split函数
--拆分字符串
CREATE FUNCTION [dbo].[fn_split](@str NVARCHAR(MAX), @split NVARCHAR(10)) RETURNS @table TABLE ([item] NVARCHAR(max)) AS BEGIN IF LEN(@split) = 0 BEGIN SET @split = N',' END DECLARE @xml XML; SET @xml = CONVERT(XML, '<x><![CDATA[' + replace(CONVERT(VARCHAR(MAX), @str), @split, ']]></x><x><![CDATA[') + ']]></x>') INSERT INTO @table SELECT item FROM (SELECT c.value('text()[1]', 'nvarchar(4000)') [item] FROM @xml.nodes('/x') t(c)) t WHERE item IS NOT NULL RETURN END declare @rn int ,@rn_count int,@n int,@n_count int,@messages varchar(500),@itemid int set @messages = 'Gold:0,Money:0,Annex1:385291156,Annex2:385291157,Annex3:385291158,Annex4:385291159,Annex5:385291160,GiftToken:0,Medal:0' select left(item,charindex(':',item)-1) xm, substring(item,charindex(':',item)+1,len(item)) value from dbo.fn_split(@messages,',') where item like 'Annex[0-9]%'
--split函數
SELECT * FROM dbo.split('581::579::519::279::406::361::560',':')
ALTER Function [dbo].[Split](@Sql varchar(8000),@Splits varchar(10))
returns @temp Table (a varchar(100))
As
Begin
Declare @i Int
Set @Sql = RTrim(LTrim(@Sql))
Set @i = CharIndex(@Splits,@Sql)
While @i >= 1
Begin
Insert @temp Values(Left(@Sql,@i-1))
Set @Sql = SubString(@Sql,@i+1,Len(@Sql)-@i)
Set @i = CharIndex(@Splits,@Sql)
End
If @Sql <> ''
Insert @temp Values (@Sql)
Return
End
-- =============================================
-- Description: <拆分字符串函數>
-- =============================================
Create FUNCTION [dbo].[Split]
(
@SplitString nvarchar(2000), -- 如果要傳入NText類型,下面需要相應的修改,注釋行為NText下同
@Separator varchar(2) -- NVarChar(2) = N','
)
RETURNS @SplitStringsTable TABLE
(
[id] int identity(1,1),
[value] varchar(8000) -- NVarChar(4000)
)
AS
BEGIN
DECLARE @CurrentIndex int;
DECLARE @NextIndex int;
DECLARE @ReturnText varchar(8000);-- NVarChar(4000)
SELECT @CurrentIndex=1;
WHILE(@CurrentIndex<=datalength(@SplitString)) -- DATALENGTH(@SplitString)/2
BEGIN
SELECT @NextIndex=charindex(@Separator,@SplitString,@CurrentIndex);
IF(@NextIndex=0 OR @NextIndex IS NULL)
SELECT @NextIndex=datalength(@SplitString)+1;--DATALENGTH(@SplitString)/2
SELECT @ReturnText=substring(@SplitString,@CurrentIndex,@NextIndex-@CurrentIndex);
INSERT INTO @SplitStringsTable([value])
VALUES(@ReturnText);
SELECT @CurrentIndex=@NextIndex+1;
END
RETURN;
END
/*功能:獲取字符串中的字母*/
CREATE FUNCTION dbo.F_Get_STR (@S VARCHAR(100))
RETURNS VARCHAR(100)
AS
BEGIN
WHILE PATINDEX('%[^a-z]%',@S)>0
BEGIN
set @s=stuff(@s,patindex('%[^a-z]%',@s),1,'')
END
RETURN @S
END
GO
--測試
select dbo.F_Get_STR('測試ABC123ABC')
split實現獲取第1到第2個分隔符中間的內容
alter function dbo.test_split(@str varchar(8000),@split varchar(100),@begin_pos int ,@end_pos int) returns varchar(8000) as begin
/*
create time :2019-04-13
author:chaoqun.guo
*/ declare @count int,@str1 varchar(8000),@i int set @i=charindex(@split,@str) set @count=0 SET @STR1='' while @i>0 begin if @count>=@begin_pos and @count< @end_pos begin IF @STR1='' BEGIN SET @STR1=LEFT(@str,@i-1) END else begin SET @STR1=@str1+@split+ LEFT(@str,@i-1) end end set @str=substring(@str,@i+1,len(@str)-@i) set @i=charindex(@split,@str) set @count=@count+1 end IF @STR<>'' BEGIN if @count>=@begin_pos and @count< @end_pos begin IF @STR1='' BEGIN SET @STR1=@str END else begin SET @STR1=@str1+@split+@str end end END return @str1 end go select dbo.test_split('123,234,456,678',',',0,5)
SQL SERVER 2016的新函數STRING_SPLIT可以直接按指定分隔符拆分字符串;
--sql server 2016
SELECT * FROM STRING_SPLIT('abc,ab,c', ',')
SQL SERVER 2017的新函數STRING_AGG可以直接按指定分隔符合并字符串;
--sql server 2017 SELECT STRING_AGG(name, ',') from sys.objects
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