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Java实现单链表的反转

發布時間:2024/10/5 java 33 豆豆
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思路1初始化一個新的頭節點reverseHead,然后遍歷舊鏈表,利用頭插法向reverseHead進行插入

思路2:
1.反轉相當于數據的更換(1和n,2和n-1,3和n-2)n為鏈表的長度
2.通過遍歷進行數據的更換,n/2為循環退出的條件

package com.company;import java.util.Stack;/*** @author:抱著魚睡覺的喵喵* @date:2021/2/4* @description:*/ public class LinkedListDemo {public static void main(String[] args) {Node node1 = new Node(1, 96, "Ronin");Node node2 = new Node(2, 100, "lisi");Node node3 = new Node(3, 99, "張三");Node node4 = new Node(4, 63, "zsh");Node node5 = new Node(5, 65, "zms");SingleLinkedList singleLinkedList = new SingleLinkedList();singleLinkedList.add(node1);singleLinkedList.add(node2);singleLinkedList.add(node2);singleLinkedList.add(node4);singleLinkedList.add(node5);System.out.println("鏈表反轉后的數據如下:");getReverse2(singleLinkedList.getNode());singleLinkedList.list();}/*** 鏈表的反轉 方法1* 思路:1.反轉相當于數據的更換(1和n,2和n-1,3和n-2)n為鏈表的長度* 2.通過遍歷進行數據的更換,n/2為循環退出的條件** @param head* @return*/public static void getReverse(Node head) {if (head.next == null) {System.out.println("LinkedList is empty!");return;}int length = getLength(head);int num1 = 0;int num2 = 0;Node mid = new Node();for (int i = 1, j = length; i <= length / 2; i++, j--) {Node temp = head;Node cur = head;while (true) {temp = temp.next;num1++;if (num1 == i) {num1 = 0;break;}}while (true) {cur = cur.next;num2++;if (j == num2) {num2 = 0;break;}}mid.sno = temp.sno;mid.score = temp.score;mid.data = temp.data;temp.sno = cur.sno;temp.score = cur.score;temp.data = cur.data;cur.sno = mid.sno;cur.score = mid.score;cur.data = mid.data;}Node temp2 = head.next;while (temp2 != null) {System.out.println(temp2);temp2 = temp2.next;}}/*** 鏈表的反轉2* 思路:* 初始化一個新的頭節點reverseHead,然后遍歷鏈表head,利用頭插法向reverseHead進行插入** @param head*/public static void getReverse2(Node head) {if (head.next == null) {System.out.println("LinkedList is empty!");return;}Node reverseHead = new Node(0, 0, "");Node cur = null;Node temp = head.next;while (temp != null) {cur = temp.next;temp.next = reverseHead.next;reverseHead.next = temp;temp = cur;}head.next = reverseHead.next;}//節點類 class Node {public Node next;public int sno;public int score;public String data;public Node() {}public Node(int Sno, int NScore, String Data) {this.sno = Sno;this.score = NScore;this.data = Data;}@Overridepublic String toString() {return "Node{" +"sno=" + sno +", score=" + score +", data='" + data + '\'' +'}';} }//鏈表操作類 class SingleLinkedList {private Node head = new Node(0, 0, ""); //初始化頭節點public Node getNode() {return head;}// add student datapublic void add(Node node) { //數據添加Node temp = head;while (temp.next != null) {temp = temp.next;}temp.next = node;}//outputpublic void list() { //遍歷數據進行打印Node temp = head.next;if (temp == null) {System.out.println("LinkedList is empty!");} else {while (temp != null) {System.out.println(temp);System.out.println();temp = temp.next;}}} }

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