<span style="font-family: Arial, Helvetica, sans-serif; background-color: rgb(255, 255, 255);"></span><pre name="code" class="html">SELECT *, count(temp2.uid) as 復購人數 FROM( SELECT m.*, temp.merchantId, temp.uid FROM merchant m,( SELECT order1.merchantId, order1.uid FROM `order` order1 WHERE order1.uid IN( SELECT DISTINCT(o.uid) FROM `order` o WHERE DATE(o.createDate)>= DATE('2015-10-06 00:00:00') AND DATE(o.createDate)<= DATE('2015-10-13 23:59:59') AND o. STATUS>= 3 AND o. STATUS<= 6 AND o.merchantId= order1.merchantId) AND DATE(order1.createDate)>= date('2015-10-14 00:00:00') AND DATE(order1.createDate)<= DATE('2015-10-21 23:59:59') AND order1. STATUS>= 3 AND order1. STATUS<= 6) AS temp WHERE temp.merchantId= m.id GROUP BY temp.merchantId, temp.uid HAVING count(*)>= 6) AS temp2 GROUP BY temp2.id
?計算的是一段時間的在后面一個時間段重復購買的人數（不重復）

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