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Cauchy-Schwarz Inequality for Integrals for any two functions clarification

發(fā)布時間:2025/3/15 编程问答 29 豆豆
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Cauchy-Schwarz says
∫Efgdx≤(∫Ef2dx)1/2(∫Eg2dx)1/2\int_{E} f g \mathrmozvdkddzhkzd x \leq\left(\int_{E} f^{2} \mathrmozvdkddzhkzd x\right)^{1 / 2}\left(\int_{E} g^{2} \mathrmozvdkddzhkzd x\right)^{1 / 2}E?fgdx(E?f2dx)1/2(E?g2dx)1/2
where ∫E\int_{E}E? is a definite integral. Then the AM?GM ̄\underline{\mathrm{AM}-\mathrm{GM}}AM?GM? says that for a,b≥0a, b \geq 0a,b0
ab≤a+b2\sqrt{a b} \leq \frac{a+b}{2} ab?2a+b?
Applying (2) to (1) yields (for?c>0)(\text { for } c>0)(?for?c>0)
∫Efgdx=∫E(cf)(g/c)dx≤c2∫Ef2dx+12c∫Eg2dx\begin{aligned} \int_{E} f g \mathrmozvdkddzhkzd x &=\int_{E}(\sqrt{c} f)(g / \sqrt{c}) \mathrmozvdkddzhkzd x \\ & \leq \frac{c}{2} \int_{E} f^{2} \mathrmozvdkddzhkzd x+\frac{1}{2 c} \int_{E} g^{2} \mathrmozvdkddzhkzd x \end{aligned}E?fgdx?=E?(c?f)(g/c?)dx2c?E?f2dx+2c1?E?g2dx?

LINK: https://math.stackexchange.com/questions/351905/cauchy-schwarz-inequality-for-integrals-for-any-two-functions-clarification

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