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I00014 汉若塔问题的C++程序

發布時間:2024/4/17 c/c++ 29 豆豆
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代碼來自維基教科書:C++ Programming As A Set Of Problems。

程序如下:

#include <iostream>void hanoi(int depth, int from, int to, int alternate){if(depth == 0){return;}hanoi(depth-1, from, alternate, to);std::cout << "Move ring " << depth << " from pole " << from << " to pole " << to << "." << std::endl;hanoi(depth-1, alternate, to, from);}int main(int argc, char** argv){hanoi(4, 1, 2, 3);return 0;}

程序運行結果如下:

Move ring 1 from pole 1 to pole 3. Move ring 2 from pole 1 to pole 2. Move ring 1 from pole 3 to pole 2. Move ring 3 from pole 1 to pole 3. Move ring 1 from pole 2 to pole 1. Move ring 2 from pole 2 to pole 3. Move ring 1 from pole 1 to pole 3. Move ring 4 from pole 1 to pole 2. Move ring 1 from pole 3 to pole 2. Move ring 2 from pole 3 to pole 1. Move ring 1 from pole 2 to pole 1. Move ring 3 from pole 3 to pole 2. Move ring 1 from pole 1 to pole 3. Move ring 2 from pole 1 to pole 2. Move ring 1 from pole 3 to pole 2.

轉載于:https://www.cnblogs.com/tigerisland/p/7564850.html

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