老外的帖子

Sure - it's easy if you have exponential and natural log functions.

Since?y = x^n, you can take the natural log of both sides:

ln(y) = n*ln(x)

Then taking the exponential of both sides gives you what you want:

y = exp(n*ln(x))

If you want something better, the best place I know to look is?Abramowitz and Stegun.

總結(jié)

以上是生活随笔為你收集整理的Fast implementation/approximation of pow() function in C/C++的全部?jī)?nèi)容，希望文章能夠幫你解決所遇到的問(wèn)題。

如果覺(jué)得生活随笔網(wǎng)站內(nèi)容還不錯(cuò)，歡迎將生活随笔推薦給好友。