? ? ? ? ? ? ? ? ? ? ? ? ? ? 計算時間列所在年的周序號

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需求描述

需求：對EMP表里員工KING和SMITH的hiredate入職時間差，基于生成的日期算每天所在的周，相對于年.

解決方法:通過DATE_FORMAT函數來完成.

注: 數據庫數據集SQL腳本詳見如下鏈接地址

員工表結構和數據初始化SQL腳本

SQL代碼

-- Mysql： SELECT B.ename b_Ename,B.HIREDATE b_hiredate,A.ename a_Ename, A.HIREDATE a_hiredate ,DATE_ADD(A.hiredate,INTERVAL pos DAY) date_Seq ,DATE_FORMAT(DATE_ADD(A.hiredate,INTERVAL pos DAY),'%U') AS weekno_Year FROM emp A,emp B,(SELECT i-1 AS pos FROM tb_incr) seq WHERE A.ename = 'SMITH' AND B.ename = 'KING' AND seq.pos <=DATEDIFF(B.HIREDATE,A.HIREDATE)

注：mysql里也可以通過yearweek函數來實現

-- mysql SELECT YEARWEEK(now()) 'yearWeek', SUBSTRING(YEARWEEK(now()),1,4)'year', SUBSTRING(YEARWEEK(now()),5,2) 'weekOfyear'

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執行結果

-- SQL Server SELECT B.ename b_Ename,B.HIREDATE b_hiredate,A.ename a_Ename, A.HIREDATE a_hiredate ,DATEADD(DAY,seq.pos,A.HIREDATE) AS date_Seq ,DATEPART(WK,DATEADD(DAY,seq.pos,A.HIREDATE)) AS weekno_Year FROM emp A,emp B,(SELECT number AS pos FROM master.[dbo].[spt_values] WHERE type = 'P') seq WHERE A.ename = 'SMITH' AND B.ename = 'KING' AND seq.pos <= DATEDIFF(DAY,A.HIREDATE,B.HIREDATE)

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