https://ac.nowcoder.com/acm/contest/322/A

題解：求和啊，快速冪啊

/* *@Author: STZG *@Language: C++ */ #include <bits/stdc++.h> #include<iostream> #include<algorithm> #include<cstdlib> #include<cstring> #include<cstdio> #include<string> #include<vector> #include<bitset> #include<queue> #include<deque> #include<stack> #include<cmath> #include<list> #include<map> #include<set> //#define DEBUG #define RI register int using namespace std; typedef long long ll; //typedef __int128 lll; const int N=100000+10; const int MOD=10000019; const double PI = acos(-1.0); const double EXP = 1E-8; const int INF = 0x3f3f3f3f; int t,n,m,k,q,ans; ll a[N]; char str; int poww(int a, int b) {ll ans = 1, base = a;while (b != 0) {if (b & 1 != 0)ans = ans*base%MOD;base = base*base%MOD;b >>= 1;}return ans; } int main() { #ifdef DEBUGfreopen("input.in", "r", stdin);//freopen("output.out", "w", stdout); #endifscanf("%d",&n);ll ans=0;for(int i=1;i<=n;i++){scanf("%lld",&a[i]);a[i]%=MOD;ans=(ans+poww(a[i],i))%MOD;}cout << ans << endl;//cout << "Hello world!" << endl;return 0; }

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