為了進一步理解,我嘗試了以下代碼

in this link.

% Extract SURF features

I = imread('cameraman.tif');

points = detectSURFFeatures(I);

[features, valid_points] = extractFeatures(I, points);

% Visualize 10 strongest SURF features, including their

% scales and orientation which were determined during the

% descriptor extraction process.

imshow(I); hold on;

strongestPoints = valid_points.selectStrongest(10);

strongestPoints.plot('showOrientation',true);

然后,在Matlab控制臺中嘗試了命令strongestPoints.Location,它返回了以下(x,y)坐標.

139.7482 95.9542

107.4502 232.0347

116.6112 138.2446

105.5152 172.1816

113.6975 48.7220

104.4210 75.7348

111.3914 154.4597

106.2879 175.2709

131.1298 98.3900

124.2933 64.4942

由于有一個坐標(107.4502 232.0347),我試圖將行232標記為黑色(I(232,：)= 0;)以查看它是否與SURF點中的232.0347 y坐標匹配,并收到下圖.因此,似乎SURF點的舍入值給出圖像的(x,y)像素坐標.

總結(jié)

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