隨時(shí)隨地退出程序

　　新建一個(gè)結(jié)合類對(duì)所有活動(dòng)進(jìn)行管理。

1 public class ActivityCollector{ 2 public static List<Activity> activities = new ArrayList<>(); 3 public static void addActivity(Activity activity){ 4 activities.add(activity); 5 } 6 public static void removeActivity(Acitivity activity){ 7 activities.remove(acitivity); 8 } 9 public static void finishAll(){ 10 for(Activity activity: activities){ 11 if(!activity.isFinishing()){ 12 activity.finish(); 13 } 14 } 15 } 16 }

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啟動(dòng)活動(dòng)技巧

　　在SecondActivity中添加一個(gè)actionStrat（）

1 public class SecondActivity extends BaseActivity{ 2 public static void actionStart(Context context,String data1,String data2){ 3 Intent intent = new Intent(context,SecondActivity.class); 4 intent.putExtra("param1","data1"); 5 intent.putExtra("param2","data2"); 6 context.startActivity(intent); 7 } 8 ...... 9 }

　　啟動(dòng)SecondActivity

public void onClick(View v){SecondActivity.actionStart(FirstAcitivity.this,"data1","data2"); }

?　　殺死整個(gè)App

/** * 退出應(yīng)用程序 */ public void AppExit(Context context) { try { ActivityCollector.finishAll(); ActivityManager activityMgr = (ActivityManager) context .getSystemService(Context.ACTIVITY_SERVICE); activityMgr.killBackgroundProcesses(context.getPackageName()); System.exit(0); } catch (Exception ignored) {} }

　　雙擊退出程序兩個(gè)方法：

　　1）定義一個(gè)變量，來(lái)標(biāo)識(shí)是否退出

// 定義一個(gè)變量，來(lái)標(biāo)識(shí)是否退出 private static boolean isExit = false; Handler mHandler = new Handler() {@Overridepublic void handleMessage(Message msg) {super.handleMessage(msg);isExit = false;} };public boolean onKeyDown(int keyCode, KeyEvent event) {if (keyCode == KeyEvent.KEYCODE_BACK) {if (!isExit) {isExit = true;Toast.makeText(getApplicationContext(), "再按一次退出程序",Toast.LENGTH_SHORT).show();// 利用handler延遲發(fā)送更改狀態(tài)信息mHandler.sendEmptyMessageDelayed(0, 2000);} else {exit(this);}return false;} return super.onKeyDown(keyCode, event);}

　　2）保存點(diǎn)擊時(shí)間：

/保存點(diǎn)擊的時(shí)間 private long exitTime = 0; public boolean onKeyDown(int keyCode, KeyEvent event) {if (keyCode == KeyEvent.KEYCODE_BACK) {if ((System.currentTimeMillis() - exitTime) > 2000) {Toast.makeText(getApplicationContext(), "再按一次退出程序",Toast.LENGTH_SHORT).show();exitTime = System.currentTimeMillis();} else {exit();}return false;}return super.onKeyDown(keyCode, event); }

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轉(zhuǎn)載于:https://www.cnblogs.com/yl-saber/p/6381339.html

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