先上筆記內容吧：

這次上課的內容有關

構造函數

析構函數

運算符重載

return * this

　　內容很細，大家好好回顧筆記再照應程序復習吧　:)

#include <iostream>using namespace std;class Integer { public:int i;int geti () const {return this->i;}void seti (int i) {this->i = i;}Integer(int j = 0);Integer(Integer & c);~Integer(); };Integer::Integer (Integer & c) { //Constructer Functioni = 18;cout << "Integer (Integer & c)" << endl; }Integer::Integer (int j) : i(j) { //Copy Constructer Functioncout << "Integer (int j)" << endl; }Integer::~Integer () { //Destructer Functioncout << "~Integer () " << endl; }const Integer & fun (const Integer & in) {cout << in.geti () << endl;return in; }int main (){Integer b(8);fun(b).geti();Integer a(b);return 0; }

下面這個程序是有關運算符重載

通過　log print 可以跟蹤觀察到析構的順序

同時還有引用返回、友元函數的例子

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#include <iostream>using namespace std;class Integer { private:int i; public:int geti () const {return this->i;}void seti (int i) {this->i = i;}Integer(int j = 0);Integer(Integer & c);~Integer();const Integer & operator = (const Integer & in);friend const Integer operator + (const Integer & lhs, const Integer & rhs); };const Integer & Integer::operator = (const Integer & in) { //Member Functioni = in.i + 50;//return in;return *this; }const Integer operator + (const Integer & lhs, const Integer & rhs) { //全局函數Integer out;out.i = lhs.i + rhs.i;return out; }Integer::Integer (Integer & c) { //Constructer Functioni = 18;cout << "Integer (Integer & c)" << endl; }Integer::Integer (int j) : i(j) { //Copy Constructer Functioncout << "Integer (int j)" << ' ' << j << endl; }Integer::~Integer () { //Destructer Functioncout << "~Integer () " << ' ' << i << endl; }int main (){Integer b(8), a, c, d;cout << "a.geti()" << a.geti() << endl;d = c = a = b;cout << "a.geti()" << a.geti() << endl;cout << "c.geti()" << c.geti() << endl;cout << "d.geti()" << d.geti() << endl;d = a + b;cout << "d.geti()" << d.geti() << endl;return 0; }

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?接下來運算符重載作一些附加說明

• =
• &
• ,

這三個運算符可以直接使用

運算符重載的時候，如果既有 成員函數，又有全局函數， 優先(?)　　

eg.

++i (前加) Integer & operator ++ ()
i++ (后加) Integer & operator ++ (int)
括號中的 int 僅僅表示后加，無其他含義

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下面的這個例子可以幫助大家更好的理解

#include <iostream>using namespace std;class Integer { private:int i; public:int geti () const {return this->i;}void seti (int i) {this->i = i;}Integer(int j = 0);Integer(Integer & c);~Integer();Integer & operator ++ ();Integer operator ++ (int);const Integer & operator = (const Integer & in);friend const Integer operator + (const Integer & lhs, const Integer & rhs); };Integer & Integer::operator ++ () {++i;return *this; }Integer Integer::operator ++ (int) {Integer temp (this->i);++temp.i;return temp; }const Integer & Integer::operator = (const Integer & in) { //Member Functioni = in.i;//return in;return *this; }const Integer operator + (const Integer & lhs, const Integer & rhs) { //全局函數Integer out;out.i = lhs.i + rhs.i;return out; }Integer::Integer (Integer & c) { //Constructer Functioni = 18;cout << "Integer (Integer & c)" << endl; }Integer::Integer (int j) : i(j) { //Copy Constructer Functioncout << "Integer (int j)" << ' ' << j << endl; }Integer::~Integer () { //Destructer Functioncout << "~Integer () " << ' ' << i << endl; }int main (){Integer b(8), a;cout << b.geti () << "," << a.geti () << endl;a = ++b;cout << b.geti () << "," << a.geti () << endl;a = b++;cout << b.geti () << "," << a.geti () << endl;return 0; }

　　

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轉載于:https://www.cnblogs.com/wushuaiyi/p/4464093.html

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