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oracle单行子查询返回多个行 order by,单行子查询返回多个行 Issue分析求助

發(fā)布時(shí)間:2025/3/12 编程问答 25 豆豆
生活随笔 收集整理的這篇文章主要介紹了 oracle单行子查询返回多个行 order by,单行子查询返回多个行 Issue分析求助 小編覺(jué)得挺不錯(cuò)的,現(xiàn)在分享給大家,幫大家做個(gè)參考.

with order_base as --獲取訂單基礎(chǔ)情況

(

select ou.order_key order_key, ou.order_quantity_i, ood.dispatch_time_t, ou.part_number_s, 'I032ZZ01' pline_name_s

from order_uv ou left join at_as_om_orderdispatchstatus ood on ou.order_key = ood.order_54

union all

select mo.atr_key order_key, mo.order_quantity_i, mo.dispatch_time_t, mo.part_number_s, to_char(mo.pline_name_s) pline_name_s

from at_as_mm_order_plan mo

)

,

plan_quantity_base as --根據(jù)訂單派發(fā)時(shí)間確定訂單派發(fā)的班次

(

select to_char(ob.dispatch_time_t,'yyyymmdd') work_day, dispatch_time_t,

(

select su.description shift_name

from at_as_sm_calendar sc, shift_uv su

where su.shift_key = sc.shift_198

and category_s = 'MFG' and target_s = ob.pline_name_s and target_type_s = 'Production Line'

and ob.dispatch_time_t >= sc.start_time_t and ob.dispatch_time_t <= sc.end_time_t

and to_char(ob.dispatch_time_t,'yyyymmdd') = to_char(sc.start_time_t,'yyyymmdd')

) shift_name,

ob.pline_name_s, ob.order_quantity_i

from order_base ob

)

--select * from plan_quantity_base;

--Select To_Char(Pqb.Dispatch_Time_T,'yyyymmdd') Work_Day, Pqb.Shift_Name, Pqb.Pline_Name_S

--From Plan_Quantity_Base Pqb

--group By to_char(Pqb.dispatch_time_t,'yyyymmdd'), Pqb.Shift_Name, Pqb.Pline_Name_S;

--,

--plan_quantity as ( --根據(jù)訂單派發(fā)時(shí)間計(jì)算生產(chǎn)線(xiàn)的班次計(jì)劃產(chǎn)量

select to_char(Pqb.dispatch_time_t,'yyyymmdd') work_day, pqb.shift_name, pqb.pline_name_s, sum(pqb.order_quantity_i) plan_quantity

From Plan_Quantity_Base Pqb

--Where Pqb.Pline_Name_S Like Decode(roduction_Line,'ALL','%%',Null,'%%',roduction_Line)

--and pqb.shift_name like decode(:shift,'ALL','%%',:shift)

group By to_char(Pqb.dispatch_time_t,'yyyymmdd'), Pqb.Shift_Name, Pqb.Pline_Name_S

--)

問(wèn)題描述:

sql運(yùn)行到 plan_quantity 時(shí)報(bào)錯(cuò):單行子查詢(xún)返回多個(gè)行

1、單獨(dú)對(duì)每個(gè)語(yǔ)句塊寫(xiě)sql語(yǔ)句查詢(xún),排查下來(lái)發(fā)現(xiàn)問(wèn)題發(fā)生地方在 plan_quantity 上;

2、運(yùn)行語(yǔ)句(Select To_Char(Pqb.Dispatch_Time_T,'yyyymmdd') Work_Day, Pqb.Shift_Name, Pqb.Pline_Name_S

From Plan_Quantity_Base Pqb)和(select * from plan_quantity_base)都沒(méi)問(wèn)題;

3、運(yùn)行語(yǔ)句

(Select To_Char(Pqb.Dispatch_Time_T,'yyyymmdd') Work_Day, Pqb.Shift_Name, Pqb.Pline_Name_S

From Plan_Quantity_Base Pqb

group By to_char(Pqb.dispatch_time_t,'yyyymmdd'), Pqb.Shift_Name, Pqb.Pline_Name_S)

( select to_char(Pqb.dispatch_time_t,'yyyymmdd') work_day, pqb.shift_name, pqb.pline_name_s, sum(pqb.order_quantity_i) plan_quantity

From Plan_Quantity_Base Pqb

--Where Pqb.Pline_Name_S Like Decode(roduction_Line,'ALL','%%',Null,'%%',roduction_Line)

--and pqb.shift_name like decode(:shift,'ALL','%%',:shift)

group By to_char(Pqb.dispatch_time_t,'yyyymmdd'), Pqb.Shift_Name, Pqb.Pline_Name_S)

報(bào)錯(cuò):單行子查詢(xún)返回多個(gè)行;

問(wèn)題疑問(wèn):

1、在 plan_quantity 語(yǔ)句塊中,已經(jīng)group by 了,并且查詢(xún)的列中并沒(méi)有子查詢(xún),為什么會(huì)發(fā)生這種錯(cuò)誤?

請(qǐng)大家?guī)兔Ψ治鱿?#xff0c;實(shí)在沒(méi)有分析出來(lái)。

問(wèn)題描述2對(duì)應(yīng)結(jié)果圖片:

問(wèn)題描述3對(duì)應(yīng)結(jié)果圖片:

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