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左神算法:反转单向和双向链表(Java版)

發(fā)布時(shí)間:2024/2/28 java 41 豆豆
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本題來(lái)自左神《程序員面試代碼指南》“反轉(zhuǎn)單向和雙向鏈表”題目。

題目

分別實(shí)現(xiàn)反轉(zhuǎn)單向鏈表和反轉(zhuǎn)雙向鏈表的函數(shù)。

如果鏈表長(zhǎng)度為N,時(shí)間復(fù)雜度要求為O(N),額外空間復(fù)雜度要求為O(1)。

題解

本題比較簡(jiǎn)單,讀者做到代碼一次完成,運(yùn)行不出錯(cuò)即可。

  • 反轉(zhuǎn)單向鏈表的函數(shù)如下(該函數(shù)返回反轉(zhuǎn)之后鏈表新的頭節(jié)點(diǎn))
  • 反轉(zhuǎn)雙向鏈表的函數(shù)如下(函數(shù)返回反轉(zhuǎn)之后鏈表新的頭節(jié)點(diǎn))
package chapter_2_listproblem;public class Problem_04_ReverseList {public static class Node {public int value;public Node next;public Node(int data) {this.value = data;}}public static Node reverseList(Node head) {Node pre = null; // pre 始終指向頭插法得到的新鏈表的表頭Node next = null; // head 始終指向越來(lái)越短的原鏈表的表頭while (head != null) {next = head.next;head.next = pre;pre = head;head = next;}return pre;}public static class DoubleNode {public int value;public DoubleNode last;public DoubleNode next;public DoubleNode(int data) {this.value = data;}}public static DoubleNode reverseList(DoubleNode head) {DoubleNode pre = null;DoubleNode next = null;while (head != null) {next = head.next;head.next = pre;head.last = next;pre = head;head = next;}return pre;}public static void printLinkedList(Node head) {System.out.print("Linked List: ");while (head != null) {System.out.print(head.value + " ");head = head.next;}System.out.println();}public static void printDoubleLinkedList(DoubleNode head) {System.out.print("Double Linked List: ");DoubleNode end = null;while (head != null) {System.out.print(head.value + " ");end = head;head = head.next;}System.out.print("| ");while (end != null) {System.out.print(end.value + " ");end = end.last;}System.out.println();}// for testpublic static void main(String[] args) {Node head1 = new Node(1);head1.next = new Node(2);head1.next.next = new Node(3);printLinkedList(head1);head1 = reverseList(head1);printLinkedList(head1);DoubleNode head2 = new DoubleNode(1);head2.next = new DoubleNode(2);head2.next.last = head2;head2.next.next = new DoubleNode(3);head2.next.next.last = head2.next;head2.next.next.next = new DoubleNode(4);head2.next.next.next.last = head2.next.next;printDoubleLinkedList(head2);printDoubleLinkedList(reverseList(head2));}}

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