************復數加法*****************************/void add(complex a,complex b,complex *c){c->real=a.real+b.real;c->img=a.img+b.img;}/*****************************復數乘法*****************************/void mul(complex a,complex b,complex *c){c->real=a.real*b.real - a.img*b.img;c->img=a.real*b.img + a.img*b.real;}/*****************************復數減法*****************************/void sub(complex a,complex b,complex *c){c->real=a.real-b.real;c->img=a.img-b.img;}/*****************************復數除法*****************************/void divi(complex a,complex b,complex *c){c->real=( a.real*b.real+a.img*b.img )/( b.real*b.real+b.img*b.img);c->img=( a.img*b.real-a.real*b.img)/(b.real*b.real+b.img*b.img);}

2 結果

總結

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