How can I make a "keep alive" HTTP request using Python's urllib2?

解決方案

Use the urlgrabber library. This includes an HTTP handler for urllib2 that supports HTTP 1.1 and keepalive:

>>> import urllib2

>>> from urlgrabber.keepalive import HTTPHandler

>>> keepalive_handler = HTTPHandler()

>>> opener = urllib2.build_opener(keepalive_handler)

>>> urllib2.install_opener(opener)

>>>

>>> fo = urllib2.urlopen('http://www.python.org')

Note: you should use urlgrabber version 3.9.0 or earlier, as the keepalive module has been removed in version 3.9.1

There is a port of the keepalive module to Python 3.

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