http://haixiaoyang.wordpress.com/category/dynamic-programming/

這個比求最大矩陣要方便多了，記錄的是rec[i][j]矩陣邊上的點的數目

//There is a square of n x n size which is comprised of n-square 1x1 squares. //Some of these 1x1 squares are colored. Find the biggest //sub square which is colored. Also asked to extend it to find the biggest area rectangleconst int N = 5; int FindLargestArea(bool A[N][N]) {int rec[N][N];int nRet = 0;for (int i = 0; i < N; i++){rec[0][i] = A[0][i] ? 1 : 0;if (rec[0][i] > nRet)nRet = rec[0][i];}for (int i = 0; i < N; i++){rec[i][0] = A[i][0] ? 1 : 0;if (rec[i][0] > nRet)nRet = rec[i][0];}for (int i = 1; i < N; i++){for (int j = 1; j < N; j++){if (!A[i][j]){rec[i][j] = 0;continue;}rec[i][j] = 1 + min(min(rec[i][j-1], rec[i-1][j]), rec[i-1][j-1]);//this is the first logic I write/*if (rec[i][j-1] == 0 || rec[i-1][j] == 0)rec[i][j] = 1;else{int nTmp = min(rec[i][j-1], rec[i-1][j]);//well, I missed the brackets leading to errorsrec[i][j] = nTmp + (A[i-nTmp][j-nTmp] ? 1 : 0);}*/if (rec[i][j] > nRet)nRet = rec[i][j];}}return nRet; }

總結

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